Chapter 2, Problem 80E

Interpretation Introduction

Interpretation:

“Increase in the height of mercury.” should be identified.

Concept introduction:

Volume of capillary is proportional to the radius and the height of the capillary as follows:

${\text{V = π r}}^{\text{2}}\text{h}$

Where, r is the radius of capillary

h is the height of capillary

Given:

Density of mercury at $0°\text{C}$:

$\text{d }=\text{ 13}.\text{596 g}/\text{ cc}$

Density of mercury at $\text{25 }°\text{C}$:

$\text{d }=\text{ 13}.\text{534 g}/\text{ cc}$

Mass of mercury = 3.380 g

Diameter =0.200 mm