Business Math (11th Edition)
11th Edition
ISBN: 9780134496436
Author: Cheryl Cleaves, Margie Hobbs, Jeffrey Noble
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 18.1, Problem 5-3SC
To determine
To calculate: The Ending inventory at cost and the cost of goods sold using the retail inventory method if sales total $7606.70 and to complete the following table,
| Date of purchase | Number of book bags purchased | Cost per unit | Ending inventory | Retail value of goods available for sale |
| February 1 | 389 | $7 | 117 | $3948.35 |
| February 12 | 400 | $6 | 89 | $3480 |
| February 25 | 200 | $9 | 36 | $2610 |
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Please use the infinite series formula and specify how you did each step. Thank you.
In a small office, there are m = 5 typists who need to use a single typewriter to complete their reports. Assume the time
each typist takes to prepare a report follows an exponential distribution with an average of 20 minutes per preparation
(A = 3 reports/hour), and the service time for the typewriter to type out a report also follows an exponential distribution,
averaging 30 minutes to complete a report (μ 2 reports/hour). Given that the number of typists is finite and all typists
=
share one typewriter, they will form a waiting queue.
(1). Describe this queuing system and explain how it fits the characteristics of the M/M/1/∞0/m model.
(2). Calculate the probability that any typist is using the typewriter at steady-state.
(3). Calculate the average number of typists waiting in the queue at steady-state.
(4). Considering the need to reduce waiting time, if an additional typewriter is introduced (turning into a two-server
system, or M/M/2/∞0/m model), analyze the expected impact,…
Use Laplace transform to solve the initial value problem
y' + y = tsin(t), y(0) = 0
Chapter 18 Solutions
Business Math (11th Edition)
Ch. 18.1 - Prob. 1-1SCCh. 18.1 - Prob. 1-2SCCh. 18.1 - Prob. 1-3SCCh. 18.1 - Prob. 1-4SCCh. 18.1 - Prob. 2-1SCCh. 18.1 - Prob. 2-2SCCh. 18.1 - Prob. 2-3SCCh. 18.1 - Prob. 2-4SCCh. 18.1 - Prob. 3-1SCCh. 18.1 - Prob. 3-2SC
Ch. 18.1 - Prob. 3-3SCCh. 18.1 - Prob. 3-4SCCh. 18.1 - Prob. 4-1SCCh. 18.1 - Prob. 4-2SCCh. 18.1 - Prob. 4-3SCCh. 18.1 - Prob. 4-4SCCh. 18.1 - Prob. 5-1SCCh. 18.1 - Prob. 5-2SCCh. 18.1 - Prob. 5-3SCCh. 18.1 - Prob. 5-4SCCh. 18.1 - Prob. 6-1SCCh. 18.1 - Prob. 6-2SCCh. 18.1 - Prob. 6-3SCCh. 18.1 - Prob. 6-4SCCh. 18.1 - Prob. 6-5SCCh. 18.1 - Prob. 1SECh. 18.1 - Prob. 2SECh. 18.1 - Prob. 3SECh. 18.1 - Prob. 4SECh. 18.1 - Prob. 5SECh. 18.1 - Prob. 6SECh. 18.1 - Prob. 7SECh. 18.1 - Prob. 8SECh. 18.1 - Prob. 9SECh. 18.1 - Prob. 10SECh. 18.1 - Prob. 11SECh. 18.1 - Prob. 12SECh. 18.1 - Prob. 13SECh. 18.1 - Prob. 14SECh. 18.1 - Prob. 15SECh. 18.1 - Prob. 16SECh. 18.1 - Prob. 17SECh. 18.1 - Prob. 18SECh. 18.1 - Prob. 19SECh. 18.1 - Prob. 20SECh. 18.1 - Prob. 21SECh. 18.1 - Prob. 22SECh. 18.1 - Prob. 23SECh. 18.1 - Prob. 24SECh. 18.1 - Prob. 25SECh. 18.1 - Prob. 26SECh. 18.1 - Prob. 27SECh. 18.1 - Prob. 28SECh. 18.1 - Prob. 29SECh. 18.2 - Prob. 1-1SCCh. 18.2 - Prob. 1-2SCCh. 18.2 - Prob. 1-3SCCh. 18.2 - Prob. 1-4SCCh. 18.2 - Prob. 2-1SCCh. 18.2 - Prob. 2-2SCCh. 18.2 - Prob. 2-3SCCh. 18.2 - Prob. 2-4SCCh. 18.2 - Prob. 1SECh. 18.2 - Prob. 2SECh. 18.2 - Prob. 3SECh. 18.2 - Prob. 4SECh. 18.2 - Prob. 5SECh. 18.2 - Prob. 