Chapter 2, Problem 2.87AQAP

Interpretation Introduction

Interpretation:

You have to find out how many centimetres $\left(c{m}^3\right)$ of olive oil have the same mass as$1.50L$ of gasoline.

Concept introduction:

${\rho }_1{V}_1={\rho }_2{V}_2\left(\text{mass}\right).$

$\begin{array}{c}\left(\text{mass=Volume}\times \text{density}\right)\\ V{}_1=\left(\frac{{\rho }_2{V}_{2.}}{{\rho }_{1.}}\right)\end{array}$

From the above equation, it becomes clear that: If ${\rho }_2{V}_1\&{\rho }_1$ are known, then $V_1$ can be calculated.

$1L=1000c{m}^3.$