Chapter 19.1, Problem 9R

To determine

To balance: the given equation.

Explanation of Solution

Introduction:

In balance equation, reactant and product will have same number of coefficient. Chemical reactions can be explained in a precise way through chemical equations.

The given reaction is

$\text{Fe}\left(\text{s}\right){\text{+Cl}}_{\text{2}}\left(\text{g}\right)\to {\text{FeCl}}_{\text{3}}\left(\text{s}\right)$

Here, in this reaction, $\text{Cl}$ is not balanced.

Balance $\text{Cl}$ by multiplying ${\text{FeCl}}_{\text{3}}$ with 2 and ${\text{Cl}}_{\text{3}}$ with 3.

$\text{Fe}\left(\text{s}\right)\text{+}{\text{3Cl}}_{\text{2}}\left(\text{g}\right)\to 2{\text{FeCl}}_{\text{3}}\left(\text{s}\right)$

Now, balance $\text{Fe}$ on reactant side by multiplying with 2.

$\text{2Fe}\left(\text{s}\right)\text{+}{\text{3Cl}}_{\text{2}}\left(\text{g}\right)\to 2{\text{FeCl}}_{\text{3}}\left(\text{s}\right)$

Therefore, the balance reaction is

$\text{2Fe}\left(\text{s}\right)\text{+}{\text{3Cl}}_{\text{2}}\left(\text{g}\right)\to 2{\text{FeCl}}_{\text{3}}\left(\text{s}\right)$

Conclusion:

Hence, the balance equation is $\text{2Fe}\left(\text{s}\right)\text{+}{\text{3Cl}}_{\text{2}}\left(\text{g}\right)\to 2{\text{FeCl}}_{\text{3}}\left(\text{s}\right)$ .