Explanation The magnetic field due to the left-hand current to B → L and the due to the right-hand current to B → R . Write the expression for the magnetic field due to a straight wire. B = μ 0 I 2 π r (I) Here, B is the magnetic field, μ 0 is the permeability of free space, I is the current, r is the distance of the point of observation to the straight wire. According to the right hand rule, the magnetic fields are shown in figure 1 . Since the triangle is equilateral, the value of angle θ = 60 ° . The angle ϕ is 90 ° − 60 ° = 30 ° . Due to the symmetry, the vertical components of the magnetic field gets cancel each other and the horizontal components add, so the net magnetic field is directed in the positive x axis. The magnitude of both the magnetic fields are same because same amount of current is passing through each wire. Write the expression for the net magnetic field in the third corner of the triangle. B net = 2 ( μ 0 I 2 π r ) cos ϕ (II) Substitute 4 π × 10 − 7 T ⋅ m / A for μ 0 , 12.0 A for I , 2.50 cm for r , 30 ° for ϕ in equation (II) to find B net . B net = 2 [ ( 4 π × 10 − 7 T ⋅ m / A ) ( 12.0 A ) 2 π ( 2.50 cm × 10 − 2 m 1 cm ) ] cos 30 ° = 2 [ ( 4 π × 10 − 7 T ⋅ m / A ) ( 12.0 A ) 2 π ( 2.50 cm × 10 − 2 m 1 cm ) ] ( 3 2 ) = 1

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ISBN: 9781260486919

Author: GIAMBATTISTA

Publisher: MCG

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Chapter 19, Problem 116P

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The current in the wire to make it hover above the other two.

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Chapter 19, Problem 117P

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The current in the wire to make it hover above the other two.

Solution Summary: The author explains the magnetic field due to the left-hand current to stackrelto B_L and the right-handed current.

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The current in the wire to make it hover above the other two.

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