EBK INTRODUCTION TO THE PRACTICE OF STA
8th Edition
ISBN: 9781319116828
Author: Moore
Publisher: VST
expand_more
expand_more
format_list_bulleted
Videos
Question
Chapter 2, Problem 178E
To determine
To find: A
Expert Solution & Answer
Answer to Problem 178E
Solution: For the pair of variables: (EdCollege, Female), the coefficient of determination value is
For the pair of variables: (EdCollege, Age 18-24), the coefficient of determination value is
For the pair of variables: (EdCollege, Age 25-34), the coefficient of determination value is
Explanation of Solution
Given: The data of 50 states with variables related to health conditions and risk behavior as well as demographic information is provided in the question.
| State | Age18_24 | Age25_34 | Female | EdCollege |
| Alabama | 13.0 | 17.1 | 52.3 | 19.7 |
| Alaska | 14.6 | 20.7 | 48.2 | 23.7 |
| Arizona | 12.5 | 19.2 | 50.4 | 23.7 |
| Arkansas | 12.6 | 17.7 | 51.7 | 17.4 |
| California | 13.4 | 19.3 | 50.4 | 27.0 |
| Colorado | 12.7 | 18.2 | 49.9 | 32.6 |
| Connecticut | 12.3 | 15.2 | 51.9 | 32.5 |
| Delaware | 12.1 | 16.8 | 52.3 | 25.3 |
| District of Columbia | 13.9 | 23.0 | 53.7 | 45.2 |
| Florida | 11.3 | 16.2 | 51.4 | 23.8 |
| Georgia | 13.4 | 18.8 | 51.4 | 24.6 |
| Guam | 16.9 | 19.6 | 49.0 | 26.0 |
| Hawaii | 11.9 | 18.8 | 50.0 | 26.7 |
| Idaho | 14.1 | 18.4 | 50.2 | 21.7 |
| Illinois | 13.2 | 18.0 | 51.3 | 27.8 |
| Indiana | 13.4 | 17.1 | 51.3 | 20.5 |
| Iowa | 13.6 | 16.0 | 51.1 | 22.6 |
| Kansas | 14.0 | 17.5 | 50.9 | 26.5 |
| Kentucky | 12.5 | 17.3 | 51.6 | 18.7 |
| Louisiana | 13.8 | 18.6 | 52.2 | 18.9 |
| Maine | 11.1 | 14.3 | 51.8 | 24.5 |
| Maryland | 12.3 | 17.3 | 52.3 | 32.8 |
| Massachusetts | 12.7 | 16.6 | 52.1 | 35.4 |
| Michigan | 13.1 | 15.7 | 51.4 | 22.8 |
| Minnesota | 12.8 | 17.4 | 50.7 | 28.8 |
| Mississippi | 14.4 | 17.9 | 52.3 | 17.5 |
| Missouri | 12.9 | 17.2 | 51.8 | 23.0 |
| Montana | 12.9 | 15.8 | 50.3 | 25.1 |
| Nebraska | 14.2 | 17.4 | 50.9 | 25.2 |
| Nevada | 11.7 | 19.5 | 49.4 | 19.9 |
| New Hampshire | 12.4 | 14.5 | 51.2 | 30.2 |
| New Jersey | 11.3 | 16.4 | 51.6 | 32.3 |
| New Mexico | 13.1 | 18.6 | 51.0 | 22.7 |
| New York | 12.5 | 17.4 | 52.1 | 29.9 |
| North Carolina | 12.9 | 17.2 | 51.7 | 23.8 |
| North Dakota | 16.8 | 16.8 | 50.0 | 23.6 |
| Ohio | 12.3 | 16.6 | 51.9 | 22.3 |
| Oklahoma | 13.8 | 18.2 | 51.2 | 20.4 |
| Oregon | 12.2 | 16.3 | 50.8 | 26.1 |
| Pennsylvania | 12.3 | 15.6 | 52.0 | 24.5 |
| Puerto Rico | 14.6 | 19.2 | 53.1 | 19.4 |
| Rhode Island | 13.2 | 15.9 | 52.2 | 27.5 |
| South Carolina | 12.8 | 17.1 | 52.1 | 21.8 |
| South Dakota | 13.9 | 17.0 | 50.4 | 22.9 |
| Tennessee | 12.1 | 17.3 | 51.9 | 20.9 |
| Texas | 13.9 | 19.7 | 50.6 | 23.1 |
| Utah | 17.2 | 22.8 | 50.1 | 25.4 |
| Vermont | 13.2 | 14.2 | 51.3 | 30.2 |
| Virginia | 12.9 | 17.2 | 51.3 | 30.9 |
Calculation: From the given data set consider the following three pair of variables.
