Foundations of College Chemistry 15e Binder Ready Version + WileyPLUS Registration Card
Foundations of College Chemistry 15e Binder Ready Version + WileyPLUS Registration Card
15th Edition
ISBN: 9781119231318
Author: Morris Hein
Publisher: Wiley (WileyPLUS Products)
Question
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Chapter 19.11, Problem 19.12P

(a)

Interpretation Introduction

Interpretation:

IUPAC name of given compound has to be given.

Foundations of College Chemistry 15e Binder Ready Version + WileyPLUS Registration Card, Chapter 19.11, Problem 19.12P , additional homework tip  1

Concept introduction:

IUPAC Nomenclature:

IUAC gives rules for the naming of chemical compounds. These rules are,

Carboxylic ester is the one of the types of organic compound with general structure of RCOOR.

Ester contains two parts, RCO is the acid part and OR is the alcohol part. Parent chain must contain RCOOR group.

In the nomenclature of Carboxylic ester, find the longest chain of the compound first then remaining groups and atoms are consider as substituent.

First write the alcohol part of the compound then write the acid parte with the –ate suffix.

Find the parent chin first then number the carbon atoms in the parent chain by giving lowest number Carboxylic group followed by designate the other substituent in its position in parent chain.

If more than one same substituent or Carboxylic groups were occurs, add a prefix (di-, tri-, tetra-, ect..) in front of parent chain name.

Finally the systematic name was written as, alcohol part followed acid part name with ate suffix.

(b)

Interpretation Introduction

Interpretation:

IUPAC name of given compound has to be given.

Foundations of College Chemistry 15e Binder Ready Version + WileyPLUS Registration Card, Chapter 19.11, Problem 19.12P , additional homework tip  2

Concept introduction:

IUPAC Nomenclature:

IUAC gives rules for the naming of chemical compounds. These rules are,

Carboxylic ester is the one of the types of organic compound with general structure of RCOOR.

Ester contains two parts, RCO is the acid part and OR is the alcohol part. Parent chain must contain RCOOR group.

In the nomenclature of Carboxylic ester, find the longest chain of the compound first then remaining groups and atoms are consider as substituent.

First write the alcohol part of the compound then write the acid parte with the –ate suffix.

Find the parent chin first then number the carbon atoms in the parent chain by giving lowest number Carboxylic group followed by designate the other substituent in its position in parent chain.

If more than one same substituent or Carboxylic groups were occurs, add a prefix (di-, tri-, tetra-, ect..) in front of parent chain name.

Finally the systematic name was written as, alcohol part followed acid part name with ate suffix.

(c)

Interpretation Introduction

Interpretation:

IUPAC name of given compound has to be given.

Foundations of College Chemistry 15e Binder Ready Version + WileyPLUS Registration Card, Chapter 19.11, Problem 19.12P , additional homework tip  3

Concept introduction:

IUPAC Nomenclature:

IUAC gives rules for the naming of chemical compounds. These rules are,

Carboxylic ester is the one of the types of organic compound with general structure of RCOOR.

Ester contains two parts, RCO is the acid part and OR is the alcohol part. Parent chain must contain RCOOR group.

In the nomenclature of Carboxylic ester, find the longest chain of the compound first then remaining groups and atoms are consider as substituent.

First write the alcohol part of the compound then write the acid parte with the –ate suffix.

Find the parent chin first then number the carbon atoms in the parent chain by giving lowest number Carboxylic group followed by designate the other substituent in its position in parent chain.

If more than one same substituent or Carboxylic groups were occurs, add a prefix (di-, tri-, tetra-, ect..) in front of parent chain name.

Finally the systematic name was written as, alcohol part followed acid part name with ate suffix.

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Students have asked these similar questions
(b) NABH, CH3 COCH,CH3 CH3CH2OH (c)
(a) Describe the molecular geometry expected for 1,2,3-butatriene (H2C=C=C=CH2). (b) Two stereoisomers are expected for 2,3,4-hexatriene (CH3CH=C=C=CHCH3). What should be the relationship between these two stereoisomers?
What is the relationship, if any, between these organic compounds?

