Explanation The efficiency of a system is the ratio of the input given to the system to the output received from the system. Given to us: Energy input to the motor, W i = 2.0 kW , Work done by the motor shaft, W o = 1.8 kW Solution The efficiency of a system is the ratio of the input given to the system to the output received from the system

Fundamentals Of Engineering Thermodynamics, 9e

9th Edition

ISBN: 9781119391432

Author: MORAN

Publisher: WILEY

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Chapter 2, Problem 2.15E

To determine

The efficiency of the motor in Example 2.6.

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Chapter 2, Problem 2.14E

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Chapter 2 Solutions

Fundamentals Of Engineering Thermodynamics, 9e

Ch. 2 - Prob. 2.1E Ch. 2 - Prob. 2.2E Ch. 2 - Prob. 2.3E Ch. 2 - Prob. 2.4E Ch. 2 - Prob. 2.5E Ch. 2 - Prob. 2.6E Ch. 2 - Prob. 2.7E Ch. 2 - Prob. 2.8E Ch. 2 - Prob. 2.9E Ch. 2 - Prob. 2.10E

Ch. 2 - Prob. 2.11E Ch. 2 - Prob. 2.12E Ch. 2 - Prob. 2.13E Ch. 2 - Prob. 2.14E Ch. 2 - Prob. 2.15E Ch. 2 - Prob. 2.16E Ch. 2 - Prob. 2.17E Ch. 2 - Prob. 2.1CU Ch. 2 - Prob. 2.2CU Ch. 2 - Prob. 2.3CU Ch. 2 - Prob. 2.4CU Ch. 2 - Prob. 2.5CU Ch. 2 - Prob. 2.6CU Ch. 2 - Prob. 2.7CU Ch. 2 - Prob. 2.8CU Ch. 2 - Prob. 2.9CU Ch. 2 - Prob. 2.10CU Ch. 2 - Prob. 2.11CU Ch. 2 - Prob. 2.12CU Ch. 2 - Prob. 2.13CU Ch. 2 - Prob. 2.14CU Ch. 2 - Prob. 2.15CU Ch. 2 - Prob. 2.16CU Ch. 2 - Prob. 2.17CU Ch. 2 - Prob. 2.18CU Ch. 2 - Prob. 2.19CU Ch. 2 - Prob. 2.20CU Ch. 2 - Prob. 2.21CU Ch. 2 - Prob. 2.22CU Ch. 2 - Prob. 2.23CU Ch. 2 - Prob. 2.24CU Ch. 2 - Prob. 2.25CU Ch. 2 - Prob. 2.26CU Ch. 2 - Prob. 2.27CU Ch. 2 - Prob. 2.28CU Ch. 2 - Prob. 2.29CU Ch. 2 - Prob. 2.30CU Ch. 2 - Prob. 2.31CU Ch. 2 - Prob. 2.32CU Ch. 2 - Prob. 2.33CU Ch. 2 - Prob. 2.34CU Ch. 2 - Prob. 2.35CU Ch. 2 - Prob. 2.36CU Ch. 2 - Prob. 2.37CU Ch. 2 - Prob. 2.38CU Ch. 2 - Prob. 2.39CU Ch. 2 - Prob. 2.40CU Ch. 2 - Prob. 2.41CU Ch. 2 - Prob. 2.42CU Ch. 2 - Prob. 2.43CU Ch. 2 - Prob. 2.44CU Ch. 2 - Prob. 2.45CU Ch. 2 - Prob. 2.46CU Ch. 2 - Prob. 2.47CU Ch. 2 - Prob. 2.48CU Ch. 2 - Prob. 2.49CU Ch. 2 - Prob. 2.50CU Ch. 2 - Prob. 2.51CU Ch. 2 - Prob. 2.52CU Ch. 2 - Prob. 2.53CU Ch. 2 - Prob. 2.54CU Ch. 2 - Prob. 2.1P Ch. 2 - Prob. 2.2P Ch. 2 - Prob. 2.3P Ch. 2 - Prob. 2.4P Ch. 2 - Prob. 2.5P Ch. 2 - Prob. 2.6P Ch. 2 - Prob. 2.7P Ch. 2 - Prob. 2.8P Ch. 2 - Prob. 2.9P Ch. 2 - Prob. 2.10P Ch. 2 - Prob. 2.11P Ch. 2 - Prob. 2.12P Ch. 2 - Prob. 2.13P Ch. 2 - Prob. 2.14P Ch. 2 - Prob. 2.15P Ch. 2 - Prob. 2.16P Ch. 2 - Prob. 2.17P Ch. 2 - Prob. 2.18P Ch. 2 - Prob. 2.19P Ch. 2 - Prob. 2.20P Ch. 2 - Prob. 2.21P Ch. 2 - Prob. 2.22P Ch. 2 - Prob. 2.23P Ch. 2 - Prob. 2.24P Ch. 2 - Prob. 2.25P Ch. 2 - Prob. 2.26P Ch. 2 - Prob. 2.27P Ch. 2 - Prob. 2.28P Ch. 2 - Prob. 2.29P Ch. 2 - Prob. 2.30P Ch. 2 - Prob. 2.31P Ch. 2 - Prob. 2.32P Ch. 2 - Prob. 2.33P Ch. 2 - Prob. 2.34P Ch. 2 - Prob. 2.35P Ch. 2 - Prob. 2.36P Ch. 2 - Prob. 2.37P Ch. 2 - Prob. 2.38P Ch. 2 - Prob. 2.39P Ch. 2 - Prob. 2.40P Ch. 2 - Prob. 2.41P Ch. 2 - Prob. 2.42P Ch. 2 - Prob. 2.43P Ch. 2 - Prob. 2.44P Ch. 2 - Prob. 2.45P Ch. 2 - Prob. 2.46P Ch. 2 - Prob. 2.47P Ch. 2 - Prob. 2.48P Ch. 2 - Prob. 2.49P Ch. 2 - Prob. 2.50P Ch. 2 - Prob. 2.51P Ch. 2 - Prob. 2.52P Ch. 2 - Prob. 2.53P Ch. 2 - Prob. 2.54P Ch. 2 - Prob. 2.55P Ch. 2 - Prob. 2.56P Ch. 2 - Prob. 2.57P Ch. 2 - Prob. 2.58P Ch. 2 - Prob. 2.59P Ch. 2 - Prob. 2.60P Ch. 2 - Prob. 2.62P Ch. 2 - Prob. 2.63P Ch. 2 - Prob. 2.64P Ch. 2 - Prob. 2.65P Ch. 2 - Prob. 2.66P Ch. 2 - Prob. 2.67P Ch. 2 - Prob. 2.68P Ch. 2 - Prob. 2.69P Ch. 2 - Prob. 2.70P Ch. 2 - Prob. 2.71P

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The efficiency of the motor in Example 2.6.

Solution Summary: The author explains that the efficiency of the motor in Example 2.6 is 90%. The ratio of input to output is the ratio given to the system and can be written as let

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The efficiency of the motor in Example 2.6.

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Chapter 2 Solutions