
Business Math (11th Edition)
11th Edition
ISBN: 9780134496436
Author: Cheryl Cleaves, Margie Hobbs, Jeffrey Noble
Publisher: PEARSON
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Chapter 18, Problem 2CP
To determine
To calculate: The overhead for each department based on sales, if the total overhead is
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Question 4 Find an equation of
(a) The plane through the point (2, 0, 1) and perpendicular to the line x =
y=2-t, z=3+4t.
3t,
(b) The plane through the point (3, −2, 8) and parallel to the plane z = x+y.
(c) The plane that contains the line x = 1+t, y = 2 − t, z = 4 - 3t and is
parallel to the plane 5x + 2y + z = 1.
(d) The plane that passes through the point (1,2,3) and contains the line
x = 3t, y = 1+t, and z = 2-t.
(e) The plane that contains the lines L₁: x = 1 + t, y = 1 − t, z = 2t and
L2 : x = 2 − s, y = s, z = 2.
Please find all values of x.
Sales personnel for Skillings Distributors submit weekly reports listing the customer contacts made during the week. A sample of 65 weekly reports showed a sample mean of 19.5 customer contacts per week. The sample standard deviation was 5.2. Provide 90% and 95% confidence intervals for the population mean number of weekly customer contacts for the sales personnel.
90% Confidence interval, to 2 decimals:
( , )
95% Confidence interval, to 2 decimals:
Chapter 18 Solutions
Business Math (11th Edition)
Ch. 18.1 - Prob. 1-1SCCh. 18.1 - Prob. 1-2SCCh. 18.1 - Prob. 1-3SCCh. 18.1 - Prob. 1-4SCCh. 18.1 - Prob. 2-1SCCh. 18.1 - Prob. 2-2SCCh. 18.1 - Prob. 2-3SCCh. 18.1 - Prob. 2-4SCCh. 18.1 - Prob. 3-1SCCh. 18.1 - Prob. 3-2SC
Ch. 18.1 - Prob. 3-3SCCh. 18.1 - Prob. 3-4SCCh. 18.1 - Prob. 4-1SCCh. 18.1 - Prob. 4-2SCCh. 18.1 - Prob. 4-3SCCh. 18.1 - Prob. 4-4SCCh. 18.1 - Prob. 5-1SCCh. 18.1 - Prob. 5-2SCCh. 18.1 - Prob. 5-3SCCh. 18.1 - Prob. 5-4SCCh. 18.1 - Prob. 6-1SCCh. 18.1 - Prob. 6-2SCCh. 18.1 - Prob. 6-3SCCh. 18.1 - Prob. 6-4SCCh. 18.1 - Prob. 6-5SCCh. 18.1 - Prob. 1SECh. 18.1 - Prob. 2SECh. 18.1 - Prob. 3SECh. 18.1 - Prob. 4SECh. 18.1 - Prob. 5SECh. 18.1 - Prob. 6SECh. 18.1 - Prob. 7SECh. 18.1 - Prob. 8SECh. 18.1 - Prob. 9SECh. 18.1 - Prob. 10SECh. 18.1 - Prob. 11SECh. 18.1 - Prob. 12SECh. 18.1 - Prob. 13SECh. 18.1 - Prob. 14SECh. 18.1 - Prob. 15SECh. 18.1 - Prob. 16SECh. 18.1 - Prob. 17SECh. 18.1 - Prob. 18SECh. 18.1 - Prob. 19SECh. 18.1 - Prob. 20SECh. 18.1 - Prob. 21SECh. 18.1 - Prob. 22SECh. 18.1 - Prob. 23SECh. 18.1 - Prob. 24SECh. 18.1 - Prob. 25SECh. 18.1 - Prob. 26SECh. 18.1 - Prob. 27SECh. 18.1 - Prob. 28SECh. 18.1 - Prob. 29SECh. 18.2 - Prob. 1-1SCCh. 18.2 - Prob. 1-2SCCh. 18.2 - Prob. 1-3SCCh. 18.2 - Prob. 1-4SCCh. 18.2 - Prob. 2-1SCCh. 18.2 - Prob. 2-2SCCh. 18.2 - Prob. 2-3SCCh. 18.2 - Prob. 2-4SCCh. 18.2 - Prob. 1SECh. 18.2 - Prob. 2SECh. 18.2 - Prob. 3SECh. 18.2 - Prob. 4SECh. 18.2 - Prob. 5SECh. 18.2 - Prob. 6SECh. 18.2 - Prob. 7SECh. 18.2 - Prob. 8SECh. 18.2 - Prob. 9SECh. 18.2 - Prob. 10SECh. 18 - Prob. 1ESCh. 18 - Prob. 2ESCh. 18 - Prob. 3ESCh. 18 - Prob. 4ESCh. 18 - Prob. 5ESCh. 18 - Prob. 6ESCh. 18 - Prob. 7ESCh. 18 - Prob. 8ESCh. 18 - Prob. 9ESCh. 18 - Prob. 10ESCh. 18 - Prob. 11ESCh. 18 - Prob. 12ESCh. 18 - Prob. 13ESCh. 18 - Prob. 14ESCh. 18 - Prob. 16ESCh. 18 - Prob. 17ESCh. 18 - Prob. 18ESCh. 18 - Prob. 19ESCh. 18 - Prob. 20ESCh. 18 - Prob. 21ESCh. 18 - Prob. 22ESCh. 18 - Prob. 23ESCh. 18 - Prob. 24ESCh. 18 - Prob. 25ESCh. 18 - Prob. 26ESCh. 18 - Prob. 27ESCh. 18 - Prob. 1PTCh. 18 - Prob. 2PTCh. 18 - Prob. 3PTCh. 18 - Prob. 4PTCh. 18 - Prob. 5PTCh. 18 - Prob. 6PTCh. 18 - Prob. 7PTCh. 18 - Prob. 8PTCh. 18 - Prob. 9PTCh. 18 - Prob. 10PTCh. 18 - Prob. 11PTCh. 18 - Prob. 12PTCh. 18 - Prob. 13PTCh. 18 - Prob. 14PTCh. 18 - Prob. 15PTCh. 18 - Prob. 16PTCh. 18 - Prob. 1CTCh. 18 - Prob. 2CTCh. 18 - Prob. 3CTCh. 18 - Prob. 4CTCh. 18 - Prob. 5CTCh. 18 - Prob. 6CTCh. 18 - Prob. 7CTCh. 18 - Prob. 8CTCh. 18 - Prob. 9CTCh. 18 - Prob. 1CPCh. 18 - Prob. 2CPCh. 18 - Prob. 1CS1Ch. 18 - Prob. 2CS1Ch. 18 - Prob. 3CS1Ch. 18 - Prob. 1CS2Ch. 18 - Prob. 2CS2
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- A simple random sample of 40 items resulted in a sample mean of 25. The population standard deviation is 5. a. What is the standard error of the mean (to 2 decimals)? b. At 95% confidence, what is the margin of error (to 2 decimals)?arrow_forwardmean trough level of the population to be 3.7 micrograms/mL. The researcher conducts a study among 93 newly diagnosed arthritis patients and finds the mean trough to be 4.1 micrograms/mL with a standard deviation of 2.4 micrograms/mL. The researcher wants to test at the 5% level of significance if the trough is different than previously reported or not. Z statistics will be used. Complete Step 5 of hypothesis testing: Conclusion. State whether or not you would reject the null hypothesis and why. Also interpret what this means (i.e. is the mean trough different from 3.7 or noarrow_forwardQ15arrow_forward
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