Chapter 19.1, Problem 1PP

To determine

To balance: the equation ${\text{MgCl}}_{\text{2}}{\text{(aq)+AgNO}}_{\text{3}}\text{(aq)}\to \text{Mg}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}\left(\text{aq}\right)\text{+AgCl}\left(\text{s}\right)$ .

Explanation of Solution

Introduction:

In balance equation, reactant and product will have same number of coefficient. Chemical reactions can be explained in a precise way through chemical equations.

The given reaction is

${\text{MgCl}}_{\text{2}}{\text{(aq)+AgNO}}_{\text{3}}\text{(aq)}\to \text{Mg}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}\left(\text{aq}\right)\text{+AgCl}\left(\text{s}\right)$

Here, in reaction, all atoms are balanced except ${\text{NO}}_{\text{3}}$ and $\text{Cl}$ .

The balance $\text{Cl}$ on the product side by multiplying $\text{AgCl}$ with 2.

${\text{MgCl}}_{\text{2}}{\text{(aq)+AgNO}}_{\text{3}}\text{(aq)}\to \text{Mg}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}\left(\text{aq}\right)\text{+2AgCl}\left(\text{s}\right)$

So, $\text{Cl}$ is balanced on both the reactant and product side.

Now, balance Ag and ${\text{NO}}_{\text{3}}$ on reactant side by multiplying ${\text{AgNO}}_{\text{3}}$ with 2,

${\text{MgCl}}_{\text{2}}{\text{(aq)+2AgNO}}_{\text{3}}\text{(aq)}\to \text{Mg}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}\left(\text{aq}\right)\text{+2AgCl}\left(\text{s}\right)$

Thus, the balance reactant is,

${\text{MgCl}}_{\text{2}}{\text{(aq)+2AgNO}}_{\text{3}}\text{(aq)}\to \text{Mg}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}\left(\text{aq}\right)\text{+2AgCl}\left(\text{s}\right)$

Conclusion:

Hence, the balanced equation is ${\text{MgCl}}_{\text{2}}{\text{(aq)+2AgNO}}_{\text{3}}\text{(aq)}\to \text{Mg}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}\left(\text{aq}\right)\text{+2AgCl}\left(\text{s}\right)$ .