6SECh. 18.2 - Prob. 7SECh. 18.2 - Prob. 8SECh. 18.2 - Prob. 9SECh. 18.2 - Prob. 10SECh. 18 - Prob. 1ESCh. 18 - Prob. 2ESCh. 18 - Prob. 3ESCh. 18 - Prob. 4ESCh. 18 - Prob. 5ESCh. 18 - Prob. 6ESCh. 18 - Prob. 7ESCh. 18 - Prob. 8ESCh. 18 - Prob. 9ESCh. 18 - Prob. 10ESCh. 18 - Prob. 11ESCh. 18 - Prob. 12ESCh. 18 - Prob. 13ESCh. 18 - Prob. 14ESCh. 18 - Prob. 16ESCh. 18 - Prob. 17ESCh. 18 - Prob. 18ESCh. 18 - Prob. 19ESCh. 18 - Prob. 20ESCh. 18 - Prob. 21ESCh. 18 - Prob. 22ESCh. 18 - Prob. 23ESCh. 18 - Prob. 24ESCh. 18 - Prob. 25ESCh. 18 - Prob. 26ESCh. 18 - Prob. 27ESCh. 18 - Prob. 1PTCh. 18 - Prob. 2PTCh. 18 - Prob. 3PTCh. 18 - Prob. 4PTCh. 18 - Prob. 5PTCh. 18 - Prob. 6PTCh. 18 - Prob. 7PTCh. 18 - Prob. 8PTCh. 18 - Prob. 9PTCh. 18 - Prob. 10PTCh. 18 - Prob. 11PTCh. 18 - Prob. 12PTCh. 18 - Prob. 13PTCh. 18 - Prob. 14PTCh. 18 - Prob. 15PTCh. 18 - Prob. 16PTCh. 18 - Prob. 1CTCh. 18 - Prob. 2CTCh. 18 - Prob. 3CTCh. 18 - Prob. 4CTCh. 18 - Prob. 5CTCh. 18 - Prob. 6CTCh. 18 - Prob. 7CTCh. 18 - Prob. 8CTCh. 18 - Prob. 9CTCh. 18 - Prob. 1CPCh. 18 - Prob. 2CPCh. 18 - Prob. 1CS1Ch. 18 - Prob. 2CS1Ch. 18 - Prob. 3CS1Ch. 18 - Prob. 1CS2Ch. 18 - Prob. 2CS2
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, subject and related others by exploring similar questions and additional content below.Similar questions
- The function g is defined by g(x) = sec² x + tan x. What are all solutions to g(x) = 1 on the interval 0 ≤ x ≤ 2π ? A x = = 0, x == = 3, x = π, x = 7 4 , 4 and x 2π only = B x = 4' 1, x = 1, x = 57 and x = 3 only C x = πk and x = - +πk D , where is any integer П x = +πk and П x = +πk, where k is any integerarrow_forwardBusiness discussarrow_forwardVector v = PQ has initial point P (2, 14) and terminal point Q (7, 3). Vector v = RS has initial point R (29, 8) and terminal point S (12, 17). Part A: Write u and v in linear form. Show all necessary work. Part B: Write u and v in trigonometric form. Show all necessary work. Part C: Find 7u − 4v. Show all necessary calculations.arrow_forward
- An object is suspended by two cables attached at a single point. The force applied on one cable has a magnitude of 125 pounds and acts at an angle of 37°. The force on the other cable is 75 pounds at an angle of 150°.Part A: Write each vector in component form. Show all necessary work.Part B: Find the dot product of the vectors. Show all necessary calculations Part C: Use the dot product to find the angle between the cables. Round the answer to the nearest degree. Show all necessary calculations.arrow_forwardAn airplane flies at 500 mph with a direction of 135° relative to the air. The plane experiences a wind that blows 60 mph with a direction of 60°.Part A: Write each of the vectors in linear form. Show all necessary calculations.Part B: Find the sum of the vectors. Show all necessary calculations. Part C: Find the true speed and direction of the airplane. Round the speed to the thousandths place and the direction to the nearest degree. Show all necessary calculations.arrow_forwardUse sigma notation to write the sum. Σ EM i=1 - n 2 4n + n narrow_forward
- Vectors t = 3i + 7j, u = 2i − 5j, and v = −21i + 9j are given.Part A: Find the angle between vectors t and u. Show all necessary calculations. Part B: Choose a value for c, such that c > 1. Find w = cv. Show all necessary work.Part C: Use the dot product to determine if t and w are parallel, orthogonal, or neither. Justify your answer.arrow_forwardKindly inform what is bottling?arrow_forwardBusiness discussarrow_forward
