Interpret the hottest and most stableelement. Concept Introduction: The isotope with less half-life will decay with higher rate and is more active for decay in comparison to isotope with more half-life will decay with lower rate and takes more time. For example: Na 2 4 is metallic in nature and loses electron readily to become more active for decay. Moreover, as it has lower half-life of 15 hr while C 1 4 is quite stable to lose or gain electron and thus is least active for decay as it has higher half-life of 5730 yr.

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Answer 1

Question

Chapter 19, Problem 38QAP

Interpretation Introduction

Interpretation:

Interpret the hottest and most stableelement.

Concept Introduction:

The isotope with less half-life will decay with higher rate and is more active for decay in comparison to isotope with more half-life will decay with lower rate and takes more time.

For example: Na²⁴ is metallic in nature and loses electron readily to become more active for decay. Moreover, as it has lower half-life of 15 hr while C¹⁴ is quite stable to lose or gain electron and thus is least active for decay as it has higher half-life of 5730 yr.

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Answer 2

Question

Chapter 19, Problem 38QAP

Interpretation Introduction

Interpretation:

Interpret the hottest and most stableelement.

Concept Introduction:

The isotope with less half-life will decay with higher rate and is more active for decay in comparison to isotope with more half-life will decay with lower rate and takes more time.

For example: Na²⁴ is metallic in nature and loses electron readily to become more active for decay. Moreover, as it has lower half-life of 15 hr while C¹⁴ is quite stable to lose or gain electron and thus is least active for decay as it has higher half-life of 5730 yr.

Expert Solution & Answer

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Check out a sample textbook solution

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Answer 3

Question

Chapter 19, Problem 38QAP

Interpretation Introduction

Interpretation:

Interpret the hottest and most stableelement.

Concept Introduction:

The isotope with less half-life will decay with higher rate and is more active for decay in comparison to isotope with more half-life will decay with lower rate and takes more time.

For example: Na²⁴ is metallic in nature and loses electron readily to become more active for decay. Moreover, as it has lower half-life of 15 hr while C¹⁴ is quite stable to lose or gain electron and thus is least active for decay as it has higher half-life of 5730 yr.

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Answer 4

Question

Chapter 19, Problem 38QAP

Interpretation Introduction

Interpretation:

Interpret the hottest and most stableelement.

Concept Introduction:

The isotope with less half-life will decay with higher rate and is more active for decay in comparison to isotope with more half-life will decay with lower rate and takes more time.

For example: Na²⁴ is metallic in nature and loses electron readily to become more active for decay. Moreover, as it has lower half-life of 15 hr while C¹⁴ is quite stable to lose or gain electron and thus is least active for decay as it has higher half-life of 5730 yr.

Expert Solution & Answer

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Answer 5

Chapter 19, Problem 38QAP

Interpretation Introduction

Interpretation:

Interpret the hottest and most stableelement.

Concept Introduction:

The isotope with less half-life will decay with higher rate and is more active for decay in comparison to isotope with more half-life will decay with lower rate and takes more time.

For example: Na²⁴ is metallic in nature and loses electron readily to become more active for decay. Moreover, as it has lower half-life of 15 hr while C¹⁴ is quite stable to lose or gain electron and thus is least active for decay as it has higher half-life of 5730 yr.

Answer 6

Chapter 19, Problem 38QAP

Interpretation Introduction

Interpretation:

Interpret the hottest and most stableelement.

Concept Introduction:

The isotope with less half-life will decay with higher rate and is more active for decay in comparison to isotope with more half-life will decay with lower rate and takes more time.

For example: Na²⁴ is metallic in nature and loses electron readily to become more active for decay. Moreover, as it has lower half-life of 15 hr while C¹⁴ is quite stable to lose or gain electron and thus is least active for decay as it has higher half-life of 5730 yr.

Answer 7

Chapter 19, Problem 38QAP

Interpretation Introduction

Interpretation:

Interpret the hottest and most stableelement.

Concept Introduction:

The isotope with less half-life will decay with higher rate and is more active for decay in comparison to isotope with more half-life will decay with lower rate and takes more time.

For example: Na²⁴ is metallic in nature and loses electron readily to become more active for decay. Moreover, as it has lower half-life of 15 hr while C¹⁴ is quite stable to lose or gain electron and thus is least active for decay as it has higher half-life of 5730 yr.

Answer 8

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Answer 11

Ch. 19.1 - Prob. 1CT Ch. 19.1 - Prob. 19.1SC Ch. 19.1 - Prob. 19.2SC Ch. 19.3 - Exercise19.3Watches with numerals that glow in the...Ch. 19.8 - Prob. 1CT Ch. 19 - Prob. 1ALQ Ch. 19 - Prob. 2ALQ Ch. 19 - Prob. 3ALQ Ch. 19 - Prob. 4ALQ Ch. 19 - Prob. 5ALQ

Solution Summary: The author explains that Na 2 4 is metallic in nature and loses electron readily to become more active for decay. Ca is the hottest element and C is most stable.

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