The number of possible arrangements before and after removal of the central barrier is to be determined and the number of arrangements after the removal of the barriercorresponding to the state in which both molecules are in the left side, right side, and opposite sides of the container, entropy for each state is to be calculated and a comment is to be made on the most probable state of the system after removal of the barrier. Concept introduction: The quantity that predicts the spontaneity of a process is called Gibbs free energy. The mathematical equation is as follows: Δ G = Δ H − T Δ S …… (1) Here, Δ G is the change in the Gibbs free energy, Δ H is the enthalpy change of the system, and Δ S is the entropy change of the system. Mathematically, entropy by Ludwig Boltzmann is given as follows: S =kln ( W ) …..(2) Here, k is Boltzmann Constant ( 1 .38×10 -23 J/K ) and W is thenumber of energetically equivalent different ways in which a molecule in a system is arranged. The number of possible arrangements is given by the equation as follows: W = X N …..(3) Here, X is the number of cells and N is the number of molecules.
The number of possible arrangements before and after removal of the central barrier is to be determined and the number of arrangements after the removal of the barriercorresponding to the state in which both molecules are in the left side, right side, and opposite sides of the container, entropy for each state is to be calculated and a comment is to be made on the most probable state of the system after removal of the barrier. Concept introduction: The quantity that predicts the spontaneity of a process is called Gibbs free energy. The mathematical equation is as follows: Δ G = Δ H − T Δ S …… (1) Here, Δ G is the change in the Gibbs free energy, Δ H is the enthalpy change of the system, and Δ S is the entropy change of the system. Mathematically, entropy by Ludwig Boltzmann is given as follows: S =kln ( W ) …..(2) Here, k is Boltzmann Constant ( 1 .38×10 -23 J/K ) and W is thenumber of energetically equivalent different ways in which a molecule in a system is arranged. The number of possible arrangements is given by the equation as follows: W = X N …..(3) Here, X is the number of cells and N is the number of molecules.
Solution Summary: The author explains how Gibbs free energy predicts the spontaneity of a process.
The number of possible arrangements before and after removal of the central barrier is to be determined and the number of arrangements after the removal of the barriercorresponding to the state in which both molecules are in the left side, right side, and opposite sides of the container, entropy for each state is to be calculated and a comment is to be made on the most probable state of the system after removal of the barrier.
Concept introduction:
The quantity that predicts the spontaneity of a process is called Gibbs free energy. The mathematical equation is as follows:
ΔG=ΔH−TΔS…… (1)
Here, ΔG is the change in the Gibbs free energy, ΔH is the enthalpy change of the system, and ΔS is the entropy change of the system.
Mathematically, entropy by Ludwig Boltzmann is given as follows:
S=kln(W)…..(2)
Here, k is Boltzmann Constant (1.38×10-23J/K) and W is thenumber of energetically equivalent different ways in which a molecule in a system is arranged.
The number of possible arrangements is given by the equation as follows:
W =XN…..(3)
Here, X is the number of cells and N is the number of molecules.
Predict the major organic product(s) of the following reactions. Indicate which of the following mechanisms is in operation: SN1, SN2, E1, or E2.
(c)
(4pts)
Mechanism:
heat
(E1)
CH3OH
+
1.5pts each
_E1 _ (1pt)
Br
CH3OH
(d)
(4pts)
Mechanism:
SN1
(1pt)
(e)
(3pts)
1111 I
H
10
Ill!!
H
LDA
THF (solvent)
Mechanism: E2
(1pt)
NC
(f)
Bri!!!!!
CH3
NaCN
(3pts)
acetone
Mechanism: SN2
(1pt)
(SN1)
-OCH3
OCH3
1.5pts each
2pts for either product
1pt if incorrect
stereochemistry
H
Br
(g)
“,、
(3pts)
H
CH3OH
+21
Mechanism:
SN2
(1pt)
H
CH3
2pts
1pt if incorrect
stereochemistry
H
2pts
1pt if incorrect
stereochemistry
A mixture of butyl acrylate and 4'-chloropropiophenone has been taken for proton NMR analysis. Based on this proton NMR, determine the relative percentage of each compound in the mixture
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
The Laws of Thermodynamics, Entropy, and Gibbs Free Energy; Author: Professor Dave Explains;https://www.youtube.com/watch?v=8N1BxHgsoOw;License: Standard YouTube License, CC-BY