1. EdCollege and Female
2. EdCollege and Age 18-24
3. EdCollege and Age 25-34
Now, construct the scatterplot with fitted linear regression line for each pair of variables.
Use Minitab to get the required result.
To draw the scatterplot of the provided data, below mentioned steps are followed in Minitab.
Step 1: Enter the data into Minitab worksheet.
Step 2: Go to Graph, select scatterplot and linear regression and click OK.
Step 3: Select the data variable column and click on Scale.
Step 4: Check minor ticks under Y Scale Low and X Scale Low and then click OK.
The obtained scatterplot of EdCollege and Female is shown below:
From the above plot we observe that there is a low positive relation between the two variables female and EdCollege.
The regression fit for the data is
The obtained scatterplot of EdCollege and Age 18-24 is shown below.
From the above plot we observe that there is a low negative relation between the two variables Age 18-24 and EdCollege. The regression fit for the data is
The obtained scatterplot of EdCollege and Age 25-34 is shown below.
From the above plot we observe that there is a low positive relation between the two variables Age 25-34 and EdCollege.
The regression fit for the data is
Interpretation: Consider the first pair of variables, EdCollege and Female. The coefficient of determination value is
Consider second pair of variables, EdCollege and Age 18-24. The coefficient of determination value is
Consider third pair of variables, EdCollege and Age 25-34. The coefficient of determination value is
Want to see more full solutions like this?
Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
solving problem 1
select bmw stock. you can assume the price of the stock
This problem is based on the fundamental option pricing formula for the continuous-time
model developed in class, namely the value at time 0 of an option with maturity T and
payoff F is given by:
We consider the two options below:
Fo=
-rT
= e
Eq[F].
1
A. An option with which you must buy a share of stock at expiration T = 1 for strike
price K = So.
B. An option with which you must buy a share of stock at expiration T = 1 for strike
price K given by
T
K =
T
St dt.
(Note that both options can have negative payoffs.) We use the continuous-time Black-
Scholes model to price these options. Assume that the interest rate on the money market
is r.
(a) Using the fundamental option pricing formula, find the price of option A. (Hint:
use the martingale properties developed in the lectures for the stock price process
in order to calculate the expectations.)
(b) Using the fundamental option pricing formula, find the price of option B.
(c) Assuming the interest rate is very small (r ~0), use Taylor…
Chapter 2 Solutions
EBK INTRODUCTION TO THE PRACTICE OF STA
Ch. 2.1 - Prob. 1UYKCh. 2.1 - Prob. 2UYKCh. 2.1 - Prob. 3UYKCh. 2.1 - Prob. 4UYKCh. 2.1 - Prob. 5ECh. 2.1 - Prob. 6ECh. 2.1 - Prob. 7ECh. 2.1 - Prob. 8ECh. 2.1 - Prob. 9ECh. 2.2 - Prob. 10UYK
Ch. 2.2 - Prob. 11UYKCh. 2.2 - Prob. 12UYKCh. 2.2 - Prob. 13UYKCh. 2.2 - Prob. 14UYKCh. 2.2 - Prob. 15UYKCh. 2.2 - Prob. 16UYKCh. 2.2 - Prob. 17UYKCh. 2.2 - Prob. 18ECh. 2.2 - Prob. 19ECh. 2.2 - Prob. 20ECh. 2.2 - Prob. 21ECh. 2.2 - Prob. 22ECh. 2.2 - Prob. 23ECh. 2.2 - Prob. 24ECh. 2.2 - Prob. 25ECh. 2.2 - Prob. 26ECh. 2.2 - Prob. 27ECh. 2.2 - Prob. 28ECh. 2.2 - Prob. 29ECh. 2.2 - Prob. 30ECh. 2.2 - Prob. 31ECh. 2.2 - Prob. 32ECh. 2.2 - Prob. 33ECh. 2.2 - Prob. 34ECh. 2.2 - Prob. 35ECh. 2.2 - Prob. 36ECh. 2.2 - Prob. 37ECh. 2.3 - Prob. 38UYKCh. 