![Organic Chemistry: A Guided Inquiry](https://www.bartleby.com/isbn_cover_images/9780618974122/9780618974122_largeCoverImage.gif)
Concept explainers
Interpretation : Whether each molecule or ion in figures 2.2 and 2.3 are legitimate Lewis structures or not should be confirmed.
Concept Introduction : A legitimate Lewis structure is an electron dot and line bond representation in which the total number of valence electrons is indicated. Number of valence electrons around hydrogen is two. Number of valence electrons around carbon, nitrogen, oxygen, fluorine atom is eight. This is called the octet rule.
![Check Mark](/static/check-mark.png)
Answer to Problem 1CTQ
All the given Lewis structures are legitimate.
Explanation of Solution
In
Total number of valence electrons =
Number of electrons consumed for bonds =
Number of remaining electrons =
The remaining four electrons are added to oxygen atom. Then it completes its octet. Therefore, given Lewis structure for water molecule is a legitimate structure.
In
Total number of valence electrons =
Number of electrons consumed for bonds =
Number of remaining electrons =
The remaining twelve electrons are added to two fluorine atom six for each. Then those complete their octet. Therefore, given Lewis structure for
In
Total number of valence electrons =
Number of electrons gained from negative charges =
Total Number of electrons =
Therefore, given Lewis structure for
In
Total number of valence electrons =
Number of electrons consumed for bonds =
Number of remaining electrons =
The remaining two electrons are added to nitrogen atom. Then it completed its octet. Therefore, given Lewis structure for
In
Total number of valence electrons =
Number of electrons consumed for bonds =
Number of remaining electrons =
The remaining six electrons are added to fluorine atom. Then it completed its octet. Therefore, given Lewis structure for
Thus, all the given Lewis structures are legitimate.
Want to see more full solutions like this?
Chapter 2 Solutions
Organic Chemistry: A Guided Inquiry
- Show work with explanation. Don't give Ai generated solutionarrow_forwardShow work. don't give Ai generated solutionarrow_forwardUse the average molarity of acetic acid (0.0867M) to calculate the concentration in % (m/v). Then calculate the % difference between the calculated concentrations of your unknown vinegar solution with the 5.00% (w/v%) vinegar solution (check the formula for % difference in the previous lab or online). Before calculating the difference with vinegar, remember that this %(m/v) is of the diluted solution. It has been diluted 10 times.arrow_forward
- #1. Retro-Electrochemical Reaction: A ring has been made, but the light is causing the molecule to un- cyclize. Undo the ring into all possible molecules. (2pts, no partial credit) hvarrow_forwardDon't used Ai solutionarrow_forwardI have a question about this problem involving mechanisms and drawing curved arrows for acids and bases. I know we need to identify the nucleophile and electrophile, but are there different types of reactions? For instance, what about Grignard reagents and other types that I might not be familiar with? Can you help me with this? I want to identify the names of the mechanisms for problems 1-14, such as Gilman reagents and others. Are they all the same? Also, could you rewrite it so I can better understand? The handwriting is pretty cluttered. Additionally, I need to label the nucleophile and electrophile, but my main concern is whether those reactions differ, like the "Brønsted-Lowry acid-base mechanism, Lewis acid-base mechanism, acid-catalyzed mechanisms, acid-catalyzed reactions, base-catalyzed reactions, nucleophilic substitution mechanisms (SN1 and SN2), elimination reactions (E1 and E2), organometallic mechanisms, and so forth."arrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning
![Text book image](https://www.bartleby.com/isbn_cover_images/9780618974122/9780618974122_smallCoverImage.gif)