Chapter 2, Problem 1SAQ

Interpretation Introduction

Interpretation:To determine the mass of the given sample

Concept introduction: Density, mass and volume are related by the formula:

$\text{Density =}\frac{\text{mass}}{\text{volume}}$- (A)

Given: Density= $\text{0}\text{.921}\text{g/mL}$

Mass= $\text{1}\text{.75 L}$

Answer to Problem 1SAQ

Solution: $\text{1}{\text{.61×10}}^{\text{3}}\text{ g}$

Explanation of Solution

Using the given values and formulae (A)

Since, $\text{1 L=1000 mL}$

$\begin{array}{l}\text{0}\text{.921 }\frac{\text{g}}{\text{mL}}\text{=}\frac{\text{mass×1 L}}{\text{1}\text{.75 L×1000 mL}}\\ \text{mass = 0}\text{.921×1}\text{.75×1000 g }\\ \text{mass = 1}{\text{.61×10}}^{\text{3}}\text{ g}\end{array}$

Conclusion

The mass of the given sample was determined.