
(a)
Interpretation:
Interpret the reason for the use of cobalt-57 for studying body’s requirement of vitamin B12.
Concept Introduction:
Majorly 99% of body mass composed of 6 elements such as oxygen, carbon, hydrogen, nitrogen, calcium and phosphorus while the 5 elements are present in 0.85 % of body.
The elements are required for proper functioning of body as some are requried as catalyst or some are required as oxidasing or reducing agent.
(b)
Interpretation:
Interpret the reason for the use of calcium-47 for studying the bone’s
Concept Introduction:
Majorly 99% of body mass composed of 6 elements such as oxygen, carbon, hydrogen, nitrogen, calcium and phosphorus while the 5 elements are present in 0.85 % of body.
The elements are required for proper functioning of body as some are requried as catalyst or some are required as oxidasing or reducing agent.
(c)
Interpretation:
Interpret the reason for the use of iron-59 for studying RBC function.
Concept Introduction:
Majorly 99% of body mass composed of 6 elements such as oxygen, carbon, hydrogen, nitrogen, calcium and phosphorus while the 5 elements are present in 0.85 % of body.
The elements are required for proper functioning of body as some are requried as catalyst or some are required as oxidasing or reducing agent.
(d)
Interpretation:
Interpret the reason for the use of mercury-197 for studying brain scan before CAT scan.
Concept Introduction:
Majorly 99% of body mass composed of 6 elements such as oxygen, carbon, hydrogen, nitrogen, calcium and phosphorus while the 5 elements are present in 0.85 % of body.
The elements are required for proper functioning of body as some are requried as catalyst or some are required as oxidasing or reducing agent.

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Chapter 19 Solutions
Introductory Chemistry: A Foundation
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- Using a cell of known pathlength b = 1.25115 x 10-3 cm, a water absorption spectrum was measured. The band at 1645 cm-1, assigned to the O-H bending, showed an absorbance, A, of 1.40. a) Assuming that water density is 1.00 g/mL, calculate the water molar concentration c (hint: M= mole/L) b) Calculate the molar absorptivity, a, of the 1645 cm-1 band c) The transmitted light, I, can be written as I= Ioexp(-xb), where x is the absorption coefficient (sometimes designated as alpha), Io is the input light, and b is the cell pathlength. Prove that x= (ln10)*x*c d) Calculate x for the 1645 cm-1 bandarrow_forwardConvert 1.38 eV into wavelength (nm) and wavenumber (cm-1) (c = 2.998 x 108 m/s; h = 6.626 x 10-34 J*s).arrow_forwardCan you help me understand the CBC method on metal bridging by looking at this problem?arrow_forward
- A partir de Aluminio y Co(NO3)2ꞏ6H2O, indicar las reacciones a realizar para obtener Azul de Thenard (Al2CoO4).arrow_forwardTo obtain Thenard Blue (Al2CoO4), the following reaction is correct (performed in an oven):Al(OH)3 + Co(OH)2 → Al2CoO4 + 4 H2Oarrow_forwardProblem 38 can u explain and solve thanks april 24arrow_forward
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