COLLEGE PHYSICS LL W/ 6 MONTH ACCESS
COLLEGE PHYSICS LL W/ 6 MONTH ACCESS
2nd Edition
ISBN: 9781319414597
Author: Freedman
Publisher: MAC HIGHER
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Chapter 19, Problem 67QAP
To determine

(a)

The magnetic field 1.0 m and 1.0 km from a bolt of lighting can transfer 10 C of charge in 2.0μs and also compare the calculated fields with Earth`s magnetic field

Expert Solution
Check Mark

Answer to Problem 67QAP

  Magnetic field at a distance of 1.0 m = 1.0 TMagnetic field at a distance of 1.0 km=1.0×103 TComparison of earth magnetic field with 1.0 m magnetic field due to bolt =20000Comparison of earth magnetic field with 1.0 m magnetic field due to bolt = 20

Explanation of Solution

Given info:

  Transferring charge = 10 CDuration = 2.0μs

Formula used:

  I=QtI=CurrentQ=charget=time

  B=μ0I2πdB=Magnetic fieldμ0=permeability of free spaceI=Current in wired=Radius from the wire

Calculation:

  Current produced,I=QtI=10 C2× 10 6 sI=5×106 A

  Magnetic field at a distance of 1.0 mB=μ0I2πdB=4π× 10 7×5× 1062π×1B=1.0 T

  Magnetic field at a distance of 1.0 kmB=μ0I2πdB=4π× 10 7×5× 1062π×1× 103B=1.0×103 T

  Earth magnetic field = 5.0×105 T Comparison with 1.0 m magnetic field due to bolt,BB earth=1 T5.0× 10 5 T=20000 Comparison with 1.0 km magnetic field due to bolt,BB earth=1.0× 10 3 T5.0× 10 5 T=20

Conclusion:

Thus, the magnetic field at a distance of 1 m is 1 T and at distance of 1 km 1.0×103 T and after comparing of Earth magnetic field with 1.0 m magnetic field due to bolt is 20000 and with 1.0 km is 20

To determine

(b)

Compare the fields in part (a) with the magnetic field produced by a typical household current of 10 A in a very long wire at the same distances from the wire as in (a)

Expert Solution
Check Mark

Answer to Problem 67QAP

  Magnetic field at a distance of 1.0 m = 2*106 TMagnetic field at a distance of 1.0 km=2.0*109 TComparison of house hold current 1.0 m magnetic field to bolt 1.0 m magnetic field  =500000Comparison of house hold current 1.0 km magnetic field to bolt 1.0 km magnetic field  =500000

Explanation of Solution

Given info:

  Current = 10 A

Formula used:

  B=μ0I2πdB=Magnetic fieldμ0=permeability of free spaceI=Current in wired=Radius from the wire

Calculation:

  Magnetic field at a distance of 1.0 mB=μ0I2πdB=4π× 10 7×102π×1B=2×106 T

  Magnetic field at a distance of 1.0 kmB=μ0I2πdB=4π× 10 7×102π×1× 103B=2.0×109 T

  Earth magnetic field = 5.0×105 T Comparison with 1.0 m magnetic field due to bolt and 1.0 m due to household current,B boltB house=1 T2.0× 10 6 T=500000Comparison with 1.0 km magnetic field due to bolt and 1.0 km due to household current,B boltB house=1.0× 10 3 T2.0× 10 9 T=500000

Conclusion:

  Magnetic field at a distance of 1.0 m = 2×106 TMagnetic field at a distance of 1.0 km=2.0×109 TComparison of house hold current 1.0 m magnetic field to bolt 1.0 m magnetic field  =500000Comparison of house hold current 1.0 km magnetic field to bolt 1.0 km magnetic field  =500000

To determine

(c)

How close would you have to get to the wire in part (b) for its magnetic field to be the same as the field produced by the lightning bolt at 1.0 km from the bolt

Expert Solution
Check Mark

Answer to Problem 67QAP

2 mm

Explanation of Solution

Given info:

  Current = 10 A

Formula used:

  B=μ0I2πdB=Magnetic fieldμ0=permeability of free spaceI=Current in wired=Radius from the wire

Calculation:

  Magnetic field due to bolt at a distance of 1.0 km = 1×10-3 TB=μ0I2πd1×10-3 T=4π× 10 7×102π×dd=2×103 m

Conclusion:

Thus, the wire should 2 mm close for its magnetic field to be the same as the field produced by the lightning bolt at 1.0 km from the bolt

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Chapter 19 Solutions

COLLEGE PHYSICS LL W/ 6 MONTH ACCESS

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