Organic Chemistry Study Guide and Solutions
Organic Chemistry Study Guide and Solutions
6th Edition
ISBN: 9781936221868
Author: Marc Loudon, Jim Parise
Publisher: W. H. Freeman
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Chapter 19, Problem 19.7P
Interpretation Introduction

(a)

Interpretation:

The difference between 2cyclohexenone and 2cyclohexenone using UV-visible spectroscopy is to be stated.

Concept introduction:

Spectroscopy method is used to identify the structure of the molecule. It is based on the interactions between matter and electromagnetic radiations. Molecules have bonding or non-bonding electrons that can absorb light while promoting electrons from ground state (HOMO) to excited state (LUMO). The light absorbed is usually in the UV or visible region. Conjugation in molecule also affects the wavelength of light absorbed.

Interpretation Introduction

(b)

Interpretation:

The difference between the given structures using UV-visible spectroscopy is to be stated.

Concept introduction:

Spectroscopy method is used to identify the structure of the molecule. It is based on the interactions between matter and electromagnetic radiations. Molecules have bonding or non-bonding electrons that can absorb light while promoting electrons from ground state (HOMO) to excited state (LUMO). The light absorbed is usually in the UV or visible region. Conjugation in molecule also affects the wavelength of light absorbed.

Interpretation Introduction

(c)

Interpretation:

The difference between 1phenyl2propanone and pmethylacetophenone using UV-visible spectroscopy is to be stated.

Concept introduction:

Spectroscopy method is used to identify the structure of the molecule. It is based on the interactions between matter and electromagnetic radiations. Molecules have bonding or non-bonding electrons that can absorb light while promoting electrons from ground state (HOMO) to excited state (LUMO). The light absorbed is usually in the UV or visible region. Conjugation in molecule also affects the wavelength of light absorbed.

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Identify products A and B from the given 1H NMR data. Treatment of CH2=CHCOCH3 with one equivalent of HCl forms compound A. A exhibits the following absorptions in its 1H NMR spectrum: 2.2 (singlet, 3H), 3.05 (triplet, 2 H), and 3.6 (triplet, 2 H) ppm. What is the structure of A?
Compound A undergoes an acid-catalyzed hydrolysis. One of the products (B) that is isolated gives the following 1H NMR spectrum. Identify the compounds A and C
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Chapter 19 Solutions

Organic Chemistry Study Guide and Solutions

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