
(a)
Interpretation:
The formula and the name of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction:
The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as
(a)

Answer to Problem 105AE
(a)
The formula of the compound is
The name of the binary compound is calcium nitride.
Explanation of Solution
To determine: The formula and the name of the binary compound formed from
The required compound is Calcium nitride
Calcium belongs to the Group
Nitrogen is a non-metal of the
Hence, its oxidation state
So, the formula of the given compound is
The name of the binary compound.
The name of the binary compound is calcium nitride.
The name of the cation present is Calcium
The anion present is Nitride
Calcium only exists in
Hence, the naming of this binary compound is, Calcium nitride.
(b)
Interpretation:
The formula and the name of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction:
The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as
(b)

Answer to Problem 105AE
(b)
The formula of the compound is
The name of the binary compound is Potassium oxide.
Explanation of Solution
To determine: The formula and the name of the binary compound formed from
The required compound is Potassium oxide
Potassium belongs to the Group
Oxygen belongs to the
Hence, its oxidation state
So, the formula of the given compound is
The name of the binary compound.
The name of the binary compound is Potassium oxide.
The name of the cation present is Potassium
The anion present is Oxide
Potassium only exists in
Hence, the naming of this binary compound is, Potassium oxide.
(c)
Interpretation:
The formula and the name of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction:
The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as
(c)

Answer to Problem 105AE
(c)
The formula of the compound is
The name of the binary compound is Rubidium fluoride.
Explanation of Solution
To determine: The formula and the name of the binary compound formed from
The required compound is Rubidium fluoride
Rubidium belongs to the Group
Fluorine belongs to the
Hence, its oxidation state
So, the formula of the given compound is
The name of the binary compound.
The name of the binary compound is Rubidium fluoride.
The name of the cation present is Rubidium
The anion present is Fluoride
Hence, the naming of this binary compound is, Rubidium fluoride.
(d)
Interpretation:
The formula and the name of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction:
The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as
(d)

Answer to Problem 105AE
(d)
The formula of the compound is
The name of the binary compound is Magnesium sulphide.
Explanation of Solution
To determine: The formula and the name of the binary compound formed from
The required compound is Magnesium sulphide
Magnesium belongs to the Group
Sulphur belongs to the
Hence, its oxidation state
So, the formula of the given compound is
The name of the binary compound.
The name of the binary compound is Magnesium sulphide.
The name of the cation present is Magnesium
The anion present is Sulphide
Hence, the naming of this binary compound is, Magnesium sulphide.
(e)
Interpretation:
The formula and the name of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction:
The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as
(e)

Answer to Problem 105AE
(e)
The formula of the compound is
The name of the binary compound is Barium iodide.
Explanation of Solution
To determine: The formula and the name of the binary compound formed from
The required compound is Barium iodide
Barium belongs to the Group
Iodine belongs to the
Hence, its oxidation state
So, the formula of the given compound is
The name of the binary compound.
The name of the binary compound is barium iodide.
The name of the cation present is Barium
The anion present is Iodide
Hence, the naming of this binary compound is, Barium iodide.
(f)
Interpretation:
The formula and the name of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction:
The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as
(f)

Answer to Problem 105AE
(f)
The formula of the compound is
The name of the binary compound is Aluminium selenide.
Explanation of Solution
To determine: The formula and the name of the binary compound formed from
The required compound is Aluminium selenide
Aluminium belongs to the Group
Selenium belongs to the
Hence, its oxidation state
So, the formula of the given compound is
The name of the binary compound.
The name of the binary compound is Aluminium selenide.
The name of the cation present is Aluminium
The anion present is Selenide
Hence, the naming of this binary compound is, Aluminium selenide.
(g)
Interpretation:
The formula and the name of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction:
The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as
(g)

Answer to Problem 105AE
(g)
The formula of the compound is
The name of the binary compound is Cesium phosphide.
Explanation of Solution
To determine: The formula and the name of the binary compound formed from
The required compound is Cesium phosphide
Cesium belongs to the Group
Phosphorous belongs to the
Hence, its oxidation state
So, the formula of the given compound is
The name of the binary compound.
The name of the binary compound is Cesium phosphide.
The name of the cation present is Cesium
The anion present is Phosphide
Hence, the naming of this binary compound is, Cesium phosphide.
(h)
Interpretation:
The formula and the name of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction:
The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as
(h)

Answer to Problem 105AE
(h)
The formula of the compound is
The name of the binary compound is Indium(III) bromide.
Explanation of Solution
To determine: The formula and the name of the binary compound formed from
The required compound is Indium(III) bromide
Indium has an oxidation state of
Oxidation state exhibited by Bromine is
So, the formula of the given compound is
The name of the binary compound.
The name of the binary compound is Indium(III) bromide.
The name of the cation present is Indium
The anion present is Bromide
Here, indium exhibits the
Hence, the naming of this binary compound is, Indium(III) bromide.
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Chapter 2 Solutions
Chemistry
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- Predict the major products of this organic reaction. If there aren't any products, because nothing will happen, check the box under the drawing area instead. No reaction. HO. O :☐ + G Na O.H Click and drag to start drawing a structure. XS xs H₂Oarrow_forwardWhat are the angles a and b in the actual molecule of which this is a Lewis structure? H H C H- a -H b H Note for advanced students: give the ideal angles, and don't worry about small differences from the ideal groups may have slightly different sizes. a = b = 0 °arrow_forwardWhat are the angles a and b in the actual molecule of which this is a Lewis structure? :0: HCOH a Note for advanced students: give the ideal angles, and don't worry about small differences from the ideal that might be caused by the fact that different electron groups may have slightly different sizes. a = 0 b=0° Sarrow_forward
- Determine the structures of the missing organic molecules in the following reaction: + H₂O +H OH O OH +H OH X Note: Molecules that share the same letter have the exact same structure. In the drawing area below, draw the skeletal ("line") structure of the missing organic molecule X. Click and drag to start drawing a structure.arrow_forwardIdentify the missing organic reactant in the following reaction: x + x O OH H* + ☑- X H+ O O Х Note: This chemical equation only focuses on the important organic molecules in the reaction. Additional inorganic or small-molecule reactants or products (like H₂O) are not shown. In the drawing area below, draw the skeletal ("line") structure of the missing organic reactant X. Click and drag to start drawing a structure. Carrow_forwardCH3O OH OH O hemiacetal O acetal O neither O 0 O hemiacetal acetal neither OH hemiacetal O acetal O neither CH2 O-CH2-CH3 CH3-C-OH O hemiacetal O acetal CH3-CH2-CH2-0-c-O-CH2-CH2-CH3 O neither HO-CH2 ? 000 Ar Barrow_forward
- What would be the best choices for the missing reagents 1 and 3 in this synthesis? 1. PPh3 2 2. n-BuLi 3 Draw the missing reagents in the drawing area below. You can draw them in any arrangement you like. • Do not draw the missing reagent 2. If you draw 1 correctly, we'll know what it is. • Note: if one of your reagents needs to contain a halogen, use bromine. Explanation Check Click and drag to start drawing a structure.arrow_forwardPredict the products of this organic reaction: NaBH3CN + NH2 ? H+ Click and drag to start drawing a structure. ×arrow_forwardPredict the organic products that form in the reaction below: + OH +H H+ ➤ ☑ X - Y Note: You may assume you have an excess of either reactant if the reaction requires more than one of those molecules to form the products. In the drawing area below, draw the skeletal ("line") structures of the missing organic products X and Y. You may draw the structures in any arrangement that you like, so long as they aren't touching. Click and drag to start drawing a structure. Garrow_forward
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