EBK GENERAL CHEMISTRY: THE ESSENTIAL CO
EBK GENERAL CHEMISTRY: THE ESSENTIAL CO
7th Edition
ISBN: 9780100257047
Author: Chang
Publisher: YUZU
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Chapter 19, Problem 19.126SP

(a)

Interpretation Introduction

Interpretation:

The total charge consumed for completion of electrolysis has to be calculated.

Concept Introduction:

  • The amount of electrical charge that is passing through a circuit depends upon the amount and time of the flow of current.  The electrical charge is measured in Coulomb.

  Q=It

  Where,

  Q is the charge in Coulomb

  I is the current in Ampere

  t is the time in second

  • Mole is the mass of the substance that is having Avogadro number of particles.  The number of moles of a given substance can be calculated by dividing its weight to molecular weight.
  • Faradays First law of electrolysis says that the quantity of substance deposited on an electrode is proportional to the charge passed through the solution.

    m = Z×Q

    Where,

    m is the amount of substance liberated

    Q is the quantity of charge passed

    Z is the electrochemical equivalence of the substance

  • Ideal gas equation is an equation that is describing the state of a imaginary ideal gas.

    PV=n RT

    Where,

    P is the pressure of the gas

    V is the volume

    n is the number of moles of gas

    R is the universal gas constant (R=0.0821LatmK-1mol-1)

    T is the temperature

(b)

Interpretation Introduction

Interpretation:

The time required for completion of electrolysis has to be calculated.

Concept Introduction:

  • The amount of electrical charge that is passing through a circuit depends upon the amount and time of the flow of current.  The electrical charge is measured in Coulomb.

  Q=It

  Where,

  Q is the charge in Coulomb

  I is the current in Ampere

  t is the time in second

  • Mole is the mass of the substance that is having Avogadro number of particles.  The number of moles of a given substance can be calculated by dividing its weight to molecular weight.
  • Faradays First law of electrolysis says that the quantity of substance deposited on an electrode is proportional to the charge passed through the solution.

    m = Z×Q

    Where,

    m is the amount of substance liberated

    Q is the quantity of charge passed

    Z is the electrochemical equivalence of the substance

  • Ideal gas equation is an equation that is describing the state of a imaginary ideal gas.

    PV=n RT

    Where,

    P is the pressure of the gas

    V is the volume

    n is the number of moles of gas

    R is the universal gas constant (R=0.0821LatmK-1mol-1)

    T is the temperature

(c)

Interpretation Introduction

Interpretation:

The amount of Mg(OH)2 formed has to be calculated.

Concept Introduction:

  • The amount of electrical charge that is passing through a circuit depends upon the amount and time of the flow of current.  The electrical charge is measured in Coulomb.

  Q=It

  Where,

  Q is the charge in Coulomb

  I is the current in Ampere

  t is the time in second

  • Mole is the mass of the substance that is having Avogadro number of particles.  The number of moles of a given substance can be calculated by dividing its weight to molecular weight.
  • Faradays First law of electrolysis says that the quantity of substance deposited on an electrode is proportional to the charge passed through the solution.

    m = Z×Q

    Where,

    m is the amount of substance liberated

    Q is the quantity of charge passed

    Z is the electrochemical equivalence of the substance

  • Ideal gas equation is an equation that is describing the state of a imaginary ideal gas.

    PV=n RT

    Where,

    P is the pressure of the gas

    V is the volume

    n is the number of moles of gas

    R is the universal gas constant (R=0.0821LatmK-1mol-1)