Chapter 19 Solutions

Foundations of College Chemistry 15e Binder Ready Version + WileyPLUS Registration Card

Ch. 19.10 - Prob. 19.11PCh. 19.11 - Prob. 19.12PCh. 19.12 - Prob. 19.13PCh. 19 - Prob. 1RQCh. 19 - Prob. 2RQCh. 19 - Prob. 3RQCh. 19 - Prob. 4RQCh. 19 - Prob. 5RQCh. 19 - Prob. 6RQCh. 19 - Prob. 7RQCh. 19 - Prob. 8RQCh. 19 - Prob. 9RQCh. 19 - Prob. 10RQCh. 19 - Prob. 11RQCh. 19 - Prob. 12RQCh. 19 - Prob. 13RQCh. 19 - Prob. 14RQCh. 19 - Prob. 15RQCh. 19 - Prob. 16RQCh. 19 - Prob. 17RQCh. 19 - Prob. 18RQCh. 19 - Prob. 19RQCh. 19 - Prob. 20RQCh. 19 - Prob. 21RQCh. 19 - Prob. 23RQCh. 19 - Prob. 24RQCh. 19 - Prob. 25RQCh. 19 - Prob. 26RQCh. 19 - Prob. 27RQCh. 19 - Prob. 28RQCh. 19 - Prob. 29RQCh. 19 - Prob. 30RQCh. 19 - Prob. 31RQCh. 19 - Prob. 32RQCh. 19 - Prob. 33RQCh. 19 - Prob. 34RQCh. 19 - Prob. 35RQCh. 19 - Prob. 36RQCh. 19 - Prob. 37RQCh. 19 - Prob. 1PECh. 19 - Prob. 2PECh. 19 - Prob. 3PECh. 19 - Prob. 4PECh. 19 - Prob. 5PECh. 19 - Prob. 6PECh. 19 - Prob. 7PECh. 19 - Prob. 8PECh. 19 - Prob. 9PECh. 19 - Prob. 10PECh. 19 - Prob. 11PECh. 19 - Prob. 12PECh. 19 - Prob. 13PECh. 19 - Prob. 14PECh. 19 - Prob. 15PECh. 19 - Prob. 16PECh. 19 - Prob. 17PECh. 19 - Prob. 18PECh. 19 - Prob. 19PECh. 19 - Prob. 20PECh. 19 - Prob. 21PECh. 19 - Prob. 22PECh. 19 - Prob. 23PECh. 19 - Prob. 24PECh. 19 - Prob. 25PECh. 19 - Prob. 26PECh. 19 - Prob. 27PECh. 19 - Prob. 28PECh. 19 - Prob. 29PECh. 19 - Prob. 30PECh. 19 - Prob. 31PECh. 19 - Prob. 32PECh. 19 - Prob. 33PECh. 19 - Prob. 34PECh. 19 - Prob. 35PECh. 19 - Prob. 36PECh. 19 - Prob. 37PECh. 19 - Prob. 38PECh. 19 - Prob. 39PECh. 19 - Prob. 40PECh. 19 - Prob. 41PECh. 19 - Prob. 42PECh. 19 - Prob. 43PECh. 19 - Prob. 44PECh. 19 - Prob. 45PECh. 19 - Prob. 46PECh. 19 - Prob. 47PECh. 19 - Prob. 48PECh. 19 - Prob. 49PECh. 19 - Prob. 50PECh. 19 - Prob. 51PECh. 19 - Prob. 52PECh. 19 - Prob. 53PECh. 19 - Prob. 54PECh. 19 - Prob. 55PECh. 19 - Prob. 56PECh. 19 - Prob. 57PECh. 19 - Prob. 58PECh. 19 - Prob. 59PECh. 19 - Prob. 60PECh. 19 - Prob. 61PECh. 19 - Prob. 62PECh. 19 - Prob. 63PECh. 19 - Prob. 64PECh. 19 - Prob. 65AECh. 19 - Prob. 66AECh. 19 - Prob. 67AECh. 19 - Prob. 68AECh. 19 - Prob. 69AECh. 19 - Prob. 70AECh. 19 - Prob. 71AECh. 19 - Prob. 72AECh. 19 - Prob. 73AECh. 19 - Prob. 74AECh. 19 - Prob. 75AECh. 19 - Prob. 76AECh. 19 - Prob. 77AECh. 19 - Prob. 78AECh. 19 - Prob. 79AECh. 19 - Prob. 80AECh. 19 - Prob. 81AECh. 19 - Prob. 82AECh. 19 - Prob. 83AECh. 19 - Prob. 84AECh. 19 - Prob. 85AECh. 19 - Prob. 86AECh. 19 - Prob. 87AECh. 19 - Prob. 89AECh. 19 - Prob. 90AE
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