2.3 - Prob. 39UYKCh. 2.3 - Prob. 40ECh. 2.3 - Prob. 41ECh. 2.3 - Prob. 42ECh. 2.3 - Prob. 43ECh. 2.3 - Prob. 44ECh. 2.3 - Prob. 45ECh. 2.3 - Prob. 46ECh. 2.3 - Prob. 47ECh. 2.3 - Prob. 48ECh. 2.3 - Prob. 49ECh. 2.3 - Prob. 50ECh. 2.3 - Prob. 51ECh. 2.3 - Prob. 52ECh. 2.3 - Prob. 53ECh. 2.3 - Prob. 54ECh. 2.3 - Prob. 55ECh. 2.3 - Prob. 56ECh. 2.3 - Prob. 57ECh. 2.3 - Prob. 58ECh. 2.3 - Prob. 59ECh. 2.3 - Prob. 60ECh. 2.3 - Prob. 61ECh. 2.4 - Prob. 62UYKCh. 2.4 - Prob. 63UYKCh. 2.4 - Prob. 64UYKCh. 2.4 - Prob. 65UYKCh. 2.4 - Prob. 66ECh. 2.4 - Prob. 67ECh. 2.4 - Prob. 68ECh. 2.4 - Prob. 69ECh. 2.4 - Prob. 70ECh. 2.4 - Prob. 71ECh. 2.4 - Prob. 72ECh. 2.4 - Prob. 73ECh. 2.4 - Prob. 74ECh. 2.4 - Prob. 75ECh. 2.4 - Prob. 76ECh. 2.4 - Prob. 77ECh. 2.4 - Prob. 78ECh. 2.4 - Prob. 79ECh. 2.4 - Prob. 80ECh. 2.4 - Prob. 81ECh. 2.4 - Prob. 82ECh. 2.4 - Prob. 83ECh. 2.4 - Prob. 84ECh. 2.4 - Prob. 85ECh. 2.4 - Prob. 86ECh. 2.4 - Prob. 87ECh. 2.4 - Prob. 88ECh. 2.4 - Prob. 89ECh. 2.4 - Prob. 90ECh. 2.4 - Prob. 91ECh. 2.5 - Prob. 92UYKCh. 2.5 - Prob. 93UYKCh. 2.5 - Prob. 94ECh. 2.5 - Prob. 95ECh. 2.5 - Prob. 96ECh. 2.5 - Prob. 97ECh. 2.5 - Prob. 98ECh. 2.5 - Prob. 99ECh. 2.5 - Prob. 100ECh. 2.5 - Prob. 101ECh. 2.5 - Prob. 102ECh. 2.5 - Prob. 103ECh. 2.5 - Prob. 104ECh. 2.5 - Prob. 105ECh. 2.5 - Prob. 106ECh. 2.5 - Prob. 107ECh. 2.5 - Prob. 108ECh. 2.5 - Prob. 109ECh. 2.5 - Prob. 110ECh. 2.5 - Prob. 112ECh. 2.5 - Prob. 113ECh. 2.5 - Prob. 114ECh. 2.6 - Prob. 115UYKCh. 2.6 - Prob. 116UYKCh. 2.6 - Prob. 117UYKCh. 2.6 - Prob. 118UYKCh. 2.6 - Prob. 119UYKCh. 2.6 - Prob. 120UYKCh. 2.6 - Prob. 121ECh. 2.6 - Prob. 122ECh. 2.6 - Prob. 123ECh. 2.6 - Prob. 124ECh. 2.6 - Prob. 125ECh. 2.6 - Prob. 126ECh. 2.6 - Prob. 127ECh. 2.6 - Prob. 128ECh. 2.6 - Prob. 129ECh. 2.6 - Prob. 130ECh. 2.6 - Prob. 131ECh. 2.6 - Prob. 132ECh. 2.7 - Prob. 133ECh. 2.7 - Prob. 134ECh. 2.7 - Prob. 135ECh. 2.7 - Prob. 136ECh. 2.7 - Prob. 137ECh. 2.7 - Prob. 138ECh. 2.7 - Prob. 139ECh. 2.7 - Prob. 140ECh. 2.7 - Prob. 141ECh. 2.7 - Prob. 142ECh. 2.7 - Prob. 143ECh. 2.7 - Prob. 144ECh. 2.7 - Prob. 145ECh. 2 - Prob. 146ECh. 2 - Prob. 147ECh. 2 - Prob. 148ECh. 2 - Prob. 149ECh. 2 - Prob. 150ECh. 2 - Prob. 151ECh. 2 - Prob. 152ECh. 2 - Prob. 153ECh. 2 - Prob. 154ECh. 2 - Prob. 155ECh. 2 - Prob. 156ECh. 2 - Prob. 157ECh. 2 - Prob. 158ECh. 2 - Prob. 159ECh. 2 - Prob. 160ECh. 2 - Prob. 161ECh. 2 - Prob. 162ECh. 2 - Prob. 163ECh. 2 - Prob. 164ECh. 2 - Prob. 165ECh. 2 - Prob. 166ECh. 2 - Prob. 167ECh. 2 - Prob. 168ECh. 2 - Prob. 169ECh. 2 - Prob. 170ECh. 2 - Prob. 171ECh. 2 - Prob. 172ECh. 2 - Prob. 173ECh. 2 - Prob. 174ECh. 2 - Prob. 175ECh. 2 - Prob. 176ECh. 2 - Prob. 177ECh. 2 - Prob. 178E
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.Similar questions
- Discuss and explain in the picturearrow_forwardBob and Teresa each collect their own samples to test the same hypothesis. Bob’s p-value turns out to be 0.05, and Teresa’s turns out to be 0.01. Why don’t Bob and Teresa get the same p-values? Who has stronger evidence against the null hypothesis: Bob or Teresa?arrow_forwardReview a classmate's Main Post. 1. State if you agree or disagree with the choices made for additional analysis that can be done beyond the frequency table. 2. Choose a measure of central tendency (mean, median, mode) that you would like to compute with the data beyond the frequency table. Complete either a or b below. a. Explain how that analysis can help you understand the data better. b. If you are currently unable to do that analysis, what do you think you could do to make it possible? If you do not think you can do anything, explain why it is not possible.arrow_forward
