Chapter 18, Problem 14STP

Interpretation Introduction

Interpretation:

The procedure for preparing $0.50Mand0.50m$ aqueous solution of $NaOH$ in lab is to be described.

Concept introduction:

Molarity is number of moles of solute dissolved in one litre of solution.

Molality is the number of moles of solute dissolved in one kg of solvent.

Answer to Problem 14STP

$0.50M$ aqueous solution of $NaOH$ is formed by dissolving $0.50moles$ of $NaOH$ in one litre solution.

$0.50m$ aqueous solution of $NaOH$ is formed by dissolving $0.50moles$ of $NaOH$ in one litre water.

Explanation of Solution

To make $0.50M$ aqueous solution of $NaOH$, the mass of $0.50moles$ of $NaOH$ is to be calculated. Then dissolve it in small amount of water by adding in one litre volumetric flask. Then completing the volume upto one litre mark and making the solution uniform by swirling it.

To make $0.50m$ aqueous solution of $NaOH$, the mass of $0.50moles$ of $NaOH$ is to be calculated. Then dissolve it in small amount of water. Then completing the volume to one litre which is equivalent to one kg water and making the solution uniform by swirling it.

Conclusion

$0.50M$ aqueous solution of $NaOH$ is formed by dissolving $0.50moles$ of $NaOH$ in one litre solution.

$0.50m$ aqueous solution of $NaOH$ is formed by dissolving $0.50moles$ of $NaOH$ in one litre water.