Chapter 19, Problem 19.35E

Interpretation Introduction

Interpretation:

The mean free path of $\text{Ne}$ at $300.0\text{K}$ and $0.987\text{bar}$ is to be calculated.

Concept introduction:

The mean distance traveled by the same particle between two consecutive collisions is termed as mean free path. The value of the mean free path of a gas depends on the pressure and temperature of the system. The mean free path of gas is represented as,

$\lambda =\frac{kT}{\sqrt{2}\pi d^{2}p}$ …(1)

Where,

• $T$ represents the temperature.

• $d$collision diameter of a gas.

• $p$ represents the pressure.

• $k$ represents the Boltzmann constant with value $1.381\times {10}^{-23}\text{J}/\text{K}$.