Chapter 18, Problem 91A

Interpretation Introduction

(a)

Interpretation:

The formula equation and the net ionic equation for the hydrolysis of given salt is to be written.

Concept introduction:

On adding a salt in water, it dissociates into its ions due to polarity of water.

Cationic part of salt is clustered by hydroxyl ions and anionic part is clustered by hydrogen ions due to electrostatic force of attractions.

Answer to Problem 91A

Formula equation:

$N{a}_{2}C{O}_3+H_{2}O\to NaOH+NaHC{O}_3$

Net ionic equation:

$C{O}_3{}^{2-}+H_{2}O\to O{H}^{-}+HC{O}_3{}^{-}$

Explanation of Solution

Formula equation can be written as:

$N{a}_{2}C{O}_3+H_{2}O\to NaOH+NaHC{O}_3$

To write net ionic equation, spectator ion is removed from the equation.

Net ionic equation:

$C{O}_3{}^{2-}+H_{2}O\to O{H}^{-}+HC{O}_3{}^{-}$

Interpretation Introduction

(b)

Interpretation:

The formula equation and the net ionic equation for the hydrolysis of given salt is to be written.

Concept introduction:

On adding a salt in water, it dissociates into its ions due to polarity of water.

Cationic part of salt is clustered by hydroxyl ions and anionic part is clustered by hydrogen ions due to electrostatic force of attractions.

Answer to Problem 91A

Formula equation:

$N{H}_{4}Br+H_{2}O\to HBr+N{H}_3$

Net ionic equation:

$N{H}_4{}^{+}+H_{2}O\to H_3{O}^{+}+N{H}_3$

Explanation of Solution

Formula equation can be written as:

$N{H}_{4}Br+H_{2}O\to HBr+N{H}_3$

To write net ionic equation, spectator ion is removed from the equation.

Net ionic equation:

$N{H}_4{}^{+}+H_{2}O\to H_3{O}^{+}+N{H}_3$