Equation for the decay of 95 241 Am by alpha particle production is to be stated. Final stable nucleus produced by the decay of 95 241 Am after successive alpha beta particle production is to be stated. The 11 intermediate nuclides produced are to be identified. Concept introduction: Nuclei of radioactive element decompose in various ways. There are two major categories. One involves a change in mass number of the decaying nucleus while others do not. Types of radioactive processes include α particle production, β particle production, γ ray production, electron capture and many others. Electron capture decay involves the capturing of one of the inner orbitals electrons by the nucleus. Beta particle production decay involves the production of beta particle ( − 1 0 e ) that is assigned mass number zero. A helium nucleus 2 4 He is produced in the alpha decay process. To determine: The equation for the decay of 95 241 Am by alpha particle production; final stable nuclide produced in the stated decay series and the 11 intermediate nuclides formed.

Question

please help

Answer 1

Question

Chapter 18, Problem 19E

Interpretation Introduction

Interpretation: Equation for the decay of 95241Am by alpha particle production is to be stated. Final stable nucleus produced by the decay of 95241Am after successive alpha beta particle production is to be stated. The 11 intermediate nuclides produced are to be identified.

Concept introduction: Nuclei of radioactive element decompose in various ways. There are two major categories. One involves a change in mass number of the decaying nucleus while others do not. Types of radioactive processes include α particle production, β particle production, γ ray production, electron capture and many others. Electron capture decay involves the capturing of one of the inner orbitals electrons by the nucleus.

Beta particle production decay involves the production of beta particle (−10e) that is assigned mass number zero.

A helium nucleus 24He is produced in the alpha decay process.

To determine: The equation for the decay of 95241Am by alpha particle production; final stable nuclide produced in the stated decay series and the 11 intermediate nuclides formed.

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Students have asked these similar questions

please help

Experiment 1 Data Table 1: Conservation of Mass - Initial Mass Data Table 1 Data Table 2 Data Table 3 Data Table 4 Panel 1 Photo 1 Data Table 5 Reaction Mass of test tube and 5.0% HC₂H₂O2 (g) # (A) (B) Mass of NaHCO, (g) Mass of balloon and NaHCO, (g) (C) 0.10 1 0829 14.38g 0.20 2 0.929 14.29g 0.35 1.00g 3 14.25g 0.50 1.14g 14.29 Experiment 1 Data Table 2: Moles of HC2H3O2 Reaction Volume of Mass of Moles of HC₂H₂O₂ 5.0% Vinegar (g) (ML) 5.0 0.25 0042 mol 2 5.0 0.25 0042 mol 3 5.0 0.25 0042 mol 5.0 0.25 0042 mol Experiment 1 Data Table 3: Moles of NaHCO3 Reaction Mass of NaHCO (g) 10g 20g 35g 50g Experiment 1 Data Table 4: Theoretical Yield of CO₂ Reaction # 1 2 3 Experiment 1 Total mass before reaction (g) (D=A+C) 15.29 15.21g 15.25g 15.349 Exercise 1 Data Table 1 Data Table 2 Data Table 3 Data Table 4 Panel 1 Photo 1 Data Table 5 Exercise 1- Data Table 1 Data Table 2 DataTable 3 Data Table 4 Panel 1 Photo 1 Data Table 5 Exercise 1- Moles of NaHCO 0012 mol 0025 mol 0044 mol 0062 mol…

The chemical reaction you investigated is a two-step reaction. What type of reaction occurs in each step? How did you determine your answer?