Bundle: Physical Chemistry, 2nd + Student Solutions Manual
2nd Edition
ISBN: 9781285257594
Author: David W. Ball
Publisher: Cengage Learning
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Chapter 2, Problem 2.89E
Interpretation Introduction
Interpretation:
ΔU for 1 mole of N2 gas going from 300 K to 1100 K at constant volume is to be calculated. Using the expression for Cv determined from exercise 2.88, and ΔU is to be evaluated.
Concept introduction:
Notably, the overall energy content of the system is defined as internal energy (ΔU). The internal energy values for an isolated system is zero. since, no heat can enter into the system. Mathematically, internal energy can be written as,
ΔU = q + w
In a given system, the enthalpy and internal energy are governed by state variables of the system. Intriguingly, the molar heat capacities of gaseous systems are determined at constant volume and can be expressed as
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An open vessel containing water stands in a laboratory measuring 5.0 m x 5.0 m x 3.0 m at 25 °C ; the vapor pressure (vp) of water at this temperature is 3.2 kPa. When the system has come to equilibrium, what mass of water will be found in the air if there is no ventilation? Repeat the calculation for open vessels containing benzene (vp = 13.1 kPa) and mercury (vp = 0.23 Pa)
Chapter 2 Solutions
Bundle: Physical Chemistry, 2nd + Student Solutions Manual
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