    T is the temperature

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Chapter 19 Solutions

EBK GENERAL CHEMISTRY: THE ESSENTIAL CO

Ch. 19.5 - Prob. 2PECh. 19.5 - Prob. 1RCCh. 19.7 - Prob. 1RCCh. 19.8 - Prob. 1RCCh. 19.8 - An aqueous solution of Mg(NO3)2 is electrolyzed....Ch. 19.8 - Prob. 2RCCh. 19.8 - Prob. 2PECh. 19.8 - Prob. 3RCCh. 19 - Prob. 19.1QPCh. 19 - Prob. 19.2QPCh. 19 - Prob. 19.3QPCh. 19 - Prob. 19.4QPCh. 19 - Prob. 19.5QPCh. 19 - Prob. 19.6QPCh. 19 - 19.7 What is the difference between the...Ch. 19 - Prob. 19.8QPCh. 19 - Prob. 19.9QPCh. 19 - Prob. 19.10QPCh. 19 - Prob. 19.11QPCh. 19 - Prob. 19.12QPCh. 19 - Prob. 19.13QPCh. 19 - 19.14 Which of the following reagents can oxidize...Ch. 19 - 19.15 Consider the following half-reactions: (aq)...Ch. 19 - 19.16 Predict whether the following reactions...Ch. 19 - Prob. 19.17QPCh. 19 - Prob. 19.18QPCh. 19 - Prob. 19.19QPCh. 19 - Prob. 19.20QPCh. 19 - Prob. 19.21QPCh. 19 - Prob. 19.22QPCh. 19 - Prob. 19.23QPCh. 19 - Prob. 19.24QPCh. 19 - Prob. 19.25QPCh. 19 - Prob. 19.26QPCh. 19 - Prob. 19.27QPCh. 19 - Prob. 19.28QPCh. 19 - Prob. 19.29QPCh. 19 - Prob. 19.30QPCh. 19 - Prob. 19.31QPCh. 19 - Prob. 19.33QPCh. 19 - Prob. 19.34QPCh. 19 - 19.35 Explain the differences between a primary...Ch. 19 - Prob. 19.36QPCh. 19 - Prob. 19.37QPCh. 19 - Prob. 19.38QPCh. 19 - Prob. 19.39QPCh. 19 - Prob. 19.40QPCh. 19 - Prob. 19.41QPCh. 19 - Prob. 19.42QPCh. 19 - 19.43 What is the difference between a galvanic...Ch. 19 - Prob. 19.44QPCh. 19 - Prob. 19.45QPCh. 19 - Prob. 19.46QPCh. 19 - Prob. 19.47QPCh. 19 - Prob. 19.48QPCh. 19 - Prob. 19.49QPCh. 19 - Prob. 19.50QPCh. 19 - 19.51 Calculate the amounts of Cu and Br2 produced...Ch. 19 - Prob. 19.52QPCh. 19 - Prob. 19.53QPCh. 19 - Prob. 19.54QPCh. 19 - 19.55 What is the hourly production rate of...Ch. 19 - Prob. 19.56QPCh. 19 - Prob. 19.57QPCh. 19 - Prob. 19.58QPCh. 19 - Prob. 19.59QPCh. 19 - Prob. 19.60QPCh. 19 - Prob. 19.61QPCh. 19 - Prob. 19.62QPCh. 19 - Prob. 19.63QPCh. 19 - Prob. 19.64QPCh. 19 - Prob. 19.65QPCh. 19 - 19.66 A sample of iron ore weighing 0.2792 g was...Ch. 19 - Prob. 19.67QPCh. 19 - Prob. 19.68QPCh. 19 - Prob. 19.69QPCh. 19 - Prob. 19.70QPCh. 19 - Prob. 19.71QPCh. 19 - Prob. 19.72QPCh. 19 - Prob. 19.73QPCh. 19 - Prob. 19.74QPCh. 19 - Prob. 19.75QPCh. 19 - Prob. 19.76QPCh. 19 - Prob. 19.77QPCh. 19 - Prob. 19.78QPCh. 19 - Prob. 19.79QPCh. 19 - Prob. 19.80QPCh. 19 - Prob. 19.81QPCh. 19 - Prob. 19.82QPCh. 19 - Prob. 19.83QPCh. 19 - Prob. 19.84QPCh. 19 - Prob. 19.86QPCh. 19 - Prob. 19.87QPCh. 19 - Prob. 19.88QPCh. 19 - Prob. 19.89QPCh. 19 - Prob. 19.90QPCh. 19 - Prob. 19.91QPCh. 19 - Prob. 19.92QPCh. 19 - Prob. 19.93QPCh. 19 - Prob. 19.94QPCh. 19 - Prob. 19.95QPCh. 19 - Prob. 19.96QPCh. 19 - Prob. 19.97QPCh. 19 - Prob. 19.98QPCh. 19 - Prob. 19.99QPCh. 19 - Prob. 19.100QPCh. 19 - Prob. 19.101QPCh. 19 - 19.102 The magnitudes (but not the signs) of the...Ch. 19 - Prob. 19.103QPCh. 19 - Prob. 19.104QPCh. 19 - Prob. 19.105QPCh. 19 - Prob. 19.106QPCh. 19 - Prob. 19.107QPCh. 19 - Prob. 19.108QPCh. 19 - Prob. 19.109QPCh. 19 - Prob. 19.110QPCh. 19 - 19.111 A spoon was silver-plated electro lyrically...Ch. 19 - Prob. 19.112QPCh. 19 - Prob. 19.113QPCh. 19 - Prob. 19.114QPCh. 19 - Prob. 19.115QPCh. 19 - Prob. 19.116QPCh. 19 - Prob. 19.117QPCh. 19 - Prob. 19.118QPCh. 19 - Prob. 19.119QPCh. 19 - Prob. 19.120QPCh. 19 - Prob. 19.121SPCh. 19 - Prob. 19.122SPCh. 19 - Prob. 19.123SPCh. 19 - Prob. 19.124SPCh. 19 - Prob. 19.125SPCh. 19 - Prob. 19.126SPCh. 19 - Prob. 19.128SPCh. 19 - Prob. 19.129SPCh. 19 - Prob. 19.130SP
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