Chapter 2, Problem 2.79SP

Interpretation Introduction

Interpretation:

The amount of ${\text{CO}}_2$ in grams which is formed in the reaction.

Concept introduction:

When a sample of ${\text{CaCO}}_{\text{3}}$ was heated results $\text{CaO}$ and ${\text{CO}}_2$ gas, $\text{CaO}$ is solid, so it remains in the solution and ${\text{CO}}_2$ is gas, so it escaped to the atmosphere. The chemical equation is ${\text{CaCO}}_{\text{3}}\left(\text{s}\right)\to \text{CaO}\left(\text{s}\right)+{\text{CO}}_{\text{2}}\left(\text{g}\right)$. From the chemical reaction , we can see that $\text{1 mole}$ of ${\text{CaCO}}_{\text{3}}$ is required to form $\text{1 mole}$ of ${\text{CO}}_2$.