Physical Chemistry
Physical Chemistry
2nd Edition
ISBN: 9781285969770
Author: Ball
Publisher: Cengage
Question
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Chapter 19, Problem 19.18E
Interpretation Introduction

(a)

Interpretation:

The units on K by using equation 19.23 are to be determined.

Concept introduction:

The distribution of speed of gas molecules is calculated by the formula,

gx=e(1/2)Kvx2eC

The simplified form of the above equation is,

K=mkT

Interpretation Introduction

(b)

Interpretation:

The units on K by using equation 19.31 are to be determined and whether they agree with the units found in part a is to be predicted.

Concept introduction:

The distribution of speed of gas molecules is calculated by the formula,

gx=e(1/2)Kvx2eC

The simplified form of the above equation is,

K=mkT

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Chapter 19 Solutions

Physical Chemistry

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