- 0|0|0|0 - Consider the time series X₁ and Y₁ = (I – B)² (I – B³)Xt. What transformations were performed on Xt to obtain Yt? seasonal difference of order 2 simple difference of order 5 seasonal difference of order 1 seasonal difference of order 5 simple difference of order 2arrow_forwardCalculate the 90% confidence interval for the population mean difference using the data in the attached image. I need to see where I went wrong.arrow_forwardMicrosoft Excel snapshot for random sampling: Also note the formula used for the last column 02 x✓ fx =INDEX(5852:58551, RANK(C2, $C$2:$C$51)) A B 1 No. States 2 1 ALABAMA Rand No. 0.925957526 3 2 ALASKA 0.372999976 4 3 ARIZONA 0.941323044 5 4 ARKANSAS 0.071266381 Random Sample CALIFORNIA NORTH CAROLINA ARKANSAS WASHINGTON G7 Microsoft Excel snapshot for systematic sampling: xfx INDEX(SD52:50551, F7) A B E F G 1 No. States Rand No. Random Sample population 50 2 1 ALABAMA 0.5296685 NEW HAMPSHIRE sample 10 3 2 ALASKA 0.4493186 OKLAHOMA k 5 4 3 ARIZONA 0.707914 KANSAS 5 4 ARKANSAS 0.4831379 NORTH DAKOTA 6 5 CALIFORNIA 0.7277162 INDIANA Random Sample Sample Name 7 6 COLORADO 0.5865002 MISSISSIPPI 8 7:ONNECTICU 0.7640596 ILLINOIS 9 8 DELAWARE 0.5783029 MISSOURI 525 10 15 INDIANA MARYLAND COLORADOarrow_forward
- Suppose the Internal Revenue Service reported that the mean tax refund for the year 2022 was $3401. Assume the standard deviation is $82.5 and that the amounts refunded follow a normal probability distribution. Solve the following three parts? (For the answer to question 14, 15, and 16, start with making a bell curve. Identify on the bell curve where is mean, X, and area(s) to be determined. 1.What percent of the refunds are more than $3,500? 2. What percent of the refunds are more than $3500 but less than $3579? 3. What percent of the refunds are more than $3325 but less than $3579?arrow_forwardA normal distribution has a mean of 50 and a standard deviation of 4. Solve the following three parts? 1. Compute the probability of a value between 44.0 and 55.0. (The question requires finding probability value between 44 and 55. Solve it in 3 steps. In the first step, use the above formula and x = 44, calculate probability value. In the second step repeat the first step with the only difference that x=55. In the third step, subtract the answer of the first part from the answer of the second part.) 2. Compute the probability of a value greater than 55.0. Use the same formula, x=55 and subtract the answer from 1. 3. Compute the probability of a value between 52.0 and 55.0. (The question requires finding probability value between 52 and 55. Solve it in 3 steps. In the first step, use the above formula and x = 52, calculate probability value. In the second step repeat the first step with the only difference that x=55. In the third step, subtract the answer of the first part from the…arrow_forwardIf a uniform distribution is defined over the interval from 6 to 10, then answer the followings: What is the mean of this uniform distribution? Show that the probability of any value between 6 and 10 is equal to 1.0 Find the probability of a value more than 7. Find the probability of a value between 7 and 9. The closing price of Schnur Sporting Goods Inc. common stock is uniformly distributed between $20 and $30 per share. What is the probability that the stock price will be: More than $27? Less than or equal to $24? The April rainfall in Flagstaff, Arizona, follows a uniform distribution between 0.5 and 3.00 inches. What is the mean amount of rainfall for the month? What is the probability of less than an inch of rain for the month? What is the probability of exactly 1.00 inch of rain? What is the probability of more than 1.50 inches of rain for the month? The best way to solve this problem is begin by a step by step creating a chart. Clearly mark the range, identifying the…arrow_forward
