Concept explainers
A three-phase line with an impedance of
Load 1: Absorbs a total of 150 kW and 120 kvar.
Load 2: Delta connected with an impedance of
Load 3: 120 kVA at 0.6 PF leading.
If the line-to-neutral voltage at the load end of the line is 2000 v (rms), determine the magnitude of the line-to-line voltage at the source end of the line.
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Chapter 2 Solutions
MindTap Engineering for Glover/Overbye/Sarma's Power System Analysis and Design, 6th Edition, [Instant Access], 1 term (6 months)
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- 5arrow_forwardVA-120 V4120 Z₁ volt In lc c ZA Three-phase source Feeder lines Balanced load In the above circuit diagram, we have source impedance Zg = 0.05+j0.15 ohm, Z₁ = 0.1+j0.2 ohm and per phase impedance in the balanced Delta connected load, Z₁ = 12+j9 ohm. RMS value of source voltage is 200 volt. Phase sequence is as shown in the diagram. RMS value of current Ic= ampere Phase angle of le= degree RMS value of line voltage VCA = B JAB Inc ICAarrow_forwardA Y-connected balanced three-phase source is connected to a three-phase balanced load through a four-wire three-phase cable. The generator has an impedance of 0.1+j0.3 Q/phase. Each phase of the cable has an impedance of 2+2j 2 The phase "B" load voltage is 102-140° kV. The impedance of each phase of the Y-connected load is 3-j5 Q/phase. For a negative sequence: 1- tto pointe) Calculate "terminal" phase voltage of phases "a" and "c" of generator. 2- E points] Calculate Vab and Vca across the load. 5 points Calculate three phase power supplied by the source. 4- 10 point] Calculate three phase power losses.arrow_forward
- Power System Analysis and Design (MindTap Course ...Electrical EngineeringISBN:9781305632134Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. SarmaPublisher:Cengage Learning