Fundamentals Of Engineering Thermodynamics, 9e
9th Edition
ISBN: 9781119391432
Author: MORAN
Publisher: WILEY
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 2, Problem 2.36P
To determine
Calculate the thickness of the brick wall and the rate of conduction of the wall surface.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
A composite plane wall consists of a 3-in.-thick layer of insulation (k = 0.029 Btu/h · ft · °R) and a 0.75-in.-thick layer of siding (k =
0.058 Btu/h · ft · °R). The inner temperature of the insulation is 67°F. The outer temperature of the siding is 0°F. Determine at steady
state (a) the temperature at the interface of the two layers, in °F, and (b) the rate of heat transfer through the wall in Btu/h-ft2 of
surface area.
A composite plane wall consists of a 5-in.-thick layer of insulation (ks = 0.029 Btu/h ft. "R) and a 0.75-in.-thick layer of siding (ks =
0.058 Btu/h-ft- ºR). The inner temperature of the insulation is 67°F. The outer temperature of the siding is 0°F. Determine at steady
state (a) the temperature at the interface of the two layers, in °F, and (b) the rate of heat transfer through the wall in Btu/h-ft² of
surface area.
In an electrically heated home, the temperature of the ground in contact with a concrete basement wall is 13.8 oC. The temperature at the inside surface of the wall is 18.4 oC. The wall is 0.13 m thick and has an area of 6.8 m2. Assume that one kilowatt hour of electrical energy costs $0.10. How many hours are required for one dollar's worth of energy to be conducted through the wall?
Chapter 2 Solutions
Fundamentals Of Engineering Thermodynamics, 9e
Ch. 2 - Prob. 2.1ECh. 2 - Prob. 2.2ECh. 2 - Prob. 2.3ECh. 2 - Prob. 2.4ECh. 2 - Prob. 2.5ECh. 2 - Prob. 2.6ECh. 2 - Prob. 2.7ECh. 2 - Prob. 2.8ECh. 2 - Prob. 2.9ECh. 2 - Prob. 2.10E
Ch. 2 - Prob. 2.11ECh. 2 - Prob. 2.12ECh. 2 - Prob. 2.13ECh. 2 - Prob. 2.14ECh. 2 - Prob. 2.15ECh. 2 - Prob. 2.16ECh. 2 - Prob. 2.17ECh. 2 - Prob. 2.1CUCh. 2 - Prob. 2.2CUCh. 2 - Prob. 2.3CUCh. 2 - Prob. 2.4CUCh. 2 - Prob. 2.5CUCh. 2 - Prob. 2.6CUCh. 2 - Prob. 2.7CUCh. 2 - Prob. 2.8CUCh. 2 - Prob. 2.9CUCh. 2 - Prob. 2.10CUCh. 2 - Prob. 2.11CUCh. 2 - Prob. 2.12CUCh. 2 - Prob. 2.13CUCh. 2 - Prob. 2.14CUCh. 2 - Prob. 2.15CUCh. 2 - Prob. 2.16CUCh. 2 - Prob. 2.17CUCh. 2 - Prob. 2.18CUCh. 2 - Prob. 2.19CUCh. 2 - Prob. 2.20CUCh. 2 - Prob. 2.21CUCh. 2 - Prob. 2.22CUCh. 2 - Prob. 2.23CUCh. 2 - Prob. 2.24CUCh. 2 - Prob. 2.25CUCh. 2 - Prob. 2.26CUCh. 2 - Prob. 2.27CUCh. 2 - Prob. 2.28CUCh. 2 - Prob. 2.29CUCh. 2 - Prob. 2.30CUCh. 2 - Prob. 2.31CUCh. 2 - Prob. 2.32CUCh. 2 - Prob. 2.33CUCh. 2 - Prob. 2.34CUCh. 2 - Prob. 2.35CUCh. 2 - Prob. 2.36CUCh. 2 - Prob. 2.37CUCh. 2 - Prob. 2.38CUCh. 2 - Prob. 2.39CUCh. 2 - Prob. 2.40CUCh. 2 - Prob. 2.41CUCh. 2 - Prob. 2.42CUCh. 2 - Prob. 2.43CUCh. 2 - Prob. 2.44CUCh. 2 - Prob. 2.45CUCh. 2 - Prob. 2.46CUCh. 2 - Prob. 2.47CUCh. 2 - Prob. 2.48CUCh. 2 - Prob. 2.49CUCh. 2 - Prob. 2.50CUCh. 2 - Prob. 2.51CUCh. 2 - Prob. 2.52CUCh. 2 - Prob. 2.53CUCh. 2 - Prob. 2.54CUCh. 2 - Prob. 2.1PCh. 2 - Prob. 2.2PCh. 2 - Prob. 2.3PCh. 2 - Prob. 2.4PCh. 2 - Prob. 2.5PCh. 2 - Prob. 2.6PCh. 2 - Prob. 2.7PCh. 2 - Prob. 2.8PCh. 2 - Prob. 2.9PCh. 2 - Prob. 2.10PCh. 2 - Prob. 2.11PCh. 2 - Prob. 2.12PCh. 2 - Prob. 2.13PCh. 2 - Prob. 2.14PCh. 2 - Prob. 2.15PCh. 2 - Prob. 2.16PCh. 2 - Prob. 2.17PCh. 2 - Prob. 2.18PCh. 2 - Prob. 2.19PCh. 2 - Prob. 2.20PCh. 2 - Prob. 2.21PCh. 2 - Prob. 2.22PCh. 2 - Prob. 2.23PCh. 2 - Prob. 2.24PCh. 2 - Prob. 2.25PCh. 2 - Prob. 2.26PCh. 2 - Prob. 2.27PCh. 2 - Prob. 2.28PCh. 2 - Prob. 2.29PCh. 2 - Prob. 2.30PCh. 2 - Prob. 2.31PCh. 2 - Prob. 2.32PCh. 2 - Prob. 2.33PCh. 2 - Prob. 2.34PCh. 2 - Prob. 2.35PCh. 2 - Prob. 2.36PCh. 2 - Prob. 2.37PCh. 2 - Prob. 2.38PCh. 2 - Prob. 2.39PCh. 2 - Prob. 2.40PCh. 2 - Prob. 2.41PCh. 2 - Prob. 2.42PCh. 2 - Prob. 2.43PCh. 2 - Prob. 2.44PCh. 2 - Prob. 2.45PCh. 2 - Prob. 2.46PCh. 2 - Prob. 2.47PCh. 2 - Prob. 2.48PCh. 2 - Prob. 2.49PCh. 2 - Prob. 2.50PCh. 2 - Prob. 2.51PCh. 2 - Prob. 2.52PCh. 2 - Prob. 2.53PCh. 2 - Prob. 2.54PCh. 2 - Prob. 2.55PCh. 2 - Prob. 2.56PCh. 2 - Prob. 2.57PCh. 2 - Prob. 2.58PCh. 2 - Prob. 2.59PCh. 2 - Prob. 2.60PCh. 2 - Prob. 2.62PCh. 2 - Prob. 2.63PCh. 2 - Prob. 2.64PCh. 2 - Prob. 2.65PCh. 2 - Prob. 2.66PCh. 2 - Prob. 2.67PCh. 2 - Prob. 2.68PCh. 2 - Prob. 2.69PCh. 2 - Prob. 2.70PCh. 2 - Prob. 2.71P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- A composite plane wall consists of a 3-in.-thick layer of insulation (k = 0.029 Btu/h · ft · °R) and a 0.75-in.-thick layer of siding (kg = 0.058 Btu/h · ft · °R). The inner temperature of the insulation is 67°F. The outer temperature of the siding is 8°F. Determine at steady state (a) the temperature at the interface of the two layers, in °F, and (b) the rate of heat transfer through the wall in Btu/h-ft? of surface area.arrow_forwardShow step-by-step solution and schematic diagram if possible. Thank you.arrow_forwardA thermal system having a cylindrical form contains a sequence of cylindrical layers is used to cool hot gases. The thermal properties of the system materials are as follows : k = 231 W/m.K, c = 1033 J/kg.K and the density = 2702 kg/m^3. The gases to be cooled has a temperature equals to 500 C. Determine the temperature of the system that corresponds to 10 % of the maximum possible heat transfer between the gas and the system. Consider that the system has a characteristic length equals to 0.03 m. The heat convective coefficient is equal to 50 W/m^2.K. The initial temperature of the system is equal to 20 C. Select one: О а. 370 К O b. 489 K С. 341 К d. 410 Karrow_forward
- A composite plane wall consists of a 4-in-thick layer of insulation (ks = 0.029 Btu/h-ft-°R) and a 0.75-in-thick layer of siding (ks = 0.058 Btu/h.ft.R). The inner temperature of the insulation is 67°F. The outer temperature of the siding is 8°F. Determine at steady state (a) the temperature at the interface of the two layers, in °F, and (b) the rate of heat transfer through the wall in Btu/h-ft² of surface area.arrow_forwardmake it short and simplearrow_forward3. A lumped system with a volume of 0.003 m³ and a surface area of 0.08 m² is made of a material with density of 3800 kg/m³, thermal conductivity of 300 W/m K, and specific heat of 200 J/kg K. If the system is exposed to a convection environment with h = 60 W/m2 K, what is the approximate time it will take for this system to reach equilibrium with the environment? Express your answer in minutes.arrow_forward
