General Chemistry
General Chemistry
4th Edition
ISBN: 9781891389603
Author: Donald A. McQuarrie, Peter A. Rock, Ethan B. Gallogly
Publisher: University Science Books
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Chapter 19, Problem 19.1P
Interpretation Introduction

Interpretation:

The equilibrium concentrations of [SbCl3] and [Cl2] for the given reaction, SbCl5(g)SbCl3(g) + Cl2(g) has to be calculated.

Concept Introduction:

Equilibrium constant: At equilibrium the ratio of products to reactants (each raised to the power corresponding to its stoichiometric coefficient) has a constant value, K

For a general reaction,

  aA+bBcC+dD

  EquilibriumconstantK=[C]c[D]d[A]a[B]b

The solids and pure liquids are not involved in equilibrium constant expression.

Expert Solution & Answer
Check Mark

Explanation of Solution

Given:

Antimony pentachloride decomposes according to the below equation.

  SbCl5(g)SbCl3(g) + Cl2(g)

The initial concentrations of all the reactant and products are,

  [SbCl5]0 = 0.165 M[SbCl3]0 = 0.0955 M   [Cl2]0 = 0.210 M

The concentration of [SbCl5] at equilibrium is 0.135 M.

Calculation of equilibrium concentrations:

Consider ‘x’ moles of [SbCl5] decomposes and gets converted to [SbCl3] and [Cl2] at equilibrium.

   SbCl5(g)      SbCl3(g)   +   Cl2(g)
Initial (M)0.165 M0.0955 M0.210 M
Change (M)-x+x+x
Equilibrium (M)0.165 M-x0.0955 M+x0.210 M+x

Solve for x using equilibrium concentration of [SbCl5]=0.135 M

  [SbCl5]eq     = 0.135 M0.165 M - x = 0.135 M       x   =0.165 M - 0.135 M        = 0.03 M

Now calculate the equilibrium concentrations of [SbCl3] and [Cl2] as below.

            x    = 0.03 M[SbCl3]eq=0.0955 M+x    =0.0955 M+ 0.03 M    = 0.1255 M    [Cl2]eq=0.210 M+x    =0.210 M+ 0.03 M    = 0.24 M

Therefore, the equilibrium concentrations of [SbCl3] and [Cl2] are 0.1255 M and 0.24 M respectively.

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Chapter 19 Solutions

General Chemistry

Ch. 19 - Prob. 19.11PCh. 19 - Prob. 19.12PCh. 19 - Prob. 19.13PCh. 19 - Prob. 19.14PCh. 19 - Prob. 19.15PCh. 19 - Prob. 19.16PCh. 19 - Prob. 19.17PCh. 19 - Prob. 19.18PCh. 19 - Prob. 19.19PCh. 19 - Prob. 19.20PCh. 19 - Prob. 19.21PCh. 19 - Prob. 19.22PCh. 19 - Prob. 19.23PCh. 19 - Prob. 19.24PCh. 19 - Prob. 19.25PCh. 19 - Prob. 19.27PCh. 19 - Prob. 19.28PCh. 19 - Prob. 19.29PCh. 19 - Prob. 19.30PCh. 19 - Prob. 19.31PCh. 19 - Prob. 19.32PCh. 19 - Prob. 19.33PCh. 19 - Prob. 19.34PCh. 19 - Prob. 19.35PCh. 19 - Prob. 19.36PCh. 19 - Prob. 19.37PCh. 19 - Prob. 19.38PCh. 19 - Prob. 19.39PCh. 19 - Prob. 19.40PCh. 19 - Prob. 19.43PCh. 19 - Prob. 19.44PCh. 19 - Prob. 19.45PCh. 19 - Prob. 19.46PCh. 19 - Prob. 19.47PCh. 19 - Prob. 19.48PCh. 19 - Prob. 19.49PCh. 19 - Prob. 19.50PCh. 19 - Prob. 19.51PCh. 19 - Prob. 19.52PCh. 19 - Prob. 19.53PCh. 19 - Prob. 19.54PCh. 19 - Prob. 19.55PCh. 19 - Prob. 19.56PCh. 19 - Prob. 19.57PCh. 19 - Prob. 19.58PCh. 19 - Prob. 19.59PCh. 19 - Prob. 19.60PCh. 19 - Prob. 19.61PCh. 19 - Prob. 19.62PCh. 19 - Prob. 19.63PCh. 19 - Prob. 19.64PCh. 19 - Prob. 19.65PCh. 19 - Prob. 19.66PCh. 19 - Prob. 19.67PCh. 19 - Prob. 19.68PCh. 19 - Prob. 19.69PCh. 19 - Prob. 19.70PCh. 19 - Prob. 19.71PCh. 19 - Prob. 19.72PCh. 19 - Prob. 19.73PCh. 19 - Prob. 19.74PCh. 19 - Prob. 19.75PCh. 19 - Prob. 19.76PCh. 19 - Prob. 19.77PCh. 19 - Prob. 19.78PCh. 19 - Prob. 19.79PCh. 19 - Prob. 19.80PCh. 19 - Prob. 19.81PCh. 19 - Prob. 19.82PCh. 19 - Prob. 19.83PCh. 19 - Prob. 19.84PCh. 19 - Prob. 19.86PCh. 19 - Prob. 19.91PCh. 19 - Prob. 19.92PCh. 19 - Prob. 19.93PCh. 19 - Prob. 19.94P
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