Concept explainers
(a)
Interpretation: The classification of the given
Concept introduction: The simplest hydrolyzed form that is obtained from the carbohydrates is known as monosaccharide. Monosaccharide is categorized into two types. The first type of monosaccharide is aldoses and the second type of monosaccharide is ketoses. Aldoses sugar possesses
Monosaccharides are also classified on the basis of the number of carbon atoms present in it. For example, the sugar that contains five carbon atoms is known as pentoses sugar and the sugar that contains six carbon atoms is known as hexoses sugar.
(b)
Interpretation: The classification of the given
Concept introduction: The simplest hydrolyzed form that is obtained from the carbohydrates is known as monosaccharide. Monosaccharide is categorized into two types. The first type of monosaccharide is aldoses and the second type of monosaccharide is ketoses. Aldoses sugar possesses aldehyde as a functional group and the ketoses sugar possesses ketone as a functional group.
Monosaccharides are also classified on the basis of the number of carbon atoms present in it. For example, the sugar that contains five carbon atoms is known as pentoses sugar and the sugar that contains six carbon atoms is known as hexoses sugar.
(c)
Interpretation: The classification of the given
Concept introduction: The simplest hydrolyzed form that is obtained from the carbohydrates is known as monosaccharide. Monosaccharide is categorized into two types. The first type of monosaccharide is aldoses and the second type of monosaccharide is ketoses. Aldoses sugar possesses aldehyde as a functional group and the ketoses sugar possesses ketone as a functional group.
Monosaccharides are also classified on the basis of the number of carbon atoms present in it. For example, the sugar that contains five carbon atoms is known as pentoses sugar and the sugar that contains six carbon atoms is known as hexoses sugar.
(d)
Interpretation: The classification of the given
Concept introduction: The simplest hydrolyzed form that is obtained from the carbohydrates is known as monosaccharide. Monosaccharide is categorized into two types. The first type of monosaccharide is aldoses and the second type of monosaccharide is ketoses. Aldoses sugar possesses aldehyde as a functional group and the ketoses sugar possesses ketone as a functional group.
Monosaccharides are also classified on the basis of the number of carbon atoms present in it. For example, the sugar that contains five carbon atoms is known as pentoses sugar and the sugar that contains six carbon atoms is known as hexoses sugar.
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Chapter 18 Solutions
General, Organic, and Biological Chemistry Seventh Edition
- Pt + H₂ Draw the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Templ 9 2 0 © 120arrow_forwardComplete boxes in the flow chart. Draw the structure of the organic compound foundin each layer after adding 3M NaOH and extraction. Make sure to include any charges. Provide explanation on answers.arrow_forward== Vid4Q2 Unanswered ☑ Provide IUPAC name of product in the reaction below A 3,4-dimethylcyclohexene B 1,2-dimethylcyclohexane C 1,2-dimethylcyclohexene D 3,4-dimethylcyclohexane H₂ Pdarrow_forward
- 5. Use the MS data to answer the questions on the next page. 14.0 1.4 15.0 8.1 100- MS-IW-5644 26.0 2.8 27.0 6.7 28.0 1.8 29.0 80 4.4 38.0 1.0 39.0 1.5 41.0 1.2 42.0 11.2 43.0 100.0 44.0 4.3 79.0 1.9 80.0 2.6 Relative Intensity 40 81.0 1.9 82.0 2.5 93.0 8.7 20- 95.0 8.2 121.0 2.0 123.0 2.0 136.0 11.8 0 138.0 11.5 20 40 8. 60 a. Br - 0 80 100 120 140 160 180 200 220 m/z Identify the m/z of the base peak and molecular ion. 2 b. Draw structures for each of the following fragments (include electrons and charges): 43.0, 93.0, 95.0, 136.0, and 138.0 m/z. C. Draw a reasonable a-fragmentation mechanism for the fragmentation of the molecular ion to fragment 43.0 m/z. Be sure to include all electrons and formal charges. 6. Using the values provided in Appendix E of your lab manual, calculate the monoisotopic mass for the pyridinium ion (CsH6N) and show your work.arrow_forwardNonearrow_forwardStereochemistry: Three possible answers- diastereomers, enantiomers OH CH₂OH I -c=0 21108 1101 41745 HOR CH₂OH IL Но CH₂OH TIL a. Compounds I and III have this relationship with each other: enantiomers b. Compounds II and IV have this relationship with each other: c. Compounds I and II have this relationship with each other: d. *Draw one structure that is a stereoisomer of II, but neither a diastereomer nor an enantiomer. (more than one correct answer)arrow_forward
- Don't used Ai solutionarrow_forwardDon't used Ai solutionarrow_forwardIn mass spectrometry, alpha cleavages are common in molecules with heteroatoms. Draw the two daughter ions that would be observed in the mass spectrum resulting from an alpha cleavage of this molecule. + NH2 Q Draw Fragment with m/z of 72arrow_forward
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