- A composite plane wall consists of a 3-in.-thick layer of insulation (ks = 0.029 Btu/h ft. °R) and a 0.75-in.-thick layer of siding (ks = 0.058 Btu/h ft. °R). The inner temperature of the insulation is 67°F. The outer temperature of the siding is 8°F. Determine at steady state (a) the temperature at the interface of the two layers, in °F, and (b) the rate of heat transfer through the wall in Btu/h-ft² of surface area. Part A Determine at steady state the temperature at the interface of the two layers, in °F. T₂ i °Farrow_forwardExample 10: Consider a long resistance wire of radius r1 = 0.2 cm and thermal conductivity kwire = 15 W/m·°C in which heat is generated uniformly as a result of resistance heating at a constant rate of g = 50 W/cm3. The wire is embedded in a 0.5-cm-thick layer of ceramic whose thermal conductivity is kceramic = 1.2 W/m·°C. If the outer surface temperature of the ceramic layer is measured to be Ts = 45°C, determine the temperatures at the center of the resistance wire and the interface of the wire and the ceramic layer under steady conditions.arrow_forwardThermodynamics: Can you show me how to solve for the answer that is written below? Please show it in step by step solution Thank you!arrow_forward
- The nodal diagram shown is of a section of a flat plate with thermal conductivity of 51 W/m K. The left side and top side are exposed to the same convection environment at 35°C and 46.3 W/m² K. The divisions used have Ax = Ay = 11 cm. At steady state, the temperature at 1 is T₁ = 51.1°C, at 3 is T3 = 85.0°C, at 5 is T5 = 114.3°C, at 7 is T7 = 121.4°C, and 8 is Tg = 130.4°C. What is the temperature at 4, T4? Express your answer in °C. Too h 8 3 7 Ax = Ay Too h S 8arrow_forward3. A well-mixed cement-lined storage tank contains water initially at 50°C. The water loses energy to its surroundings via conduction through the tank's concrete-lined walls. The tank sits in an unheated warehouse with an air temperature of 0°C. A diagram of the storage tank is shown below. The cement lining is 1.5-cm thick and has a thermal conductivity (htc) of 2.0 W/(m K). height = 1.5 m diameter = 2.0 m a. How long will it take (in minutes) for the water to cool to 40°C? b. Why might you be over- or underestimating the time it will take to cool the contents of the reactor?arrow_forward2 (a) The inner and outer surfaces of a 5m x 10m brick wall of thickness 30 cm and thermal conductivity 0.69 W/m·K are maintained at temperatures of 20°C and 5°C, respectively. (i) Determine the rate of heat transfer through the wall, in W. [Note: State all assumptions] (ii) Explain the effect of thermal conductivity in rate of heat transferarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Principles of Heat Transfer (Activate Learning wi...Mechanical EngineeringISBN:9781305387102Author:Kreith, Frank; Manglik, Raj M.Publisher:Cengage Learning
Principles of Heat Transfer (Activate Learning wi...
Mechanical Engineering
ISBN:9781305387102
Author:Kreith, Frank; Manglik, Raj M.
Publisher:Cengage Learning
Physics - Thermodynamics: (21 of 22) Change Of State: Process Summary; Author: Michel van Biezen;https://www.youtube.com/watch?v=AzmXVvxXN70;License: Standard Youtube License