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Concept explainers
(a)
Interpretation: Among the terms triacylglycerol, glycerophospholipid and sphingophospholipids, the term that can be applied to the given characterization has to be predicted.
Concept introduction: Triacylglycerol is produced by the reaction of one molecule of glycerol and three molecules of fatty acid. Glycerophospholipids are basically made up of two fatty acids, a phosphate group which is esterified to glycerol and an alcohol group which is esterified to the phosphate group. In sphingophospholipids, the platform molecule is sphingosine to which one fatty acid and one phosphate group are attached. An alcohol is attached to the phosphate group.
(b)
Interpretation: Among the terms triacylglycerol, glycerophospholipid and sphingophospholipids, the term that can be applied to the given characterization has to be predicted.
Concept introduction: Triacylglycerol is produced by the reaction of one molecule of glycerol and three molecules of fatty acid. Glycerophospholipids are basically made up of two fatty acids, a phosphate group which is esterified to glycerol and an alcohol group which is esterified to the phosphate group. In sphingophospholipids, the platform molecule is sphingosine to which one fatty acid and one phosphate group are attached. An alcohol is attached to the phosphate group.
(c)
Interpretation: Among the terms triacylglycerol, glycerophospholipid and sphingophospholipids, the term that can be applied to the given characterization has to be predicted.
Concept introduction: Triacylglycerol is produced by the reaction of one molecule of glycerol and three molecules of fatty acid. Glycerophospholipids are basically made up of two fatty acids, a phosphate group which is esterified to glycerol and an alcohol group which is esterified to the phosphate group. In sphingophospholipids, the platform molecule is sphingosine to which one fatty acid and one phosphate group are attached. An alcohol is attached to the phosphate group.
(d)
Interpretation: Among the terms triacylglycerol, glycerophospholipid and sphingophospholipids, the term that can be applied to the given characterization has to be predicted.
Concept introduction: Triacylglycerol is produced by the reaction of one molecule of glycerol and three molecules of fatty acid. Glycerophospholipids are basically made up of two fatty acids, a phosphate group which is esterified to glycerol and an alcohol group which is esterified to the phosphate group. In sphingophospholipids, the platform molecule is sphingosine to which one fatty acid and one phosphate group are attached. An alcohol is attached to the phosphate group.
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Chapter 19 Solutions
General, Organic, and Biological Chemistry Seventh Edition
- Illustrate reaction mechanisms of alkenes with water in the presence of H2SO4, detailing each step of the process. Please show steps of processing. Please do both, I will thumb up for sure #1 #3arrow_forwardDraw the following molecule: (Z)-1-chloro-1-butenearrow_forwardIdentify the molecule as having a(n) E, Z, cis, or trans configuration. CH3 H₁₂C ○ E ○ z ○ cis transarrow_forward
- Identify the molecule as having a(n) E, Z, cis, or trans configuration. H₂C- CH3 О Е ○ cis ○ transarrow_forwardThe decomposition of dinitrogen pentoxide according to the equation: 50°C 2 N2O5(g) 4 NO2(g) + O2(g) follows first-order kinetics with a rate constant of 0.0065 s-1. If the initial concentration of N2O5 is 0.275 M, determine: the final concentration of N2O5 after 180 seconds. ...arrow_forwardDon't used hand raitingarrow_forward
- CS2(g) →CS(g) + S(g) The rate law is Rate = k[CS2] where k = 1.6 × 10−6 s−¹. S What is the concentration of CS2 after 5 hours if the initial concentration is 0.25 M?arrow_forwardCS2(g) → CS(g) + S(g) The rate law is Rate = k [CS2] where k = 1.6 × 10-6 s−1. S Calculate the half-life.arrow_forwardThe following is a first order reaction where the rate constant, k, is 6.29 x 10-3 min-*** What is the half-life? C2H4 C2H2 + H2arrow_forward
- Control Chart Drawing Assignment The table below provides the number of alignment errors observed during the final inspection of a certain model of airplane. Calculate the central, upper, and lower control limits for the c-chart and draw the chart precisely on the graph sheet provided (based on 3-sigma limits). Your chart should include a line for each of the control limits (UCL, CL, and LCL) and the points for each observation. Number the x-axis 1 through 25 and evenly space the numbering for the y-axis. Connect the points by drawing a line as well. Label each line drawn. Airplane Number Number of alignment errors 201 7 202 6 203 6 204 7 205 4 206 7 207 8 208 12 209 9 210 9 211 8 212 5 213 5 214 9 215 8 216 15 217 6 218 4 219 13 220 7 221 8 222 15 223 6 224 6 225 10arrow_forwardCollagen is used to date artifacts. It has a rate constant = 1.20 x 10-4 /years. What is the half life of collagen?arrow_forwardיווי 10 20 30 40 50 60 70 3.5 3 2.5 2 1.5 1 [ppm] 3.5 3 2.5 2 1.5 1 6 [ppm] 1 1.5 -2.5 3.5arrow_forward
- General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningOrganic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,Introductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage Learning
- Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage LearningOrganic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage LearningWorld of ChemistryChemistryISBN:9780618562763Author:Steven S. ZumdahlPublisher:Houghton Mifflin College Div
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