Starting Out With C++: Early Objects (10th Edition)
10th Edition
ISBN: 9780135235003
Author: Tony Gaddis, Judy Walters, Godfrey Muganda
Publisher: PEARSON
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Question
Chapter 19, Problem 3RQE
A node without child is referred a “leaf node”.
Program Plan Intro
Binary tree:
A complete binary tree is a binary tree with the property that every node must have exactly two children, and at the last level the nodes should be from left to right.
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Assume the tree node structure is following........
struct node
{
int data;
struct node* left;
struct node* right;
};
struct node *root = null;
and there is a created new node function, called newnode(int new_data).
Please filled the Blank of Insertion function.
void insert(struct node *root, int key) {
struct node *current;
queue q;
q.enque(root);
while(!q.empty()
}
current = q.front();
q.deque();
if(current->left == NULL) {
break;
}
else
}
q.enque(
if(current->right == NULL) {
break;
else
q.enque(_
= newnode(key);
= newnode(key);
_-));
#ifndef BT_NODE_H#define BT_NODE_H
struct btNode{ int data; btNode* left; btNode* right;};
// pre: bst_root is root pointer of a binary search tree (may be 0 for// empty tree) and portArray has the base address of an array large// enough to hold all the data items in the binary search tree// post: The binary search tree has been traversed in-order and the data// values are written (as they are encountered) to portArray in// increasing positional order starting from the first elementvoid portToArrayInOrder(btNode* bst_root, int* portArray);void portToArrayInOrderAux(btNode* bst_root, int* portArray, int& portIndex);
// pre: (none)// post: dynamic memory of all the nodes of the tree rooted at root has been// freed up (returned back to heap/freestore) and the tree is now empty// (root pointer contains the null address)void tree_clear(btNode*& root);
// pre: (none)// post: # of nodes contained in tree rooted at root is returnedint…
Computer Science
lab3.h
-------------
#include<stdio.h>
#include<stdlib.h>
#ifndef LAB3_H
#define LAB3_H
// A linked list node
struct Node
{
int data; //Data
struct Node *next; // Address to the next node
};
//initialize: create an empty head node (whose "data" is intentionally missing); This head node will not be used to store any data;
struct Node *init () {
//create head node
struct Node *head = (struct Node*)malloc(sizeof(struct Node));
}
//Create a new node to store data and insert it to the end of current linked list; the head node will still be empty and data in the array in "main.c" are not stored in head node
void insert(struct node *head, int data) {
struct Node *newNode = (struct Node*)malloc(sizeof(struct Node));
new_node->data = data;
new_node->next= head;
}
//print data for all nodes in the linked list except the head node (which is empty)
void display (struct Node *head) {
struct Node *current_node = head;
while ( current_node != NULL) {
printf("%d ",…
Chapter 19 Solutions
Starting Out With C++: Early Objects (10th Edition)
Ch. 19.1 - Prob. 19.1CPCh. 19.1 - Prob. 19.2CPCh. 19.1 - Prob. 19.3CPCh. 19.1 - Prob. 19.4CPCh. 19.1 - Prob. 19.5CPCh. 19.1 - Prob. 19.6CPCh. 19.2 - Prob. 19.7CPCh. 19.2 - Prob. 19.8CPCh. 19.2 - Prob. 19.9CPCh. 19.2 - Prob. 19.10CP
Ch. 19.2 - Prob. 19.11CPCh. 19.2 - Prob. 19.12CPCh. 19 - Prob. 1RQECh. 19 - Prob. 2RQECh. 19 - Prob. 3RQECh. 19 - Prob. 4RQECh. 19 - Prob. 5RQECh. 19 - Prob. 6RQECh. 19 - Prob. 7RQECh. 19 - Prob. 8RQECh. 19 - Prob. 9RQECh. 19 - Prob. 10RQECh. 19 - Prob. 11RQECh. 19 - Prob. 12RQECh. 19 - Prob. 13RQECh. 19 - Prob. 14RQECh. 19 - Prob. 15RQECh. 19 - Prob. 16RQECh. 19 - Prob. 17RQECh. 19 - Prob. 18RQECh. 19 - Prob. 19RQECh. 19 - Prob. 20RQECh. 19 - Prob. 1PCCh. 19 - Prob. 2PCCh. 19 - Prob. 3PCCh. 19 - Prob. 4PCCh. 19 - Prob. 5PCCh. 19 - Prob. 6PCCh. 19 - Prob. 7PCCh. 19 - Prob. 8PCCh. 19 - Prob. 9PCCh. 19 - Prob. 10PC
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