- 8) Solve the given system using the Gaussian Elimination process. 2x8y = 3 (-6x+24y = −6arrow_forwardA small company of science writers found that its rate of profit (in thousands of dollars) after t years of operation is given by P'(t) = (5t + 15) (t² + 6t+9) ³. (a) Find the total profit in the first three years. (b) Find the profit in the sixth year of operation. (c) What is happening to the annual profit over the long run? (a) The total profit in the first three years is $ (Round to the nearest dollar as needed.)arrow_forwardI just need to know why this is wrong below: What is the test statistic W? W=5 (incorrect) and What is the p-value of this test? (p-value < 0.001-- incorrect) Use the Wilcoxon signed rank test to test the hypothesis that the median number of pages in the statistics books in the library from which the sample was taken is 400. A sample of 12 statistics books have the following numbers of pages pages 127 217 486 132 397 297 396 327 292 256 358 272 What is the sum of the negative ranks (W-)? 75 What is the sum of the positive ranks (W+)? 5What type of test is this? two tailedWhat is the test statistic W? 5 These are the critical values for a 1-tailed Wilcoxon Signed Rank test for n=12 Alpha Level 0.001 0.005 0.01 0.025 0.05 0.1 0.2 Critical Value 75 70 68 64 60 56 50 What is the p-value for this test? p-value < 0.001arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Discrete Mathematics and Its Applications ( 8th I...MathISBN:9781259676512Author:Kenneth H RosenPublisher:McGraw-Hill Education
Mathematics for Elementary Teachers with Activiti...MathISBN:9780134392790Author:Beckmann, SybillaPublisher:PEARSON
Thinking Mathematically (7th Edition)MathISBN:9780134683713Author:Robert F. BlitzerPublisher:PEARSON
Discrete Mathematics With ApplicationsMathISBN:9781337694193Author:EPP, Susanna S.Publisher:Cengage Learning,
Pathways To Math Literacy (looseleaf)MathISBN:9781259985607Author:David Sobecki Professor, Brian A. MercerPublisher:McGraw-Hill Education
Discrete Mathematics and Its Applications ( 8th I...
Math
ISBN:9781259676512
Author:Kenneth H Rosen
Publisher:McGraw-Hill Education
Mathematics for Elementary Teachers with Activiti...
Math
ISBN:9780134392790
Author:Beckmann, Sybilla
Publisher:PEARSON
Thinking Mathematically (7th Edition)
Math
ISBN:9780134683713
Author:Robert F. Blitzer
Publisher:PEARSON
Discrete Mathematics With Applications
Math
ISBN:9781337694193
Author:EPP, Susanna S.
Publisher:Cengage Learning,
Pathways To Math Literacy (looseleaf)
Math
ISBN:9781259985607
Author:David Sobecki Professor, Brian A. Mercer
Publisher:McGraw-Hill Education
Use of ALGEBRA in REAL LIFE; Author: Fast and Easy Maths !;https://www.youtube.com/watch?v=9_PbWFpvkDc;License: Standard YouTube License, CC-BY
Compound Interest Formula Explained, Investment, Monthly & Continuously, Word Problems, Algebra; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=P182Abv3fOk;License: Standard YouTube License, CC-BY
Applications of Algebra (Digit, Age, Work, Clock, Mixture and Rate Problems); Author: EngineerProf PH;https://www.youtube.com/watch?v=Y8aJ_wYCS2g;License: Standard YouTube License, CC-BY