Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN: 9781285199047
Author: John W. Moore, Conrad L. Stanitski
Publisher: Cengage Learning
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Chapter 19, Problem 32QRT

(a)

Interpretation Introduction

Interpretation:

Amount of Na(s) and Cl2(g) has to be calculated that can be produced in 24 hours.

(a)

Expert Solution
Check Mark

Explanation of Solution

In Downs process, the reaction that takes place is given as,

    2Na+(aq) + 2e- 2Na(s) 2Cl-(aq) Cl2(g) + 2e-

In the problem statement it is given as the Downs cell operates at 7.0V and 4.0×104A.

The number of moles of electrons that is required can be calculated as shown below,

    24hr×(4×104A)×3600s1hr×1C1A·1s×1mole-96485C = 34560096485×104mole- = 3.58×104mole-

From the mol of electrons that is required, the amount of sodium and chlorine that is obtained can be calculated as shown below,

    3.58×104mole-×2molNa2mole-×22.9898gNa1molNa = 164.60692×104gNa = 82.30×104gNa = 8.23×105gNa

    3.58×104mole-×1molCl22mole-×70.906gCl21molCl2 = 253.843482×104gCl2 = 126.92×104gCl2 = 1.27×106gCl2

Therefore, the amount of sodium and chlorine obtained is 8.23×105g and 1.27×106g respectively.

(b)

Interpretation Introduction

Interpretation:

Energy consumption for the given Downs cell in 24 hours has to be calculated.

(b)

Expert Solution
Check Mark

Explanation of Solution

In Downs process, the reaction that takes place is given as,

    2Na+(aq) + 2e- 2Na(s) 2Cl-(aq) Cl2(g) + 2e-

In the problem statement it is given as the Downs cell operates at 7.0V and 4.0×104A.

Energy consumption of this cell can be calculated as shown below,

    24hr×(4×104A)×3600s1hr×1C1A·1s×7.0V×1J1C·1V×1kWh3.60×106J = 24192003.6×102kWh = 672000×102kWh = 6.7×103kWh

Energy consumption is calculated as 6.7×103kWh.

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Chapter 19 Solutions

Chemistry: The Molecular Science

Ch. 19.5 - Prob. 19.9ECh. 19.5 - Prob. 19.3PSPCh. 19.5 - Use the terms oxidation, reduction, oxidizing...Ch. 19.5 - Prob. 19.11ECh. 19.6 - Prob. 19.13ECh. 19.6 - Prob. 19.14ECh. 19.6 - Prob. 19.15CECh. 19.6 - Prob. 19.16CECh. 19.6 - Prob. 19.4PSPCh. 19.6 - Prob. 19.5PSPCh. 19.6 - Prob. 19.17ECh. 19.6 - Prob. 19.6PSPCh. 19.6 - Prob. 19.7PSPCh. 19.6 - Prob. 19.8PSPCh. 19 - Prob. 1QRTCh. 19 - Prob. 2QRTCh. 19 - Prob. 3QRTCh. 19 - Prob. 4QRTCh. 19 - Prob. 5QRTCh. 19 - Prob. 6QRTCh. 19 - Prob. 7QRTCh. 19 - Prob. 8QRTCh. 19 - Prob. 9QRTCh. 19 - Prob. 10QRTCh. 19 - Prob. 11QRTCh. 19 - Prob. 12QRTCh. 19 - Prob. 13QRTCh. 19 - Prob. 14QRTCh. 19 - Prob. 15QRTCh. 19 - Prob. 16QRTCh. 19 - Prob. 17QRTCh. 19 - Prob. 18QRTCh. 19 - Prob. 19QRTCh. 19 - Prob. 20QRTCh. 19 - Prob. 21QRTCh. 19 - Prob. 22QRTCh. 19 - Prob. 23QRTCh. 19 - Prob. 24QRTCh. 19 - Prob. 25QRTCh. 19 - Prob. 26QRTCh. 19 - Identify the substance or substances produced by...Ch. 19 - Prob. 28QRTCh. 19 - Prob. 29QRTCh. 19 - Prob. 30QRTCh. 19 - Prob. 31QRTCh. 19 - Prob. 32QRTCh. 19 - Prob. 33QRTCh. 19 - Prob. 34QRTCh. 19 - Prob. 35QRTCh. 19 - Prob. 36QRTCh. 19 - Prob. 37QRTCh. 19 - Prob. 38QRTCh. 19 - Prob. 39QRTCh. 19 - Prob. 40QRTCh. 19 - Prob. 41QRTCh. 19 - Prob. 42QRTCh. 19 - A human body contains approximately 5 L of blood....Ch. 19 - Prob. 44QRTCh. 19 - Prob. 45QRTCh. 19 - Prob. 46QRTCh. 19 - Prob. 47QRTCh. 19 - Prob. 48QRTCh. 19 - Prob. 49QRTCh. 19 - Prob. 50QRTCh. 19 - Prob. 51QRTCh. 19 - Prob. 52QRTCh. 19 - Prob. 53QRTCh. 19 - Prob. 54QRTCh. 19 - Prob. 55QRTCh. 19 - Prob. 56QRTCh. 19 - Prob. 57QRTCh. 19 - Prob. 58QRTCh. 19 - Prob. 59QRTCh. 19 - Prob. 60QRTCh. 19 - Prob. 61QRTCh. 19 - Prob. 62QRTCh. 19 - Prob. 63QRTCh. 19 - Prob. 64QRTCh. 19 - Prob. 65QRTCh. 19 - Prob. 66QRTCh. 19 - Prob. 67QRTCh. 19 - Prob. 68QRTCh. 19 - Prob. 69QRTCh. 19 - Prob. 70QRTCh. 19 - Prob. 71QRTCh. 19 - Prob. 72QRTCh. 19 - Prob. 73QRTCh. 19 - Prob. 74QRTCh. 19 - Use the phase diagram for sulfur for Question 75....Ch. 19 - Prob. 76QRTCh. 19 - Prob. 77QRTCh. 19 - Prob. 78QRTCh. 19 - Prob. 79QRTCh. 19 - Prob. 80QRTCh. 19 - A natural brine found in Arkansas has a bromide...Ch. 19 - Prob. 82QRTCh. 19 - Prob. 83QRTCh. 19 - Prob. 84QRTCh. 19 - At 20. C the vapor pressure of white phosphorus is...Ch. 19 - Prob. 86QRTCh. 19 - Assume that the radius of Earth is 6400 km, the...Ch. 19 - Prob. 88QRTCh. 19 - Prob. 89QRTCh. 19 - Prob. 90QRTCh. 19 - Prob. 91QRTCh. 19 - Prob. 92QRTCh. 19 - Prob. 93QRTCh. 19 - Prob. 94QRTCh. 19 - Prob. 95QRTCh. 19 - Use a Born-Haber cycle (Sec. 5-13) to calculate...Ch. 19 - Prob. 97QRTCh. 19 - Elemental analysis of a borane indicates this...Ch. 19 - Prob. 99QRTCh. 19 - Prob. 100QRT
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