(a)
To find: The marginal total of the provided data to add them in the table.
(a)

Answer to Problem 157E
Solution: The obtained marginal totals are shown in the below table.
Field of study |
Canada |
France |
Germany |
Italy |
Japan |
UK |
US |
Total` |
SsBL |
64 |
153 |
66 |
125 |
250 |
152 |
878 |
1688 |
SME |
35 |
111 |
66 |
80 |
136 |
128 |
355 |
911 |
AH |
27 |
74 |
33 |
42 |
123 |
105 |
397 |
801 |
Ed |
20 |
45 |
18 |
16 |
39 |
14 |
167 |
319 |
Other |
30 |
289 |
35 |
58 |
97 |
76 |
272 |
857 |
Total |
176 |
672 |
218 |
321 |
645 |
475 |
2069 |
4576 |
Explanation of Solution
Calculation: To obtain the marginal totals, below steps are followed in the Minitab software.
Step 1: Enter the data in Minitab worksheet.
Step 2: Go to Stat > Tables >
Step 3: Select “Field” in “For rows” and select “Country” in “For columns”. And select “Count” in “Frequencies are in”.
Step 4: Select the option “Counts” under the “Categorical Variables”.
Step 5: Click OK twice.
The totals are obtained as the Minitab output. The obtained marginal totals are shown in the below table.
Field of study |
Canada |
France |
Germany |
Italy |
Japan |
UK |
US |
Total |
SsBL |
64 |
153 |
66 |
125 |
250 |
152 |
878 |
1688 |
SME |
35 |
111 |
66 |
80 |
136 |
128 |
355 |
911 |
AH |
27 |
74 |
33 |
42 |
123 |
105 |
397 |
801 |
Ed |
20 |
45 |
18 |
16 |
39 |
14 |
167 |
319 |
Other |
30 |
289 |
35 |
58 |
97 |
76 |
272 |
857 |
Total |
176 |
672 |
218 |
321 |
645 |
475 |
2069 |
4576 |
Interpretation: The row Total of the table indicates the marginal total corresponding to the Field of Study and the column Total shows the marginal totals for each country.
(b)
To find: The marginal distribution for the countries of the provided data and the graphical representation of the distribution.
(b)

Answer to Problem 157E
Solution: The obtained marginal totals are shown in the below table.
Country |
Canada |
France |
Germany |
Italy |
Japan |
UK |
US |
Total |
Marginal Percentage |
3.846 |
14.685 |
4.764 |
7.015 |
14.095 |
10.38 |
45.214 |
100 |
And the graphical representation is shown below:
Explanation of Solution
Calculation: To obtain the marginal distribution, below steps are followed in the Minitab software.
Step 1: Enter the data in Minitab worksheet.
Step 2: Go to Stat > Tables > Descriptive Statistics.
Step 3: Select “Field” in “For rows” and select “Country” in “For columns”. And select “Count” in “Frequencies are in”.
Step 4: Select the option “Total percents” and under the “Categorical Variables”.
Step 5: Click OK twice.
The percentage of totals are obtained as the Minitab output. The obtained marginal distribution are shown in the below table.
Country |
Canada |
France |
Germany |
Italy |
Japan |
UK |
US |
Total |
Marginal Percentage |
3.846 |
14.685 |
4.764 |
7.015 |
14.095 |
10.38 |
45.214 |
100 |
Graph: The marginal distribution is graphically shown by using the bar graph. To obtained the graphical representation, below steps are followed in the Minitab software.
Step 1: Insert the data into the worksheet.
Step 2: Go to Graph
Step 3: Click on the drop down menu of “Bar represents” and select “Values from table”.
Step 3: Select “Simple” and click “OK”.
Step 4: Specify the “Graph variables” and “Categorical variable”.
Step 5: Click “OK”.
The bar graph is obtained as:
Interpretation: The maximum percentage of students belongs to US whereas the minimum percentage of the students belongs to Canada.
(c)
To find: The marginal distribution for the Field of study of the provided data and the graphical representation of the distribution.
(c)

