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Concept explainers
(a)
Interpretation:
To determine the ligand and their charges in
Concept introduction:
Coordination compounds are those in which a transition metal atom is bonded to a ligand which can be neutral, cation or anion. The
A ligand is an atom or a group of atoms or an anion that has an unshared pair of electrons.Thus, it can act as a Lewis base. It can donate its pair of electrons to the metal atom to form a coordinate bond with the transition metal atom.
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Answer to Problem 1QAP
The ligands in the given complex ion are ammonia, oxalate and chloride ion.
Ammonia is a neutral ligand, while chloride ion carries a charge of -1 and oxalate ion carries a charge of -2.
Explanation of Solution
In the given compound,
Oxalate is denoted by the symbol ‘ox’ and its chemical formula is (C2 O4 ). It is a bidentate ligand as it can forms coordination bond with the transition metal element through two of its oxygen atoms and it carries a charge of -2, one negative charge on each of the terminal oxygen atoms.
Ammonia (NH3 ) is also a monodentate as it forms single coordinate bond with the central metal atom, and it is a neutral ligand as it carries no charge.
Cl- is a monodentate ligand as it forms single coordinate bond with central metal atom.
(b)
Interpretation:
To determine the oxidation state of iron in
Concept introduction:
Coordination compounds are those in which a transition metal atom is bonded to a ligand which can be neutral, cation or anion. The transition metal element is enclosed within a bracket and a charge is present on the ion to balance the charge present on the ligands.
A ligand is an atom or a group of atoms or an anion that has an unshared pair of electrons and thus it can act as a Lewis base. It can donate its pair of electrons to the metal atom to form a coordinate bond with the transition metal atom.
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Answer to Problem 1QAP
The oxidation number of ironis +2 in thiscomplex ion.
Explanation of Solution
In the given compound,
Oxalate is denoted by the symbol ‘ox’ and its chemical formula is (C2 O4 ). It is a bidentate ligand as it can forms coordination bond with the transition metal element through two of its oxygen atoms and it carries a charge of -2, one negative charge on each of the terminal oxygen atoms.
Ammonia (NH3 ) is also a monodentate as it forms single coordinate bond with the central metal atom and it is a neutral ligand as it carries no charge.
Cl- is a monodentate ligand as it forms single coordinate bond with central metal atom.
The total charge on this complex ion is -3. Let ‘x’ be the oxidation number of the central metal atom which is ‘Fe’.
-3 = x + 2 (-2) + 1 (0) + 1(-1)
-3 = x -4-1
-3 +5 = x
x = +2
(c)
Interpretation:
To determine formula of the potassium salt of
Concept introduction:
Coordination compounds are those in which a transition metal atom is bonded to a ligand which can be neutral, cation or anion. The transition metal element is enclosed within a bracket and a charge is present on the ion to balance the charge present on the ligands.
A ligand is an atom or a group of atoms or an anion that has an unshared pair of electrons and thus it can act as a Lewis base. It can donate its pair of electrons to the metal atom to form a coordinate bond with the transition metal atom.
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Answer to Problem 1QAP
The chemical formula of the potassium salt of the given complex ion is
Explanation of Solution
In the given compound,
The total charge on this complex ion is -3. This charge can be neutralized by the presence of three monovalent positively charged cations.
This means that when three potassium ions come in contact with this complex ion, a new potassium salt can be formed with the chemical formula as
Formation of this new potassium salt can be explained as:
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Chapter 19 Solutions
Student Solutions Manual For Masterton/hurley's Chemistry: Principles And Reactions, 8th
- Deducing the reactants of a Diels-Alder reaction vn the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating the reactants? ? Δ O If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like. • If your answer is no, check the box under the drawing area instead. Click and drag to start drawing a structure. Product can't be made in one step. Explanation Checkarrow_forwardPredict the major products of the following organic reaction: Δ ? Some important notes: • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. • Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers. Explanation Check Click and drag to start drawing a structure. Larrow_forward> Can the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating the reactants? ? Δ • If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like. If your answer is no, check the box under the drawing area instead. Explanation Check Click and drag to start drawing a structure. Х © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accesarrow_forward
- Predict the major products of the following organic reaction: O O + A ? Some important notes: • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. • Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers. Explanation Check Click and drag to start drawing a structure. eserved. Terms of Use | Privacy Center >arrow_forward(EXM 2, PRBLM 3) Here is this problem, can you explain it to me and show how its done. Thank you I need to see the work for like prbl solving.arrow_forwardcan someone draw out the reaction mechanism for this reaction showing all bonds, intermediates and side products Comment on the general features of the 1H-NMR spectrum of isoamyl ester provided belowarrow_forward
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