Concept explainers
A common reference electrode consists of a silver we coated with AgCl(s) and immersed in 1M KCI.
a. What is
b. Cite several reasons why this electrode should be easier use than a standard hydrogen electrode
c. By comparing the potential of the silver-silver chloride electrode with that of the silver-silver eon electrode, determine
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General Chemistry: Principles and Modern Applications (11th Edition)
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- It took 150. s for a current of 1.25 A to plate out 0.109 g of a metal from a solution containing its cations. Show that it is not possible for the cations to have a charge of 1+.arrow_forwardA galvanic cell is based on the following half-reactions: In this cell, the copper compartment contains a copper electrode and [Cu2+] = 1.00 M, and the vanadium compartment contains a vanadium electrode and V2+ at an unknown concentration. The compartment containing the vanadium (1.00 L of solution) was titrated with 0.0800 M H2EDTA2, resulting in the reaction H2EDTA2(aq)+V2+(aq)VEDTA2(aq)+2H+(aq)K=? The potential of the cell was monitored to determine the stoichiometric point for the process, which occurred at a volume of 500.0 mL H2EDTA2 solution added. At the stoichiometric point, was observed to be 1 .98 V. The solution was buffered at a pH of 10.00. a. Calculate before the titration was carried out. b. Calculate the value of the equilibrium constant, K, for the titration reaction. c. Calculate at the halfway point in the titration.arrow_forwardAn electrochemical cell consists of a nickel metal electrode immersed in a solution with [Ni2+] = 1.0 M separated by a porous disk from an aluminum metal electrode immersed in a solution with [Al3+] = 1.0 M. Sodium hydroxide is added to the aluminum compartment, causing Al(OH)3(s) to precipitate. After precipitation of Al(OH)3 has ceased, the concentration of OH is 1.0 104 M and the measured cell potential is 1.82 V. Calculate the Ksp value for Al(OH)3. Al(OH)3(s)Al3+(aq)+3OH(aq)Ksp=?arrow_forward
- What is the maximum work you can obtain from 30.0 g of nickel in the following cell when the cell potential is 0.97 V? Ni(s)Ni2+(aq)Ag+(aq)Ag(s)arrow_forwardThe cell potential of the following cell at 25C is 0.480 V. ZnZn2+(1M)H+(testsolution)H2(1atm)Pt What is the pH of the test solution?arrow_forwardA current of 0.0100 A is passed through a solution of rhodium sulfate, causing reduction of the metal ion to the metal. After 3.00 hours, 0.038 g of Rh has been deposited. What is the charge on the rhodium ion, Rhn+? What is the formula for rhodium sulfate?arrow_forward
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