Chapter 18.4, Problem 52SSC

Interpretation Introduction

Interpretation:

The molarity of solution of hydrobromic acid when it is titrated with sodium hydroxide is to be calculated.

Concept introduction:

At equivalence point,

Moles of hydrogen ions from acid = moles of hydroxyl ions from base

Answer to Problem 52SSC

Molarity of $HBr=0.121M$

Explanation of Solution

Given data:

$\begin{array}{l}{V}_{NaOH}=30.35mL\\ MolarityofNaOH=0.1M\\ V_{HBr}=25mL\end{array}$

Therefore,

$\begin{array}{c}{n}_{NaOH}=0.1\times \frac{30.35}{1000}\\ =0.003035\end{array}$

So, $n_{HBr}=0.003035$

$\begin{array}{c}MolarityofHBr=\frac{0.003035}{25/1000}\\ =0.121M\end{array}$

Conclusion

Molarity = $0.121M$