Answer to Problem 157E
Solution: The obtained marginal totals are shown in the below table.
Field of study |
SsBL |
SME |
AH |
Ed |
Other |
Total |
Marginal Percentage |
36.888 |
19.908 |
17.504 |
6.971 |
18.728 |
100 |
And the graphical representation is shown below:
Explanation of Solution
Calculation: To obtained the marginal totals, below steps are followed in the Minitab software.
Step 1: Enter the data in Minitab worksheet.
Step 2: Go to Stat > Tables > Descriptive Statistics.
Step 3: Select “Field” in “For rows” and select “Country” in “For columns”. And select “Count” in “Frequencies are in”.
Step 4: Select the option “Total percents” and under the “Categorical Variables”.
Step 5: Click OK twice.
The percentage of totals are obtained as the Minitab output. The obtained marginal distribution are shown in the below table.
Field of study |
SsBL |
SME |
AH |
Ed |
Other |
Total |
Marginal Percentage |
17.504 |
6.971 |
18.728 |
19.908 |
36.888 |
100 |
Graph: The marginal distribution is graphically shown by using the bar graph. To obtain the graphical representation, below steps are followed in the Minitab software.
Step 1: Insert the data into the worksheet.
Step 2: Go to Graph
Step 3: Click on the drop down menu of “Bar represents” and select “Values from table”.
Step 3: Select “Simple” and click “OK”.
Step 4: Specify the “Graph variables” and “Categorical variable”.
Step 5: Click “OK”.
The bar graph is obtained as:
Interpretation: The maximum percentage of students studies SsBL fields whereas the minimum percentage of the students studies Ed.
Want to see more full solutions like this?
Chapter 2 Solutions
EBK INTRODUCTION TO THE PRACTICE OF STA
- I need help with this problem and an explanation of the solution for the image described below. (Statistics: Engineering Probabilities)arrow_forwardI need help with this problem and an explanation of the solution for the image described below. (Statistics: Engineering Probabilities)arrow_forwardI need help with this problem and an explanation of the solution for the image described below. (Statistics: Engineering Probabilities)arrow_forward
- I need help with this problem and an explanation of the solution for the image described below. (Statistics: Engineering Probabilities)arrow_forwardI need help with this problem and an explanation of the solution for the image described below. (Statistics: Engineering Probabilities)arrow_forward3. Consider the following regression model: Yi Bo+B1x1 + = ···· + ßpxip + Єi, i = 1, . . ., n, where are i.i.d. ~ N (0,0²). (i) Give the MLE of ẞ and σ², where ẞ = (Bo, B₁,..., Bp)T. (ii) Derive explicitly the expressions of AIC and BIC for the above linear regression model, based on their general formulae.arrow_forward
- How does the width of prediction intervals for ARMA(p,q) models change as the forecast horizon increases? Grows to infinity at a square root rate Depends on the model parameters Converges to a fixed value Grows to infinity at a linear ratearrow_forwardConsider the AR(3) model X₁ = 0.6Xt-1 − 0.4Xt-2 +0.1Xt-3. What is the value of the PACF at lag 2? 0.6 Not enough information None of these values 0.1 -0.4 이arrow_forwardSuppose you are gambling on a roulette wheel. Each time the wheel is spun, the result is one of the outcomes 0, 1, and so on through 36. Of these outcomes, 18 are red, 18 are black, and 1 is green. On each spin you bet $5 that a red outcome will occur and $1 that the green outcome will occur. If red occurs, you win a net $4. (You win $10 from red and nothing from green.) If green occurs, you win a net $24. (You win $30 from green and nothing from red.) If black occurs, you lose everything you bet for a loss of $6. a. Use simulation to generate 1,000 plays from this strategy. Each play should indicate the net amount won or lost. Then, based on these outcomes, calculate a 95% confidence interval for the total net amount won or lost from 1,000 plays of the game. (Round your answers to two decimal places and if your answer is negative value, enter "minus" sign.) I worked out the Upper Limit, but I can't seem to arrive at the correct answer for the Lower Limit. What is the Lower Limit?…arrow_forward
- Let us suppose we have some article reported on a study of potential sources of injury to equine veterinarians conducted at a university veterinary hospital. Forces on the hand were measured for several common activities that veterinarians engage in when examining or treating horses. We will consider the forces on the hands for two tasks, lifting and using ultrasound. Assume that both sample sizes are 6, the sample mean force for lifting was 6.2 pounds with standard deviation 1.5 pounds, and the sample mean force for using ultrasound was 6.4 pounds with standard deviation 0.3 pounds. Assume that the standard deviations are known. Suppose that you wanted to detect a true difference in mean force of 0.25 pounds on the hands for these two activities. Under the null hypothesis, 40 0. What level of type II error would you recommend here? = Round your answer to four decimal places (e.g. 98.7654). Use α = 0.05. β = 0.0594 What sample size would be required? Assume the sample sizes are to be…arrow_forwardConsider the hypothesis test Ho: 0 s² = = 4.5; s² = 2.3. Use a = 0.01. = σ against H₁: 6 > σ2. Suppose that the sample sizes are n₁ = 20 and 2 = 8, and that (a) Test the hypothesis. Round your answers to two decimal places (e.g. 98.76). The test statistic is fo = 1.96 The critical value is f = 6.18 Conclusion: fail to reject the null hypothesis at a = 0.01. (b) Construct the confidence interval on 02/2/622 which can be used to test the hypothesis: (Round your answer to two decimal places (e.g. 98.76).) 035arrow_forwardUsing the method of sections need help solving this please explain im stuckarrow_forward
- MATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th...StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage LearningStatistics for The Behavioral Sciences (MindTap C...StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. WallnauPublisher:Cengage Learning
- Elementary Statistics: Picturing the World (7th E...StatisticsISBN:9780134683416Author:Ron Larson, Betsy FarberPublisher:PEARSONThe Basic Practice of StatisticsStatisticsISBN:9781319042578Author:David S. Moore, William I. Notz, Michael A. FlignerPublisher:W. H. FreemanIntroduction to the Practice of StatisticsStatisticsISBN:9781319013387Author:David S. Moore, George P. McCabe, Bruce A. CraigPublisher:W. H. Freeman





