CHEM:ATOM FOC 2E CL (TEXT)
CHEM:ATOM FOC 2E CL (TEXT)
2nd Edition
ISBN: 9780393284218
Author: Stacey Lowery Bretz, Natalie Foster, Thomas R. Gilbert, Rein V. Kirss
Publisher: WW Norton & Co
Question
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Chapter 2, Problem 2.61QA
Interpretation Introduction

To find:

The number of carbon atoms in one molecule of (a) CH4; (b) C3H8; (c) C6H6; and (d) C6H12O6.

Expert Solution & Answer
Check Mark

Answer to Problem 2.61QA

Solution:

(a) CH4:The number of carbon atoms is 1.

(b) C3H8: The number of carbon atoms is 3.

(c) C6H6: The number of carbon atoms is 6.

(d) C6H12O6: The number of carbon atoms is 6.

Explanation of Solution

Avogadro’s number is equal to 6.022*1023 atoms or molecules.

1 mole = 6.022*1023 molecules.

a) CH4Here we can use Avogadro’s number as a conversion factor to calculate number of atoms in 1 molecule of CH4.

1 molecule CH4 × 1 mole CH46.023×1023 molecule ×1 mole C1 mole CH4×6.023×1023 C atoms 1 mole C= 1 atom of carbon.

(b) C3H8  - Here we can use Avogadro’s number as a conversion factor to calculate number of atoms in 1 molecule of C3H8

1 molecule C3H8 × 1 mole C3H86.023×1023 molecule ×3 mole C1 mole C3H8×6.023×1023 C atoms 1 mole C= 3 atoms of carbon.

(c) C6H6 - Here we can use Avogadro’s number as a conversion factor to calculate number of atoms in 1 molecule of C6H6.

1 molecule C6H6 × 1 mole C6H66.023×1023 molecule ×6 mole C1 mole C6H6×6.023×1023 C atoms 1 mole C= 6 atoms of carbon

(d) C6H12O6 - Here we can use Avogadro’s number as a conversion factor to calculate number of atoms in 1 molecule of C6H12O6.

1 molecule C6H12O6 × 1 mole C6H12O66.023×1023 molecule ×6 mole C1 mole C6H12O6×6.023×1023 C atoms 1 mole C= 6 atoms of carbon

Conclusion:

The number of carbon atoms can be calculated by using Avogadro’s number.

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Chapter 2 Solutions

CHEM:ATOM FOC 2E CL (TEXT)

Ch. 2 - Prob. 2.11VPCh. 2 - Prob. 2.12VPCh. 2 - Prob. 2.13QACh. 2 - Prob. 2.14QACh. 2 - Prob. 2.15QACh. 2 - Prob. 2.16QACh. 2 - Prob. 2.17QACh. 2 - Prob. 2.18QACh. 2 - Prob. 2.19QACh. 2 - Prob. 2.20QACh. 2 - Prob. 2.21QACh. 2 - Prob. 2.22QACh. 2 - Prob. 2.23QACh. 2 - Prob. 2.24QACh. 2 - Prob. 2.25QACh. 2 - Prob. 2.26QACh. 2 - Prob. 2.27QACh. 2 - Prob. 2.28QACh. 2 - Prob. 2.29QACh. 2 - Prob. 2.30QACh. 2 - Prob. 2.31QACh. 2 - Prob. 2.32QACh. 2 - Prob. 2.33QACh. 2 - Prob. 2.34QACh. 2 - Prob. 2.35QACh. 2 - Prob. 2.36QACh. 2 - Prob. 2.37QACh. 2 - Prob. 2.38QACh. 2 - Prob. 2.39QACh. 2 - Prob. 2.40QACh. 2 - Prob. 2.41QACh. 2 - Prob. 2.42QACh. 2 - Prob. 2.43QACh. 2 - Prob. 2.44QACh. 2 - Prob. 2.45QACh. 2 - Prob. 2.46QACh. 2 - Prob. 2.47QACh. 2 - Prob. 2.48QACh. 2 - Prob. 2.49QACh. 2 - Prob. 2.50QACh. 2 - Prob. 2.51QACh. 2 - Prob. 2.52QACh. 2 - Prob. 2.53QACh. 2 - Prob. 2.54QACh. 2 - Prob. 2.55QACh. 2 - Prob. 2.56QACh. 2 - Prob. 2.57QACh. 2 - Prob. 2.58QACh. 2 - Prob. 2.59QACh. 2 - Prob. 2.60QACh. 2 - Prob. 2.61QACh. 2 - Prob. 2.62QACh. 2 - Prob. 2.63QACh. 2 - Prob. 2.64QACh. 2 - Prob. 2.65QACh. 2 - Prob. 2.66QACh. 2 - Prob. 2.67QACh. 2 - Prob. 2.68QACh. 2 - Prob. 2.69QACh. 2 - Prob. 2.70QACh. 2 - Prob. 2.71QACh. 2 - Prob. 2.72QACh. 2 - Prob. 2.73QACh. 2 - Prob. 2.74QACh. 2 - Prob. 2.75QACh. 2 - Prob. 2.76QACh. 2 - Prob. 2.77QACh. 2 - Prob. 2.78QACh. 2 - Prob. 2.79QACh. 2 - Prob. 2.80QACh. 2 - Prob. 2.81QACh. 2 - Prob. 2.82QACh. 2 - Prob. 2.83QACh. 2 - Prob. 2.84QACh. 2 - Prob. 2.85QACh. 2 - Prob. 2.86QACh. 2 - Prob. 2.87QACh. 2 - Prob. 2.88QACh. 2 - Prob. 2.89QACh. 2 - Prob. 2.90QACh. 2 - Prob. 2.91QACh. 2 - Prob. 2.92QACh. 2 - Prob. 2.93QACh. 2 - Prob. 2.94QACh. 2 - Prob. 2.95QACh. 2 - Prob. 2.96QACh. 2 - Prob. 2.97QACh. 2 - Prob. 2.98QACh. 2 - Prob. 2.99QACh. 2 - Prob. 2.100QACh. 2 - Prob. 2.101QACh. 2 - Prob. 2.102QACh. 2 - Prob. 2.103QACh. 2 - Prob. 2.104QACh. 2 - Prob. 2.105QACh. 2 - Prob. 2.106QACh. 2 - Prob. 2.107QACh. 2 - Prob. 2.108QACh. 2 - Prob. 2.109QACh. 2 - Prob. 2.110QACh. 2 - Prob. 2.111QACh. 2 - Prob. 2.112QACh. 2 - Prob. 2.113QACh. 2 - Prob. 2.114QACh. 2 - Prob. 2.115QACh. 2 - Prob. 2.116QA
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