Biology: The Dynamic Science (MindTap Course List)
4th Edition
ISBN: 9781305389892
Author: Peter J. Russell, Paul E. Hertz, Beverly McMillan
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
Chapter 19, Problem 10TYK
When two protein-coding genes have very similar
a. one of them is a duplicate of the other, copied by aretrotransposon.
b. they are nonhomologous.
c. one of them is a pseudogene.
d. they were produced by unequal crossing-over.
e. they are transcribed in the same cell types.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
For each statement below indicate whether it is true or false.
A. Introns are transcribed regions that are not removed in RNA processing.
B. In paracentric inversions, centromeres are contained within inverted chromosome segments.
C. A base substitution that results in an A being switched to a T would be referred to as a transition.
The origin of genes that have new functions often involves the divergence of gene duplicates.Duplicates can arise via several mechanisms. a. One mechanism of gene duplication is retrotransposition, the insertion into the genome of DNA produced by reverse transcription of a messenger RNA. These gene duplicates are often dead on arrival: they are pseudogenes as soon as they are formed. Why are such duplicates so often dead on arrival? b. A second mechanism of gene duplication occurs via unequal crossing over during meiosis. Gene duplicates formed this way are functional more often than when they arise by reverse transcription. Why is that? c. If a gene duplicate is initially functional, what are its possible ultimate fates? Which is most likely,and why?
A researcher has identified a mutant strain of yeast whose histones are unable to be acetylated. Which of the following is the MOST reasonable prediction for how the phenotype of this mutant yeast will differ from the phenotype of yeast cells with acetylated histones?
A. The mutant will grow more rapidly.
B. The mutant will grow much more slowly.
C. The mutant will show decreased levels of gene expression.
D. The mutant will show increased levels of gene expression.
Chapter 19 Solutions
Biology: The Dynamic Science (MindTap Course List)
Ch. 19.1 - What additional biological questions can be...Ch. 19.2 - What is the principle behind whole-genome shotgun...Ch. 19.2 - Prob. 2SBCh. 19.2 - Prob. 3SBCh. 19.2 - Prob. 4SBCh. 19.3 - Prob. 1SBCh. 19.3 - Prob. 2SBCh. 19.3 - Prob. 3SBCh. 19.4 - Prob. 1SBCh. 19.4 - Prob. 2SB
Ch. 19 - Prob. 1TYKCh. 19 - How do pseudogenes differ from genes? a. They are...Ch. 19 - Prob. 3TYKCh. 19 - Prob. 4TYKCh. 19 - Prob. 5TYKCh. 19 - Prob. 6TYKCh. 19 - About 95% of the average human transcription unit...Ch. 19 - Prob. 8TYKCh. 19 - Prob. 9TYKCh. 19 - When two protein-coding genes have very similar...Ch. 19 - Prob. 11TYKCh. 19 - Prob. 12TYKCh. 19 - Prob. 13TYKCh. 19 - Discuss Concepts The genome of the yeast...Ch. 19 - Prob. 15TYKCh. 19 - Prob. 16TYKCh. 19 - Prob. 17TYKCh. 19 - Below is a sequence of 540 bases from a genome....
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- With regard to gene duplications, which of the following statement(s) is/are correct?a. Gene duplications may be caused by nonallelic homologousrecombination.b. Large gene duplications are more likely to be harmful thansmaller ones.c. Gene duplications are responsible for creating gene familiesthat encode proteins with similar and specialized functions.d. All of the above statements are correct.arrow_forwardDefine the following terms: a. histone b. heterochromatin c. spermine d. intergenic sequences e. tandem repeatsarrow_forwardWhat did the Hershey / Chase experiments (above) demonstrate about the molecules responsible for genetic inheritance patterns in the T2 bacteriophage? A. the genetic material consists of carbohydrates, not RNA B. the genetic material consists of protein, not lipids C. the genetic material consists of DNA, not polypeptides D. the genetic material consists of protein, not DNA E. the genetic material consists of lipids, not polypeptidesarrow_forward
- In the lab, you discover two yeast haploid mutants that cannot produce arginine. You cross them together and the resulting diploid produces arginine. If producing arginine is the wild type phenotype, what can you definitively conclude? A.The haploid strains have identical mutations in the same genes. B.The haploid strains have identical mutations in different genes. C.The haploid strains have mutations in different genes. D.The haploid strains have mutations in the same gene. E.The haploid strains must belong to the complementation group encoding the first enzyme in the biosynthetic pathway.arrow_forwardPax-6 is a gene that is involved in eye formation in many invertebrates, such as Drosophila. Pax-6 is also found in vertebrates. A Pax-6 gene from a mouse can be expressed in a fly and the protein (PAX-6) leads to a compound fly eye. This information suggests which of the following? a. PAX-6 proteins have identical amino acid sequencesb. Pax-6 genes are identical in nucleotide sequencec. PAX-6 proteins are different for formation of different kinds of eyesd. Pax-6 is highly conserved and shows shared evolutionary ancestryarrow_forward1a) Why is it possible for you to study the eye colour gene by extracting cheek cells? a. Because the nucleus of every cell in the human body contains the same genetic information. b. Because the cheek cells are located near the cells of the eye and so they are able to exchange DNA. c. Because all genes in the human body are expressed at all times so it is easy to study them. d. All of the above are possible explanations. 1b) What is the purpose of heating the sample to 75°C following addition of the 0.2M NaOH solution? a. To denature the histone proteins that are keeping the DNA tightly coiled. b. To ensure that all the DNA is removed from the swab in preparation for PCR. c. To breakdown the cheek cell membrane to release the DNA from the cell. d. It breaks down the circular DNA down into linear fragments so that they will be easier to visualize.iarrow_forward
