Chapter 2, Problem 2.93QP

(a)

Interpretation Introduction

To determine: The name of the given compound $\text{MnS}$.

Interpretation: The name of the given compound $\text{MnS}$ is to be stated.

Concept introduction: The naming of the compound is done on the basis of atoms attached to it and the charge present on each atom.

Answer to Problem 2.93QP

The name of the given compound $\text{MnS}$ is Manganese $\left(\text{II}\right)$ sulfide.

Explanation of Solution

The oxidation state of sulfur atom is $-2$.

The oxidation state of manganese is assumed to be $x$.

The oxidation state of the metal center present in $\text{MnS}$ is expressed as,

$\begin{array}{c}x+\left(-2\right)=0\\ x=+2\end{array}$

The oxidation state of manganese is $+2$.

The sulfur atom with $-2$ charge is termed as sulfide ion.

Therefore the name of $\text{MnS}$ is Manganese $\left(\text{II}\right)$ sulfide.

(b)

Interpretation Introduction

To determine: The name of the given compound ${\text{V}}_3{\text{N}}_2$.

Interpretation: The name of the given compound ${\text{V}}_3{\text{N}}_2$ is to be stated.

Concept introduction: The naming of the compound is done on the basis of atoms attached to it and the charge present on each atom.

Answer to Problem 2.93QP

The name of the given compound ${\text{V}}_3{\text{N}}_2$ is Vanadium $\left(\text{II}\right)$ nitride.

Explanation of Solution

The oxidation state of nitrogen atom is $-3$.

The oxidation state of vanadium is assumed to be $x$.

The oxidation state of the metal center present in ${\text{V}}_3{\text{N}}_2$ is expressed as,

$\begin{array}{c}3x+2\left(-3\right)=0\\ x=\frac{6}{3}\\ x=+2\end{array}$

The oxidation state of vanadium is $+2$.

The nitrogen atom with $-3$ charge is termed as nitride.

Therefore the name of ${\text{V}}_3{\text{N}}_2$ is Vanadium $\left(\text{II}\right)$ nitride.

(c)

Interpretation Introduction

To determine: The name of the given compound ${\text{Cr}}_2{\left({\text{SO}}_4\right)}_3$.

Interpretation: The name of the given compound ${\text{Cr}}_2{\left({\text{SO}}_4\right)}_3$ is to be stated.

Concept introduction: The naming of the compound is done on the basis of atoms attached to it and the charge present on each atom.

Answer to Problem 2.93QP

The name of the given compound ${\text{Cr}}_2{\left({\text{SO}}_4\right)}_3$ is Chromium $\left(\text{III}\right)$ sulfate.

Explanation of Solution

The oxidation state of sulfate ion is $-2$.

The oxidation state of chromium is assumed to be $x$.

The oxidation state of the metal center present in ${\text{Cr}}_2{\left({\text{SO}}_4\right)}_3$ is expressed as,

$\begin{array}{c}2x+3\left(-2\right)=0\\ x=\frac{6}{2}\\ x=+3\end{array}$

The oxidation state of chromium is $+3$.

The sulfide ion with $-2$ charge is termed as sulfate.

Therefore the name of ${\text{Cr}}_2{\left({\text{SO}}_4\right)}_3$ is chromium $\left(\text{III}\right)$ sulfate.

(d)

Interpretation Introduction

To determine: The name of the given compound $\text{Co}{\left({\text{NO}}_3\right)}_2$.

Interpretation: The name of the given compound $\text{Co}{\left({\text{NO}}_3\right)}_2$ is to be stated.

Concept introduction: The naming of the compound is done on the basis of atoms attached to it and the charge present on each atom.

Answer to Problem 2.93QP

The name of the given compound $\text{Co}{\left({\text{NO}}_3\right)}_2$ is Cobalt $\left(\text{II}\right)$ nitrate.

Explanation of Solution

The oxidation state of nitrate ion is $-1$.

The oxidation state of Cobalt is assumed to be $x$.

The oxidation state of the metal center present in $\text{Co}{\left({\text{NO}}_3\right)}_2$ is expressed as,

$\begin{array}{c}x+2\left(-1\right)=0\\ x=+2\end{array}$

The oxidation state of Cobalt is $+2$.

The nitrate ion with $-1$ charge is termed as nitrate.

Therefore the name of ${\text{Cr}}_2{\left({\text{SO}}_4\right)}_3$ is Cobalt $\left(\text{II}\right)$ nitrate.

(e)

Interpretation Introduction

To determine: The name of the given compound ${\text{Fe}}_2{\text{O}}_3$.

Interpretation: The name of the given compound ${\text{Fe}}_2{\text{O}}_3$ is to be stated.

Concept introduction: The naming of the compound is done on the basis of atoms attached to it and the charge present on each atom.

Answer to Problem 2.93QP

The name of the given compound ${\text{Fe}}_2{\text{O}}_3$ is Iron $\left(\text{III}\right)$ oxide.

Explanation of Solution

The oxidation state of oxygen atom is $-2$.

The oxidation state of Iron is assumed to be $x$.

The oxidation state of the metal center present in ${\text{Fe}}_2{\text{O}}_3$ is expressed as,

$\begin{array}{c}2x+3\left(-2\right)=0\\ x=\frac{6}{2}\\ x=+3\end{array}$

The oxidation state of Iron is $+3$.

The oxygen atom with $-2$ charge is termed as oxide.

Therefore the name of ${\text{Fe}}_2{\text{O}}_3$ is Iron $\left(\text{III}\right)$ oxide.

Conclusion

1. a. The name of the given compound $\text{MnS}$ is Manganese $\left(\text{II}\right)$ sulfide.
2. b. The name of the given compound ${\text{V}}_3{\text{N}}_2$ is Vanadium $\left(\text{II}\right)$ nitride.
3. c. The name of the given compound ${\text{Cr}}_2{\left({\text{SO}}_4\right)}_3$ is Chromium $\left(\text{III}\right)$ sulfate.
4. d. The name of the given compound $\text{Co}{\left({\text{NO}}_3\right)}_2$ is Cobalt $\left(\text{II}\right)$ nitrate.
5. e. The name of the given compound ${\text{Fe}}_2{\text{O}}_3$ is Iron $\left(\text{III}\right)$ oxide.