Explanation Given that, Weigh, W = 36 lb ⥤ m = 36 32.2 = 1.118 lb.s 2 /ft Spring constant, k = W δ s t = 36 0.2 12 = 2160 lb/ft Undamped natural frequency is given by: ω n = k m = 2160 1.118 = 43.95 rad/s Unbalanced mass: m ' = w δ s t = 0.65 16 32.2 = 1.26 × 10 − 3 r = 6.25 in = 0.52 ft Forcing Frequency: ω f = 2 π N 60 = 2 π × 900 60 = 94.24 rad/s Unbalanced force: P m = m ' r ω 2 f = 1.26x10-3x0.52x94.24² = 5.81 lb Frequency ratio: ω ω n = 94.24 43.95 = 2 To determine ii. The amplitude of the vibration of the motor when damping factor c c c is 0.055.

Vector Mechanics for Engineers: Dynamics

11th Edition

ISBN: 9780077687342

Author: Ferdinand P. Beer, E. Russell Johnston Jr., Phillip J. Cornwell, Brian Self

Publisher: McGraw-Hill Education

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Forced undamped vibrations

In mechanical engineering, vibration is expressed as the term that occurs due to an object's backward and forward movement about a point of equilibrium. Generally, there are three types of vibrations which are,

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Chapter 19.5, Problem 19.144P

To determine

i.

The amplitude of the vibration of the motor when no damping is present.

To determine

ii.

The amplitude of the vibration of the motor when damping factor ccc is 0.055.

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Chapter 19.5, Problem 19.143P

Chapter 19.5, Problem 19.145P

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Vector Mechanics for Engineers: Dynamics

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i. The amplitude of the vibration of the motor when no damping is present.

Solution Summary: The author explains the amplitude of the motor's vibration when no damping is present.