- Suppose that you are studying the role of Protein B, which you believe plays a role in regulating PCD/Apoptosis in mice. You create two lines of mutant mice. One (bb) is homozygous for a loss-of-function allele of gene B. The other (Bb) is heterozygous, with one wild-type allele and one loss-of function allele. Initially you pay particular attention to two phenotypes of the resulting mice:(i) The morphology of their paws (see picture)(ii) The size of their brains & shape of their skulls. The bb mice have unusually large brains and unusual protrusions from their skulls. Suggest one other aspect of mouse morphology or physiology that you might expect to be altered in the absence of Protein B. Briefly explain your reasoning. Also, based on the apparent effect of Protein B on the likelihood of PCD/Apoptosis, would you classify Protein B as the product of a proto-oncogene or of a tumor suppressor gene?arrow_forwardSuppose that you are studying the role of Protein B, which you believe plays a role in regulating PCD/Apoptosis in mice. You create two lines of mutant mice. One (bb) is homozygous for a loss-of-function allele of gene B. The other (Bb) is heterozygous, with one wild-type allele and one loss-of function allele. Initially you pay particular attention to two phenotypes of the resulting mice:(i) The morphology of their paws (see picture) (ii) The size of their brains & shape of their skulls. The bb mice have unusually large brains and unusual protrusions from their skulls. Based on these data, does it appear that Protein B, when present and active, favors or inhibits PCD/Apoptosis?Briefly explain your reasoning. The answer should address both the paw and brain/skull data.arrow_forwardA cell is homozygous for a LOF mutation in the histone acetyltransferase (HAT) gene. Which of the following is/are true? a. Chromatin in the cell will be more condensed than usual, decreasing expression of genes that should be expressed. b. This will lead to histones with more positive charges on their tails, increasing the interaction between histones and the DNA backbone. c. This will lead to a decrease in DNA methylation and therefore cause an increase in gene expression. d. Chromatin in the cell will be less condensed than usual, increasing expression of genes that should not be expressed.arrow_forward
- For each statement below indicate whether it is true or false. A. Assume that a species has a diploid chromosome number of 24. The term applied to an individual with 25 chromosomes would be aneuploid. B. 5’GGATTC3’ is the consensus sequence of the -35 regulatory region of prokaryotic genes. C. The chromosomes in the image illustrate a reciprocal translocation:arrow_forwardDefine the following terms:a. histonesb. heterochromatinc. euchromatind. intergenic sequencese. tandem repeatsarrow_forwardThe case of golden labs in which a mutation in a gene for the pigment transport protein results in a lack of pigment (the golden color) instead of the brown or black the results from the actual pigment genes, is an example of... Select one: a. multiple alleles b. epistasis c. genomic imprinting d. altered methylationarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Human Anatomy & Physiology (11th Edition)BiologyISBN:9780134580999Author:Elaine N. Marieb, Katja N. HoehnPublisher:PEARSON
Biology 2eBiologyISBN:9781947172517Author:Matthew Douglas, Jung Choi, Mary Ann ClarkPublisher:OpenStax
Anatomy & PhysiologyBiologyISBN:9781259398629Author:McKinley, Michael P., O'loughlin, Valerie Dean, Bidle, Theresa StouterPublisher:Mcgraw Hill Education,
Molecular Biology of the Cell (Sixth Edition)BiologyISBN:9780815344322Author:Bruce Alberts, Alexander D. Johnson, Julian Lewis, David Morgan, Martin Raff, Keith Roberts, Peter WalterPublisher:W. W. Norton & Company
Laboratory Manual For Human Anatomy & PhysiologyBiologyISBN:9781260159363Author:Martin, Terry R., Prentice-craver, CynthiaPublisher:McGraw-Hill Publishing Co.
Inquiry Into Life (16th Edition)BiologyISBN:9781260231700Author:Sylvia S. Mader, Michael WindelspechtPublisher:McGraw Hill Education
Human Anatomy & Physiology (11th Edition)
Biology
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:PEARSON
Biology 2e
Biology
ISBN:9781947172517
Author:Matthew Douglas, Jung Choi, Mary Ann Clark
Publisher:OpenStax
Anatomy & Physiology
Biology
ISBN:9781259398629
Author:McKinley, Michael P., O'loughlin, Valerie Dean, Bidle, Theresa Stouter
Publisher:Mcgraw Hill Education,
Molecular Biology of the Cell (Sixth Edition)
Biology
ISBN:9780815344322
Author:Bruce Alberts, Alexander D. Johnson, Julian Lewis, David Morgan, Martin Raff, Keith Roberts, Peter Walter
Publisher:W. W. Norton & Company
Laboratory Manual For Human Anatomy & Physiology
Biology
ISBN:9781260159363
Author:Martin, Terry R., Prentice-craver, Cynthia
Publisher:McGraw-Hill Publishing Co.
Inquiry Into Life (16th Edition)
Biology
ISBN:9781260231700
Author:Sylvia S. Mader, Michael Windelspecht
Publisher:McGraw Hill Education
Mitochondrial mutations; Author: Useful Genetics;https://www.youtube.com/watch?v=GvgXe-3RJeU;License: CC-BY