Explanation Given information: The instantaneous velocity is v = v 0 + a t . The position as a function of time is x = x 0 + v 0 t + 1 2 a t 2 . Calculation: Show the position as a function of time as follows x = x 0 + v 0 t + 1 2 a t 2 Here, x is the position, x 0 is the initial position, v 0 is the initial velocity, a is the acceleration, and t is the time. Differentiate both sides of the Equation with respect to time t . d x d t = d d t ( x 0 + v 0 t + 1 2 a t 2 )

Essential University Physics: Volume 1 (3rd Edition)

3rd Edition

ISBN: 9780321993724

Author: Richard Wolfson

Publisher: PEARSON

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Chapter 2, Problem 29E

To determine

To prove: the equation v=v0+at by differentiating the equation x=x0+v0t+12at2 .

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Chapter 2, Problem 28E

Chapter 2, Problem 30E

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Chapter 2 Solutions

Essential University Physics: Volume 1 (3rd Edition)

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To prove: the equation v = v 0 + a t by differentiating the equation x = x 0 + v 0 t + 1 2 a t 2 .

Solution Summary: The author explains how the equation v=v_0+at can be proved by differentiating its equation.

To prove: the equation v=v0+at by differentiating the equation x=x0+v0t+12at2 .

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Chapter 2 Solutions