
To calculate: The cost of goods available for sale using the following table,
Date of purchase |
Unit purchased |
Cost per unit |
Beginning inventory |
182 |
$21 |
August 20 |
78 |
$27 |
September 12 |
39 |
$28 |
October 2 |
52 |
$21 |
Cost of goods available for sale |

Answer to Problem 1ES
Solution:
The total cost of goods available for sale is $8112.
Explanation of Solution
Given information:
The inventory table,
Date of purchase |
Unit purchased |
Cost per unit |
Beginning inventory |
182 |
$21 |
August 20 |
78 |
$27 |
September 12 |
39 |
$28 |
October 2 |
52 |
$21 |
Cost of goods available for sale |
Formula used:
Use the following formulae,
Calculation:
Consider the inventory table,
Date of purchase |
Unit purchased |
Cost per unit |
Beginning inventory |
182 |
$21 |
August 20 |
78 |
$27 |
September 12 |
39 |
$28 |
October 2 |
52 |
$21 |
Cost of goods available for sale |
Now, using the formula to find total cost of goods available for sale,
So, total cost of goods available for sale is $8112.
Want to see more full solutions like this?
Chapter 18 Solutions
Business Math (11th Edition)
- 6) Solve the triangle. 9 6 B A 4 A) A 127.2°, B = 32.1°, C= 20.7° B) A 127.2°, B = 20.7°, C= 32.1° C) A 32.1°, B = 20.7°, C = 127.2° D) A 32.1°, B = 127.2°, C = 20.7°arrow_forwardFind cot 0. A) 8√√55 55 3 8 B) ㄢ 55 3 √55 8 D) 3-√/55 55arrow_forwardEvaluate the following integral over the Region R. (Answer accurate to 2 decimal places). √ √(x + y) A R R = {(x, y) | 25 < x² + y² ≤ 36, x < 0} Hint: The integral and Region is defined in rectangular coordinates.arrow_forward
- Could you please answer this question using excel. For 1a) I got 84.75 and for part 1b) I got 85.33 and was wondering if you could check if my answers were correct. Thanksarrow_forwardFind the volume of the solid that lies under the paraboloid z = 81 - x² - y² and within the cylinder (x − 1)² + y² = 1. A plot of an example of a similar solid is shown below. (Answer accurate to 2 decimal places). Volume using Double Integral Paraboloid & Cylinder -3 Hint: The integral and region is defined in polar coordinates.arrow_forwardEvaluate the following integral over the Region R. (Answer accurate to 2 decimal places). √4(1–2² 4(1 - x² - y²) dA R 3 R = {(r,0) | 0 ≤ r≤ 2,0π ≤0≤¼˜}. Hint: The integral is defined in rectangular coordinates. The Region is defined in polar coordinates.arrow_forward
- Evaluate the following integral over the Region R. (Answer accurate to 2 decimal places). R - 1 · {(r,0) | 1 ≤ r≤ 5,½π≤ 0<1π}. Hint: Be sure to convert to Polar coordinates. Use the correct differential for Polar Coordinates.arrow_forwardEvaluate the following integral over the Region R. (Answer accurate to 2 decimal places). √ √2(x+y) dA R R = {(x, y) | 4 < x² + y² < 25,0 < x} Hint: The integral and Region is defined in rectangular coordinates.arrow_forwardQ/Draw the graph k 3,4, and extract perfect ma ching from itarrow_forward
- π sin2x sin3x sin5x sin30x sinx - sin6x - sin10x - sin15x) 2 dxarrow_forwardf(x+T) = f(x) f(x) = sin² (x) + cos² (x) T=?arrow_forwardHW: The frame shown in the figure is pinned at A and C. Use moment distribution method, with and without modifications, to draw NFD, SFD, and BMD. B I I 40 kN/m A 3 m 4 marrow_forward
- Discrete Mathematics and Its Applications ( 8th I...MathISBN:9781259676512Author:Kenneth H RosenPublisher:McGraw-Hill EducationMathematics for Elementary Teachers with Activiti...MathISBN:9780134392790Author:Beckmann, SybillaPublisher:PEARSON
- Thinking Mathematically (7th Edition)MathISBN:9780134683713Author:Robert F. BlitzerPublisher:PEARSONDiscrete Mathematics With ApplicationsMathISBN:9781337694193Author:EPP, Susanna S.Publisher:Cengage Learning,Pathways To Math Literacy (looseleaf)MathISBN:9781259985607Author:David Sobecki Professor, Brian A. MercerPublisher:McGraw-Hill Education





