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(a)
Interpretation:
The given multistep synthesis by using necessary reagents is to be shown.
Concept introduction:
In the synthesis of para-butyl aniline the starting material is benzene. This on acid hydrolysis converts to
(b)
Interpretation:
The given multistep synthesis by using necessary reagents is to be shown.
Concept introduction:
The starting material for the given synthesis is a bicyclic
(c)
Interpretation:
The given multistep synthesis by using necessary reagents is to be shown.
Concept introduction:
In the given synthesis the starting material is biphenyl compound. In the compound of biphenyl two benzene rings are attached with each other by the carbon-carbon bond and with the loss of two hydrogen atoms. Biphenyl first undergoes nitration with nitric acid and sulphuric acid. Then it undergoes reduction for nitro group to amine group. Biphenyl amine reacts with ethyl chloride and converts to ethylbiphenyl amine. On further reduction and reaction with suitable reagent desired product is formed.
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Chapter 19 Solutions
Organic Chemistry (9th Edition)
- The number of noncyclic isomers that have the composition C4H8Owith the O as part of an OH group, counting a pair of stereoisomers as1, is A. 8; B. 6; C. 9; D. 5; E. None of the other answers is correct.arrow_forwardNonearrow_forwardThe number of carbon skeletons that have 8 carbons, one of which istertiary is A. 7; B. More than 7; C. 6; D. 5; E. 4arrow_forward
- The azide ion is N3^-. In addition to the ionic charge, it’s three mostimportant contributing structures also have formal charges. The totalnumber of π bonds in these three contributing structures isA. 6; B. 12; C. 3; D. 9; E. None of the other answers is correct.arrow_forwardThe sum of the numerals in the name of the compoundis A. None of the other answers is correct.; B. 11;C. 6; D. 8; E. 5.arrow_forwardA compound has a six carbon ring with three double bonds. Attachedto the ring is a three carbon chain with a triple bond and a two carbonchain with two bromines attached. The number of hydrogens in a molecule of this compound is A. 10; B. 12; C. 14; D. 13; E. None of the other answers is correct.arrow_forward
- Can you help me? I can't seem to understand the handwriting for the five problems, and I want to be able to solve them and practice. If you'd like to give me steps, please do so to make it easier understand.arrow_forwardThe number of 2sp3 hybrid orbitals in the moleculeis A. 12; B. 8; C. 3; D. 11; E. None of the other answers is correct.arrow_forwardNonearrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage LearningOrganic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning
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