Explanation The efficiency of a system is the ratio of the input given to the system to the output received from the system. Given to us: Energy input to the motor, W i = 2.0 kW , Work done by the motor shaft, W o = 1.8 kW Solution The efficiency of a system is the ratio of the input given to the system to the output received from the system

Fundamentals Of Engineering Thermodynamics, 9e

9th Edition

ISBN: 9781119391432

Author: MORAN

Publisher: WILEY

See similar textbooks

Concept explainers

Clutches, Brakes, Couplings, and Flywheels

The clutch is described as a machine element used to connect or disconnect two shafts together to transmit torque or power. The clutch works on the principles of friction. The clutch is commonly used in automobiles to transfer power from the driving shaf…

Videos

Question

Chapter 2, Problem 2.15E

To determine

The efficiency of the motor in Example 2.6.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 2, Problem 2.14E

Chapter 2, Problem 2.16E

Students have asked these similar questions

state is Derive an expression for the volume expansivity of a substance whose equation of RT P = v-b a v(v + b)TZ where a and b are empirical constants.

For a gas whose equation of state is P(v-b)=RT, the specified heat difference Cp-Cv is equal to which of the following (show all work): (a) R (b) R-b (c) R+b (d) 0 (e) R(1+v/b)

of state is Derive an expression for the specific heat difference of a substance whose equation RT P = v-b a v(v + b)TZ where a and b are empirical constants.

Chapter 2 Solutions

Fundamentals Of Engineering Thermodynamics, 9e

Ch. 2 - Prob. 2.1E Ch. 2 - Prob. 2.2E Ch. 2 - Prob. 2.3E Ch. 2 - Prob. 2.4E Ch. 2 - Prob. 2.5E Ch. 2 - Prob. 2.6E Ch. 2 - Prob. 2.7E Ch. 2 - Prob. 2.8E Ch. 2 - Prob. 2.9E Ch. 2 - Prob. 2.10E

Ch. 2 - Prob. 2.11E Ch. 2 - Prob. 2.12E Ch. 2 - Prob. 2.13E Ch. 2 - Prob. 2.14E Ch. 2 - Prob. 2.15E Ch. 2 - Prob. 2.16E Ch. 2 - Prob. 2.17E Ch. 2 - Prob. 2.1CU Ch. 2 - Prob. 2.2CU Ch. 2 - Prob. 2.3CU Ch. 2 - Prob. 2.4CU Ch. 2 - Prob. 2.5CU Ch. 2 - Prob. 2.6CU Ch. 2 - Prob. 2.7CU Ch. 2 - Prob. 2.8CU Ch. 2 - Prob. 2.9CU Ch. 2 - Prob. 2.10CU Ch. 2 - Prob. 2.11CU Ch. 2 - Prob. 2.12CU Ch. 2 - Prob. 2.13CU Ch. 2 - Prob. 2.14CU Ch. 2 - Prob. 2.15CU Ch. 2 - Prob. 2.16CU Ch. 2 - Prob. 2.17CU Ch. 2 - Prob. 2.18CU Ch. 2 - Prob. 2.19CU Ch. 2 - Prob. 2.20CU Ch. 2 - Prob. 2.21CU Ch. 2 - Prob. 2.22CU Ch. 2 - Prob. 2.23CU Ch. 2 - Prob. 2.24CU Ch. 2 - Prob. 2.25CU Ch. 2 - Prob. 2.26CU Ch. 2 - Prob. 2.27CU Ch. 2 - Prob. 2.28CU Ch. 2 - Prob. 2.29CU Ch. 2 - Prob. 2.30CU Ch. 2 - Prob. 2.31CU Ch. 2 - Prob. 2.32CU Ch. 2 - Prob. 2.33CU Ch. 2 - Prob. 2.34CU Ch. 2 - Prob. 2.35CU Ch. 2 - Prob. 2.36CU Ch. 2 - Prob. 2.37CU Ch. 2 - Prob. 2.38CU Ch. 2 - Prob. 2.39CU Ch. 2 - Prob. 2.40CU Ch. 2 - Prob. 2.41CU Ch. 2 - Prob. 2.42CU Ch. 2 - Prob. 2.43CU Ch. 2 - Prob. 2.44CU Ch. 2 - Prob. 2.45CU Ch. 2 - Prob. 2.46CU Ch. 2 - Prob. 2.47CU Ch. 2 - Prob. 2.48CU Ch. 2 - Prob. 2.49CU Ch. 2 - Prob. 2.50CU Ch. 2 - Prob. 2.51CU Ch. 2 - Prob. 2.52CU Ch. 2 - Prob. 2.53CU Ch. 2 - Prob. 2.54CU Ch. 2 - Prob. 2.1P Ch. 2 - Prob. 2.2P Ch. 2 - Prob. 2.3P Ch. 2 - Prob. 2.4P Ch. 2 - Prob. 2.5P Ch. 2 - Prob. 2.6P Ch. 2 - Prob. 2.7P Ch. 2 - Prob. 2.8P Ch. 2 - Prob. 2.9P Ch. 2 - Prob. 2.10P Ch. 2 - Prob. 2.11P Ch. 2 - Prob. 2.12P Ch. 2 - Prob. 2.13P Ch. 2 - Prob. 2.14P Ch. 2 - Prob. 2.15P Ch. 2 - Prob. 2.16P Ch. 2 - Prob. 2.17P Ch. 2 - Prob. 2.18P Ch. 2 - Prob. 2.19P Ch. 2 - Prob. 2.20P Ch. 2 - Prob. 2.21P Ch. 2 - Prob. 2.22P Ch. 2 - Prob. 2.23P Ch. 2 - Prob. 2.24P Ch. 2 - Prob. 2.25P Ch. 2 - Prob. 2.26P Ch. 2 - Prob. 2.27P Ch. 2 - Prob. 2.28P Ch. 2 - Prob. 2.29P Ch. 2 - Prob. 2.30P Ch. 2 - Prob. 2.31P Ch. 2 - Prob. 2.32P Ch. 2 - Prob. 2.33P Ch. 2 - Prob. 2.34P Ch. 2 - Prob. 2.35P Ch. 2 - Prob. 2.36P Ch. 2 - Prob. 2.37P Ch. 2 - Prob. 2.38P Ch. 2 - Prob. 2.39P Ch. 2 - Prob. 2.40P Ch. 2 - Prob. 2.41P Ch. 2 - Prob. 2.42P Ch. 2 - Prob. 2.43P Ch. 2 - Prob. 2.44P Ch. 2 - Prob. 2.45P Ch. 2 - Prob. 2.46P Ch. 2 - Prob. 2.47P Ch. 2 - Prob. 2.48P Ch. 2 - Prob. 2.49P Ch. 2 - Prob. 2.50P Ch. 2 - Prob. 2.51P Ch. 2 - Prob. 2.52P Ch. 2 - Prob. 2.53P Ch. 2 - Prob. 2.54P Ch. 2 - Prob. 2.55P Ch. 2 - Prob. 2.56P Ch. 2 - Prob. 2.57P Ch. 2 - Prob. 2.58P Ch. 2 - Prob. 2.59P Ch. 2 - Prob. 2.60P Ch. 2 - Prob. 2.62P Ch. 2 - Prob. 2.63P Ch. 2 - Prob. 2.64P Ch. 2 - Prob. 2.65P Ch. 2 - Prob. 2.66P Ch. 2 - Prob. 2.67P Ch. 2 - Prob. 2.68P Ch. 2 - Prob. 2.69P Ch. 2 - Prob. 2.70P Ch. 2 - Prob. 2.71P

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

The efficiency of the motor in Example 2.6.

Solution Summary: The author explains that the efficiency of the motor in Example 2.6 is 90%. The ratio of input to output is the ratio given to the system and can be written as let

Concept explainers

Videos

The efficiency of the motor in Example 2.6.

Want to see the full answer?

Chapter 2 Solutions