(a)
Interpretation:
The given amine needs to be labeled as 10, 20 or 30.
Concept introduction:
Answer to Problem 74P
A tertiary (3o) amine.
Explanation of Solution
Amines are derivatives which are derived from ammonia, wherein one or more hydrogen atoms have been replaced by a substituent such as an alkyl or aryl group. They can be called as alkylamines and arylamines.
Whether an amine is primary (1o), secondary (2o) or tertiary (3o) depends on the number of hydrogen atoms replaced by an alkyl or aryl group in ammonia. The amine is a primary amine if one hydrogen atom is replaced, it is a secondary amine if 2 hydrogen atoms are replaced and if three hydrogen atoms are replaced it is known as a tertiary amine.
The given compound is as follows:
Here, only one hydrogen atom is replaced and therefore this amine called as a primary (1o) amine.
(b)
Interpretation:
The molecular shape around each atom of phentermine needs to be determined.
Concept introduction:
Molecular geometry is named as molecular shape and it is the three-dimensional arrangement of atoms within a molecule of the environment. Atoms arrange in space with an exact shape to minimize the repulsion. This can be determined using VSEPR theory.
Answer to Problem 74P
Carbons of benzene molecule;trigonal planar.
Carbon of −CH2 / -C(CH3)2NH2 CH2-/-CH3;tetrahedral.
Nitrogen of NH2;trigonal pyramidal.
Explanation of Solution
VSEPR or Valence Shell Electron Pair Repulsion theory is a model used to determine the geometry of molecules considering minimum electrostatic repulsion between the valence electrons of central atom in the molecule.
Carbons of benzene molecule;
Number of bonds= 3
Number of lone pairs = 0
Therefore, the shape is trigonal planar.
Carbon of −CH2/ -C(CH3)2NH2CH2-/-CH3;
Number of bonds= 4
Number of lone pairs = 0
Therefore, the shape is tetrahedral.
Nitrogen of NH2;
Number of bonds= 3
Number of lone pairs = 1
Therefore, the shape is trigonal pyramidal.
(c)
Interpretation:
The constitutional isomer containing a primary amine needs to be determined.
Concept introduction:
Constitutional isomers are called as compounds that have the unique molecular formula and different structural connectivity. To determine whether two molecules are constitutional isomer, the number of each atom needs to be counted in both molecules and see how the atoms are arranged.
Answer to Problem 74P
Explanation of Solution
Whether an amine is primary (1o), secondary (2o) or tertiary (3o) depends on the number of hydrogen atoms replaced by an alkyl or aryl group in ammonia. The amine is a primary amine if one hydrogen atom is replaced, it is a secondary amine if 2 hydrogen atoms are replaced and if three hydrogen atoms are replaced it is known as a tertiary amine.
Here all one hydrogen atom is replaced and therefore this amine called a primary amine (1o).
(d)
Interpretation:
The constitutional isomer that contains a secondary amine needs to be determined.
Concept introduction:
Constitutional isomers are called as compounds that have the unique molecular formula and different structural connectivity. To determine whether two molecules are constitutional isomer, the number of each atom needs to be counted in both molecules and see how the atoms are arranged.
Answer to Problem 74P
Explanation of Solution
Whether an amine is primary (1o), secondary (2o) or tertiary (3o) depends on the number of hydrogen atoms replaced by an alkyl or aryl group in ammonia. The amine is a primary amine if one hydrogen atom is replaced, it is a secondary amine if 2 hydrogen atoms are replaced and if three hydrogen atoms are replaced it is known as a tertiary amine.
Here all 3 hydrogen atoms are replaced and therefore this amine called as a secondary amine (2o).
(e)
Interpretation:
The structure of phentermine hydrobromide molecule needs to be drawn.
Concept introduction:
Phentermine hydrobromide can stimulate the central nervous system and increases the blood pressure and heart rate which decreases the appetite. It is taken along with diet and exercise in order to reduce obesity.
Answer to Problem 74P
Explanation of Solution
Phentermine hydrobromide can stimulate the central nervous system and increases the blood pressure and heart rate which decreases the appetite. It is taken along with the diet and exercise in order to reduce the obesity.
Its molecular formula is C17H22BrN. It has the following structure.
(f)
Interpretation:
The products formed if phentermine is treated with benzoic acid needs to be determined.
Concept introduction:
Amines are derivatives which are derived from ammonia, wherein one or more hydrogen atoms have been replaced by a substituent such as an alkyl or aryl group. They can be called as alkylamines and arylamines.
Answer to Problem 74P
Explanation of Solution
Amines are derivatives which are derived from ammonia, wherein one or more hydrogen atoms have been replaced by a substituent such as an alkyl or aryl group. They can be called as alkylamines and arylamines.
Whether an amine is primary (1o), secondary (2o) or tertiary (3o) depends on the number of hydrogen atoms replaced by an alkyl or aryl group in ammonia. The amine is a primary amine if one hydrogen atom is replaced, it is a secondary amine if 2 hydrogen atoms are replaced and if three hydrogen atoms are replaced it is known as a tertiary amine.
Benzphetamine is a tertiary ammine. It has basic properties and it accepts protons from acids. Acetic acid is donated a proton to this amine and formed below the salt.
Want to see more full solutions like this?
Chapter 18 Solutions
Connect One Semester Access Card for General, Organic, & Biological Chemistry
- Influence of salt concentrations on electrostatic interactions 2 Answer is 2.17A why not sure step by step please What is the Debye length in a concentrated salt solution with an ionic strength of 2.00 mol/l? Assume room temperature, i.e. T= 298 K, and provide your answer as a numerical expression with 3 significant figures in Å (1 Å = 10-10 m).arrow_forwardThe name of the following molecule is: Νarrow_forwardThe table shows the tensile stress-strain values obtained for various hypothetical metals. Based on this, indicate which is the most brittle and which is the most tough (or most resistant). Breaking strength Elastic modulus Material Yield strength Tensile strength Breaking strain A (MPa) 415 (MPa) (MPa) (GPa) 550 0.15 500 310 B 700 850 0.15 720 300 C Non-effluence fracture 650 350arrow_forward
- Please correct answer and don't used hand raitingarrow_forwardThe table shows the tensile stress-strain values obtained for various hypothetical metals. Based on this, indicate which material will be the most ductile and which the most brittle. Material Yield strength Tensile strength Breaking strain Breaking strength Elastic modulus (MPa) (MPa) (MPa) (GPa) A 310 340 0.23 265 210 B 100 120 0.40 105 150 с 415 550 0.15 500 310 D 700 850 0.14 720 210 E - Non-effluence fracture 650 350arrow_forwardPlease correct answer and don't used hand raitingarrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage LearningChemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning