(a) Interpretation: The product of the reaction between ( CH 3 CH 2 ) 3 N: (Lewis base) and given Lewis acid is to be drawn. Concept introduction: A Lewis acid-base reaction takes place between an electron rich species and an electron deficient species. In such reactions, a Lewis base (electron rich species) donates electron pair to a Lewis acid (electron deficient species) and forms a new bond.
(a) Interpretation: The product of the reaction between ( CH 3 CH 2 ) 3 N: (Lewis base) and given Lewis acid is to be drawn. Concept introduction: A Lewis acid-base reaction takes place between an electron rich species and an electron deficient species. In such reactions, a Lewis base (electron rich species) donates electron pair to a Lewis acid (electron deficient species) and forms a new bond.
Solution Summary: The author explains that a Lewis acid-base reaction takes place between electron rich species and electron deficient species.
Interpretation: The product of the reaction between (CH3CH2)3N: (Lewis base) and given Lewis acid is to be drawn.
Concept introduction: A Lewis acid-base reaction takes place between an electron rich species and an electron deficient species. In such reactions, a Lewis base (electron rich species) donates electron pair to a Lewis acid (electron deficient species) and forms a new bond.
Interpretation Introduction
(b)
Interpretation: The product of reaction between (CH3CH2)3N: (Lewis base) and given Lewis acid is to be drawn.
Concept introduction: A Lewis acid-base reaction takes place between an electron rich species and an electron deficient species. In such reactions, a Lewis base (electron rich species) donates electron pair to a Lewis acid (electron deficient species) and forms a new bond.
Interpretation Introduction
(c)
Interpretation: The product of the reaction between (CH3CH2)3N: (Lewis base) and given Lewis acid is to be drawn.
Concept introduction: A Lewis acid-base reaction takes place between an electron rich species and an electron deficient species. In such reactions, a Lewis base (electron rich species) donates electron pair to a Lewis acid (electron deficient species) and forms a new bond.
Draw the product formed when the Lewis acid (CH;CH),C* reacts with each Lewis base: (a) H20; (b) CH3OH; (c) (CH3)20;
(d) NH3; (e) (CH3)2NH.
Using the data in Appendix C, determine which of the following bases is strong enough to deprotonate acetonitrile (CH3CN), so that equilibrium favors the products: (a) NaH; (b) Na2CO3; (c) NaOH; (d) NaNH2; (e) NaHCO3.
In each of the following reactions, two possible organic products can be formed. Draw both organic products in each case and then circle the
one formed in greatest quantity in each case.
HC
(a)
1) NaH,
2) acid
(b)
CH,CH,OH
(c)
CH,CH,OH
NH2
(d)
O
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