- Client 1 Weight before diet (pounds) Weight after diet (pounds) 128 120 2 131 123 3 140 141 4 178 170 5 121 118 6 136 136 7 118 121 8 136 127arrow_forwardClient 1 Weight before diet (pounds) Weight after diet (pounds) 128 120 2 131 123 3 140 141 4 178 170 5 121 118 6 136 136 7 118 121 8 136 127 a) Determine the mean change in patient weight from before to after the diet (after – before). What is the 95% confidence interval of this mean difference?arrow_forwardIn order to find probability, you can use this formula in Microsoft Excel: The best way to understand and solve these problems is by first drawing a bell curve and marking key points such as x, the mean, and the areas of interest. Once marked on the bell curve, figure out what calculations are needed to find the area of interest. =NORM.DIST(x, Mean, Standard Dev., TRUE). When the question mentions “greater than” you may have to subtract your answer from 1. When the question mentions “between (two values)”, you need to do separate calculation for both values and then subtract their results to get the answer. 1. Compute the probability of a value between 44.0 and 55.0. (The question requires finding probability value between 44 and 55. Solve it in 3 steps. In the first step, use the above formula and x = 44, calculate probability value. In the second step repeat the first step with the only difference that x=55. In the third step, subtract the answer of the first part from the…arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Glencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw Hill
Holt Mcdougal Larson Pre-algebra: Student Edition...AlgebraISBN:9780547587776Author:HOLT MCDOUGALPublisher:HOLT MCDOUGAL
Big Ideas Math A Bridge To Success Algebra 1: Stu...AlgebraISBN:9781680331141Author:HOUGHTON MIFFLIN HARCOURTPublisher:Houghton Mifflin Harcourt
Functions and Change: A Modeling Approach to Coll...AlgebraISBN:9781337111348Author:Bruce Crauder, Benny Evans, Alan NoellPublisher:Cengage Learning
Glencoe Algebra 1, Student Edition, 9780079039897...
Algebra
ISBN:9780079039897
Author:Carter
Publisher:McGraw Hill
Holt Mcdougal Larson Pre-algebra: Student Edition...
Algebra
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Big Ideas Math A Bridge To Success Algebra 1: Stu...
Algebra
ISBN:9781680331141
Author:HOUGHTON MIFFLIN HARCOURT
Publisher:Houghton Mifflin Harcourt
Functions and Change: A Modeling Approach to Coll...
Algebra
ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
Publisher:Cengage Learning
How to make Frequency Distribution Table / Tally Marks and Frequency Distribution Table; Author: Reenu Math;https://www.youtube.com/watch?v=i_A6RiE8tLE;License: Standard YouTube License, CC-BY
Frequency distribution table in statistics; Author: Math and Science;https://www.youtube.com/watch?v=T7KYO76DoOE;License: Standard YouTube License, CC-BY
Frequency Distribution Table for Grouped/Continuous data | Math Dot Com; Author: Maths dotcom;https://www.youtube.com/watch?v=ErnccbXQOPY;License: Standard Youtube License