For each part, the compound with the higher boiling point is to be identified; and the reasons for the same are to be explained. Concept introduction: Unbranched alkanes havea higher boiling point than branched alkanes. As the branching increases in alkanes, the boiling point decreases. If the molecular weight is the same then aldehyde and ketone have higher boiling points than their corresponding hydrocarbons as result of polarity. An alcohol of the same molecular weight has a higher boiling point than its corresponding aldehyde and ketone due to hydrogen bonding in alcohols. Primary amines have higher boiling points than secondary amines and secondary amines have higher boiling points than tertiary amines.

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Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 2, Problem 25PP

Interpretation Introduction

Interpretation:

For each part, the compound with the higher boiling point is to be identified; and the reasons for the same are to be explained.

Concept introduction:

Unbranched alkanes havea higher boiling point than branched alkanes. As the branching increases in alkanes, the boiling point decreases.

If the molecular weight is the same then aldehyde and ketone have higher boiling points than their corresponding hydrocarbons as result of polarity.

An alcohol of the same molecular weight has a higher boiling point than its corresponding aldehyde and ketone due to hydrogen bonding in alcohols.

Primary amines have higher boiling points than secondary amines and secondary amines have higher boiling points than tertiary amines.

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PRACTICE PROBLEM 2.2 The compounds in each part below have the same (or similar) molecular weights. Which compound in cach part would you expect to have the higher boiling point? Explain your answers. (a) OH or (c) OH or HO (b) (CHN or A factor (in addition to polarity and hydrogen bonding) that affects the melting point of many organic compounds is the compactness and rigidity of their individual molecules. • Molecules that are symmetrical generally have abnormally high melting points. sert- Buryl alcohol, for example, has a much higher melting point than the other isomeric alcohols shown here: OH OH tert-Butyl alcohol (mp 25 "C) Butyl alcohol (mp -00 "C) Isobutyl alcohol sec-Butyl alcohol (mp 108 C) (mp-114 C) о о

For each pair of compounds, predict which one has the higher molecular dipole moment, and explain your reasoning.(a) ethyl chloride or ethyl iodide

Draw one possible structure for each of the following compounds based on the descriptions below. (i) A compound with molecular formula C6H11NO that includes alkene, secondary amine, and primary alcohol functional groups. (ii) A compound with molecular formula C6H9NO that has an amide functional group and does not have an alkene group.

Answer 2

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Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 2, Problem 25PP

Interpretation Introduction

Interpretation:

For each part, the compound with the higher boiling point is to be identified; and the reasons for the same are to be explained.

Concept introduction:

Unbranched alkanes havea higher boiling point than branched alkanes. As the branching increases in alkanes, the boiling point decreases.

If the molecular weight is the same then aldehyde and ketone have higher boiling points than their corresponding hydrocarbons as result of polarity.

An alcohol of the same molecular weight has a higher boiling point than its corresponding aldehyde and ketone due to hydrogen bonding in alcohols.

Primary amines have higher boiling points than secondary amines and secondary amines have higher boiling points than tertiary amines.

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Answer 3

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 2, Problem 25PP

Interpretation Introduction

Interpretation:

For each part, the compound with the higher boiling point is to be identified; and the reasons for the same are to be explained.

Concept introduction:

Unbranched alkanes havea higher boiling point than branched alkanes. As the branching increases in alkanes, the boiling point decreases.

If the molecular weight is the same then aldehyde and ketone have higher boiling points than their corresponding hydrocarbons as result of polarity.

An alcohol of the same molecular weight has a higher boiling point than its corresponding aldehyde and ketone due to hydrogen bonding in alcohols.

Primary amines have higher boiling points than secondary amines and secondary amines have higher boiling points than tertiary amines.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 2, Problem 25PP

Interpretation Introduction