
Concept explainers
(a)
Interpretation:
The hydrophobic and hydrophilic part of the 7, 10, 13, 16, 19-docosapentaenoic acid should be labeled.
Concept Introduction:
Fatty acids are long chain
Unsaturated fatty acids can be defined as the long chain fatty acids which have a long hydrocarbon chain with −COOH group. In unsaturated fatty acids, the carbon chain must have at least one double bond.
(b)
Interpretation:
The melting point difference in the cis and trans-isomer of the 7, 10, 13, 16, 19-docosapentaenoic acid should be determined.
Concept Introduction:
Fatty acids are long chain carboxylic acid, which may or may not have unsaturation in the molecule. They react with glycerol to form triglycerides. The reaction is known as esterification as a carboxylic acid group reacts with the alcoholic group to form an ester group.
Unsaturated fatty acids can be defined as the long chain fatty acids which have a long hydrocarbon chain with −COOH group. In unsaturated fatty acids, the carbon chain must have at least one double bond.
(c)
Interpretation:
The physical state of 7, 10, 13, 16, 19-docosapentaenoic acid as solid or liquid at room temperature should be determined.
Concept Introduction:
Fatty acids are long chain carboxylic acid, which may or may not have unsaturation in the molecule. They react with glycerol to form triglycerides. The reaction is known as esterification as a carboxylic acid group reacts with the alcoholic group to form an ester group.
Unsaturated fatty acids can be defined as the long chain fatty acids which have a long hydrocarbon chain with −COOH group. In unsaturated fatty acids, the carbon chain must have at least one double bond.
(d)
Interpretation:
The omega-n designation for the 7, 10, 13, 16, 19-docosapentaenoic acid should be determined.
Concept Introduction:
Fatty acids are long chain carboxylic acid, which may or may not have unsaturation in the molecule. They react with glycerol to form triglycerides. The reaction is known as esterification as a carboxylic acid group reacts with the alcoholic group to form an ester group.
Unsaturated fatty acids can be defined as the long chain fatty acids which have a long hydrocarbon chain with −COOH group. In unsaturated fatty acids, the carbon chain must have at least one double bond.

Want to see the full answer?
Check out a sample textbook solution
Chapter 19 Solutions
Connect One Semester Access Card for General, Organic, & Biological Chemistry
- Given Kp for 2 reactions. Find the Kp for the following reaction: BrCl(g)+ 1/2 I2(g) ->IBr(g) + 1/2 Cl2(g)arrow_forwardFor a certain gas-phase reaction at constant pressure, the equilibrium constant Kp is observed to double when the temperature increases from 300 K to 400 K. Calculate the enthalpy change of the reaction, Ah, using this information.arrow_forwardHydrogen bonding in water plays a key role in its physical properties. Assume that the energy required to break a hydrogen bond is approximately 8 kJ/mol. Consider a simplified two-state model where a "formed" hydrogen bond is in the ground state and a "broken" bond is in the excited state. Using this model: • Calculate the fraction of broken hydrogen bonds at T = 300 K, and also at T = 273 K and T = 373 K. • At what temperature would approximately 50% of the hydrogen bonds be broken? • What does your result imply about the accuracy or limitations of the two-state model in describing hydrogen bonding in water? Finally, applying your understanding: • Would you expect it to be easier or harder to vaporize water at higher temperatures? Why? If you were to hang wet laundry outside, would it dry more quickly on a warm summer day or on a cold winter day, assuming humidity is constant?arrow_forward
- (3 pts) Use the Kapustinskii equation to calculate the lattice enthalpy for MgBr2 anddiscuss any differences between this result and that from #4.arrow_forward(3 pts) Silver metal adopts a fcc unit cell structure and has an atomic radius of 144 pm. Fromthis information, calculate the density of silver. Show all work.arrow_forward4. (3 pts) From the information below, determine the lattice enthalpy for MgBr2. Show all work. AH/(kJ mol-¹) Sublimation of Mg(s) +148 lonization of Mg(g) +2187 to Mg2+(g) Vaporization of Br₂(1) +31 Dissociation of Br,(g) +193 Electron gain by Br(g) -331 Formation of MgBr₂(s) -524arrow_forward
- 1. (4 pts-2 pts each part) Consider the crystal structures of NaCl, ZnS, and CsCl (not necessarily shown in this order). a. For one of the three compounds, justify that the unit cell is consistent with stoichiometry of the compound. b. In each of the crystal structures, the cations reside in certain holes in the anions' packing structures. For each compound, what type of holes are occupied by the cations and explain why those particular types of holes are preferred.arrow_forward(2 pts) What do you expect to happen in a Na2O crystal if a Cl− ion replaces one of the O2−ions in the lattice?arrow_forward(2 pts) WSe2 is an ionic compound semiconductor that can be made to be p-type or n-type.What must happen to the chemical composition for it to be p-type? What must happen tothe chemical composition for it to be n-type?arrow_forward
- 8. (2 pts) Silicon semiconductors have a bandgap of 1.11 eV. What is the longest photon wavelength that can promote an electron from the valence band to the conduction band in a silicon-based photovoltaic solar cell? Show all work. E = hv = hc/λ h = 6.626 x 10-34 Js c = 3.00 x 108 m/s 1 eV 1.602 x 10-19 Jarrow_forwardA solution containing 100.0 mL of 0.155 M EDTA buffered to pH 10.00 was titrated with 100.0 mL of 0.0152 M Hg(ClO4)2 in a cell: calomel electrode (saturated)//titration solution/Hg(l) Given the formation constant of Hg(EDTA)2-, logKf= 21.5, and alphaY4-=0.30, find out the cell voltage E. Hg2+(aq) + 2e- = Hg(l) E0= 0.852 V E' (calomel electrode, saturated KCl) = 0.241 Varrow_forwardFrom the following reduction potentials I2 (s) + 2e- = 2I- (aq) E0= 0.535 V I2 (aq) + 2e- = 2I- (aq) E0= 0.620 V I3- (aq) + 2e- = 3I- (aq) E0= 0.535 V a) Calculate the equilibrium constant for I2 (aq) + I- (aq) = I3- (aq). b) Calculate the equilibrium constant for I2 (s) + I- (aq) = I3- (aq). c) Calculate the solubility of I2 (s) in water.arrow_forward
- General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningOrganic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningIntroductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage LearningWorld of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage Learning





