(a) Interpretation: The balanced equation for the given reaction in basic solution should be written. Concept introduction: The half-reaction method can be used to balance the redox equation using the following steps. - Atoms that are oxidized and which are reduced should be determined. - The two unbalanced half-cell reactions are written. - Then the elements in the reaction except oxygen and hydrogen should be balanced. - Oxygen atoms are balanced by adding water molecules to the opposite side of the equation. - Hydrogen atoms are balanced by adding H + ions to the opposite side of the equation. In a basic medium, OH − ions are added to neutralize H + ions in the final step. - Charges are made equal by adding electrons to a more positive side. - The two half-reactions are multiplied by a suitable factor to equal the electron count in both half-equations. - Two balanced half-equations are added together and electrons and other common species are canceled.
(a) Interpretation: The balanced equation for the given reaction in basic solution should be written. Concept introduction: The half-reaction method can be used to balance the redox equation using the following steps. - Atoms that are oxidized and which are reduced should be determined. - The two unbalanced half-cell reactions are written. - Then the elements in the reaction except oxygen and hydrogen should be balanced. - Oxygen atoms are balanced by adding water molecules to the opposite side of the equation. - Hydrogen atoms are balanced by adding H + ions to the opposite side of the equation. In a basic medium, OH − ions are added to neutralize H + ions in the final step. - Charges are made equal by adding electrons to a more positive side. - The two half-reactions are multiplied by a suitable factor to equal the electron count in both half-equations. - Two balanced half-equations are added together and electrons and other common species are canceled.
Solution Summary: The author explains how the half-reaction method can be used to balance the redox equation using the following steps.
The balanced equation for the given reaction in basic solution should be written.
Concept introduction:
The half-reaction method can be used to balance the redox equation using the following steps.
- Atoms that are oxidized and which are reduced should be determined.
- The two unbalanced half-cell reactions are written.
- Then the elements in the reaction except oxygen and hydrogen should be balanced.
- Oxygen atoms are balanced by adding water molecules to the opposite side of the equation.
- Hydrogen atoms are balanced by adding H+ ions to the opposite side of the equation. In a basic medium, OH− ions are added to neutralize H+ ions in the final step.
- Charges are made equal by adding electrons to a more positive side.
- The two half-reactions are multiplied by a suitable factor to equal the electron count in both half-equations.
- Two balanced half-equations are added together and electrons and other common species are canceled.
Interpretation Introduction
(b)
Interpretation:
ΔG0 for the reaction obtained in part (a) should be calculated.
Concept introduction:
The standard Gibbs free energy change can be calculated as follows:
ΔG0=−nFE0ΔG0= Standard Gibbs free energyn = number of moles of electrons transferredF = Faraday constantE0= Standard cell potential
b) Certain cyclic compounds are known to be conformationally similar to carbohydrates, although they are not
themselves carbohydrates. One example is Compound C shown below, which could be imagined as adopting
four possible conformations. In reality, however, only one of these is particularly stable. Circle the conformation
you expect to be the most stable, and provide an explanation to justify your choice. For your explanation to be
both convincing and correct, it must contain not only words, but also "cartoon" orbital drawings contrasting the
four structures.
Compound C
Possible conformations (circle one):
Дет
Lab Data
The distance entered is out of the expected range.
Check your calculations and conversion factors.
Verify your distance. Will the gas cloud be closer to the cotton ball with HCI or NH3?
Did you report your data to the correct number of significant figures?
- X
Experimental Set-up
HCI-NH3
NH3-HCI
Longer Tube
Time elapsed (min)
5 (exact)
5 (exact)
Distance between cotton balls (cm)
24.30
24.40
Distance to cloud (cm)
9.70
14.16
Distance traveled by HCI (cm)
9.70
9.80
Distance traveled by NH3 (cm)
14.60
14.50
Diffusion rate of HCI (cm/hr)
116
118
Diffusion rate of NH3 (cm/hr)
175.2
175.2
How to measure distance and calculate rate
For the titration of a divalent metal ion (M2+) with EDTA, the stoichiometry of the reaction is typically:
1:1 (one mole of EDTA per mole of metal ion)
2:1 (two moles of EDTA per mole of metal ion)
1:2 (one mole of EDTA per two moles of metal ion)
None of the above
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
The Laws of Thermodynamics, Entropy, and Gibbs Free Energy; Author: Professor Dave Explains;https://www.youtube.com/watch?v=8N1BxHgsoOw;License: Standard YouTube License, CC-BY