Chapter 2, Problem 3CRP

Explanation of Solution

Calculate the memory cells of the Vole from address $0\times 98$ to $0\times \text{A2}$ in the block:

• The numbers of main memory cells are 256 in a computer. The addresses of every cell are $00$ to $\text{FF}$ in hexadecimal.
• To calculate the number of memory cells from address $98$ to $\text{A2}$, write the address $98$ and $\text{A2}$ from hexadecimal to decimal form.
• To change the hexadecimal $98$ into decimal, multiply the first digit that is 8 (from right side of the number) with 16 which is raised by power of 0 and then multiply the second digit from right that is 9 with 16 which has now power 1 and add them together.

  $\begin{array}{c}98=9\times \left({16}^1\right)+8\times \left({16}^0\right)\\ =144+8\\ =152\end{array}$

• Convert the hexadecimal $\text{A2}$ to decimal, multiply the first digit 2 from right side of the number by 16 which is raised by power of 0 and then multiply the second digit from right $\text{A}\left(10\right)$ and multiply it by 16 which has now power 1 and add them together.

  $\begin{array}{c}\text{A2}=10\times \left({16}^1\right)+2\times \left({16}^0\right)\\ =160+2\\ =162\end{array}$

• Thus, the range of address is $162$ to 152